4 - 2 Light and Color LIGHT AND COLOR Name(s) ____________________________________ Do you know why things are the color that they are? Have you ever wondered why the ocean is blue? Do you know why grass is green? Have you ever wondered what makes the sun and the sky turn red as the sun goes down? Most people think that objects look a certain color simply because they are that color. For example, we say, "Roses are red and violets are blue," not "Roses just look red, and violets just look blue." We think of objects as having color, not that they just appear to have color. We want to believe that a red rose would still be red even if we were to place it somewhere that was so dark that we could not even see the rose. It might be too dark to see, but the rose would certainly still be red, wouldn't it? The problem with this common sense "model" for colors is that it cannot be used to explain a variety of color phenomena we experience everyday. It cannot be used to explain why the sky is blue during the day, red at dusk, and black at night. It does not explain why the "blue" shirt we bought at the store looks purple when we get it home. It does not account for how television or computer screens can display objects that appear to be yellow even though television and computer screens cannot make the color yellow. And it certainly cannot begin to explain the formation of a rainbow. The activities in this section will introduce a scientific model for color that is an extension of the photon model for light. At first, it may seem awkward to try and explain color by referring to photons, but over time the photon model should become an indispensable way for you to think about color. The Photon Model The diagram on the next page is meant to portray the photon model of light. The person shown in the diagram is able to see the box on the right because photons are coming out of the lamp, bouncing of the box, and then going into the person's eyes. This picture represents a somewhat simplified version of the photon model, because the photons bouncing off the box should really be shown scattering in every direction, not just towards the person. However, it would be very confusing to show all of the photons, so just the ones that are bouncing towards the person are shown. Notice that more photons are shown hitting the box than are shown bouncing off. This is because some photons are absorbed when they hit the box. A perfectly black box would absorb all the photons that hit it. A perfectly white box would reflect all the photons. UNIT 4 ENERGY AND INTERACTIONS IV-21 © CALVIN COLLEGE 4 - 2 Light and Color A Diagram of the Photon Model Note: Some photons are absorbed when they hit the box. It is important to remember that, according to the photon model, the man in the picture does not actually "see" the box. Rather, what he sees are the photons coming into his eyes that have bounced of the box. Therefore, the man's brain determines what is true about the way the box looks, including the color of the box, based upon the photons that are going into his eyes. The photons themselves must have a way of telling the man about the color of the box. Photons Come in Many Colors One way that photons could tell us about the color of an object would be if the photons themselves came in different colors. As a matter of fact, we can demonstrate that photons do indeed come in many colors by looking at the world through special glasses that have diffraction grating lenses. Activity #1 Separating Colors with Diffraction Glasses The room lights should be dim or off for the following activities. Obtain a pair of diffraction grating glasses for each member of your group, plus one laser pointer to be shared. There should also be a few regular light sources positioned around the room that you can see from your seat. Be careful never to look at a bright light source (especially the sun or a laser beam!) or try to drive a car while you are wearing the diffraction grating glasses. UNIT 4 ENERGY AND INTERACTIONS IV-22 © CALVIN COLLEGE 4 - 2 Light and Color 1. Without using your diffraction grating glasses, look at one of the regular light sources in the room. Note that the light coming from the bulb appears to be white. 2. Now, put on your diffraction grating glasses, and notice that the main beam of light still looks white, but there are also very colorful light patterns all around the main beam. Somehow, diffraction grating glasses are able to produce all the colors of the rainbow from a source of "white" light. 3. Take off your diffraction glasses, and this time shine the laser at a piece of paper in front of you. Remember; never look directly into the laser beam or directly at its reflection from a mirror! It is only safe to look at the light from the laser after it has reflected off an object such as the wall or a piece of paper. What color is the laser light? What colors do you think you will see if you were to look at the laser light through your diffraction grating glasses? (Remember, only look at the laser light after it has reflected from the paper.) Will you see the same colorful patterns of light as you saw when you looked at the regular light source, or will there be a difference? Write your prediction below. 4. Shine the laser at the the paper, and look at its reflection through your diffraction grating glasses. What do you see? Was you prediction correct? Describe below the colors you can see through your glasses. UNIT 4 ENERGY AND INTERACTIONS IV-23 © CALVIN COLLEGE 4 - 2 Light and Color Apparently diffraction grating glasses are able to separate white light into all the colors of the rainbow, but they do not turn single colors of the rainbow (in this case red) into other colors. How do diffraction glasses manage to do this? The explanation depends upon us imagining that photons come in different colors. A Photon Model for Color All the colors that we see around us can be explained if we imagine that photons come in different colors. For simplicity, we will imagine that photons can only be one of the seven colors of the rainbow: red, orange, yellow, green, cyan, blue, and violet. The colors that we perceive depend upon the colors of the photons that are going into our eyes. When we see the red light of a laser, then only red photons are going into our eyes. If we see the reflection of a green laser light, then that would mean that only green photons are entering our eyes. If two or more differently colored photons are entering your eye at the same time, then your brain interprets the color you see to be a kind of average of those photon colors. For example, if equal numbers of red and yellow photons go into your eye, then your brain interprets the color to be orange, even though orange photons are not actually going into your eye. A mixture of red and blue photons will appear to be a purple color. When photons of all the colors of the rainbow go into your eye at the same time, your brain interprets that color to be white! The diagram below depicts a man looking at a lamp that produces normal "white" light. The photons traveling towards the man have been labeled as R, O, Y , G, C , B, and V to designate photons that are red, orange, yellow, green, cyan, blue, and violet. (A normal light bulb would produce photons of all these colors.) Even though many differently colored photons are entering the man's eyes, his brain can only interpret a single color at a time. Since a combination of photons of all colors of the rainbow average out to be white, the man thinks that the light is white. Keep in mind that there are no white photons. We only think we see white when we see all the colors at once. R O Y B R C V UNIT 4 ENERGY AND INTERACTIONS G V O IV-24 Y B G C R O B © CALVIN COLLEGE 4 - 2 Light and Color The diagram below shows a man looking at a beam of light from a lamp after it reflects off a white piece of paper. Since white paper is good at reflecting photons, all the different colors of photons are still reaching his eyes, and the spot of light on the paper looks white to him. R Y O V B R C Y V G G B O R C B O G C V B Y R G O C V B R Y The man below is looking at a spot on a white piece of paper from a red laser beam. Since the laser only produces red photons, and since the "white" paper reflects all photons well (including red ones), the man sees a red spot on the paper. LASER R R R R R R R R R R R R R R R R R R UNIT 4 ENERGY AND INTERACTIONS IV-25 © CALVIN COLLEGE 4 - 2 Light and Color Your diffraction grating glasses have the special ability to separate photons according to their color. The diagram below shows what happens when "white" light passes through a diffraction grating. (In order to keep the diagram from being too cluttered, only blue, green and red photons have been shown.) Notice that some of the photons go straight through the diffraction grating glasses. The rest bend off to the side, with the color of the photon determining the amount that the photon changes direction. Once the photons have changed direction according to their color, we can see individual beams of differently colored photons. R R R G R G R G G B G B R R G B B R B B B G R B B G R B G R R G G B B R R G G B Diffraction Grating Glasses The diagram below shows red laser light going through diffraction grating glasses. Since the laser only gives off red photons, only red light can be seen on the other side of the diffraction grating glasses. R R R R R R R LASER R R R R R R R R R R R R R R R Diffraction Grating Glasses UNIT 4 ENERGY AND INTERACTIONS IV-26 © CALVIN COLLEGE R R 4 - 2 Light and Color Our eyes alone cannot tell us what colors of photons we are seeing when the photons are all mixed together, because our brains interpret the mix of colors as being a single color. However, the diffraction grating glasses can tell us what colors are present, because they separate out the photons according to color so that we can see them. Therefore, diffraction grating glasses are useful tools in discovering what colors of photons are present in light. Activity #2 Seeing True Colors with Diffraction Glasses It is best if the room lights are very dim for these activities. If you cannot dim the lights in this room, then try moving to another, darker location to do this activity. Obtain three differently colored LED penlights (red, blue and green). Have your diffraction grating glasses ready, but do not put them on until you are instructed to do so. Warning: Do not point the lights directly towards your eyes. They are quite bright. View the lights from the side or from slightly behind. A. Red Penlight Observation: What color does this light appear to be when you are not wearing your diffraction grating glasses? Hypothesis: What color photons do you think the penlight is giving off? Explain why you think so. Testing the Hypothesis: Use your diffraction grating glasses to determine what color photons actually are being given off by the light. Compare your answer to your hypothesis, and explain any differences between them. (Ask your instructor for help if you are unsure of your results.) UNIT 4 ENERGY AND INTERACTIONS IV-27 © CALVIN COLLEGE 4 - 2 Light and Color B. Blue Penlight Observation: What color does this light appear to be when you are not wearing your diffraction grating glasses? Hypothesis: What color photons do you think the penlight is giving off? Explain why you think so. Testing the Hypothesis: Use your diffraction grating glasses to determine what color photons actually are being given off by the light. Compare your answer to your hypothesis, and explain any differences between them. C. Green Penlight Observation: What color does this light appear to be when you are not wearing your diffraction grating glasses? Hypothesis: What color photons do you think the penlight is giving off? Explain why you think so. Testing the Hypothesis: Use your diffraction grating glasses to determine what color photons actually are being given off by the light. Compare your answer to your hypothesis, and explain any differences between them. UNIT 4 ENERGY AND INTERACTIONS IV-28 © CALVIN COLLEGE 4 - 2 Light and Color Activity #3 Testing Color Filters Obtain a set of plastic color filters and three differently colored LED pen lights (red, blue and green) for your group. A filter is defined to be an object that will let some materials or objects through, but not others. For example, a coffee filter allows coffee and water to pass through, but not coffee grounds. A water filter allows water through, but not dirt. Look through each of your filters (one at a time) at a white light source. Why do you think they call these filters? For example, what does a red color filter do? The diagram below shows white light from a lamp striking a red filter. Complete the diagram by showing the photons that would emerge on the right side of the filter. Have your instructor or the class assistant check your work before you move on. R O Y B C V G Red Filter UNIT 4 ENERGY AND INTERACTIONS IV-29 © CALVIN COLLEGE 4 - 2 Light and Color The partial diagrams below show light sources shining at filters. Complete the diagrams by showing the photons moving towards the filters from the left, and then also indicate if any of the photons would get through. In every case assume that the light sources and the filters are perfect. Green light Red filter White light Green filter Blue light Blue filter Green light Blue filter UNIT 4 ENERGY AND INTERACTIONS IV-30 © CALVIN COLLEGE 4 - 2 Light and Color Activity #4 Are Color Filters Perfect? A perfect red filter would only let red photons through. The photons of other colors would get absorbed, or else they would reflect off. A perfect green filter would only let green photons through, and it would stop all other photons from getting through. Use your diffraction grating glasses and find a way to test and see how good your red, yellow, green, and blue filters operate. Do they just allow one color of photon through, or do several different colors get through? Describe below how you did your tests. For each filter, indicate which colors of photons got through by circling those colors. If only a few photons of a certain color get through, underline that color. Describe how you did your tests: Red Filter Which photons can get through? Red orange yellow green cyan blue violet cyan blue violet cyan blue violet cyan blue violet Yellow Filter Which photons can get through? Red orange yellow green Green Filter Which photons can get through? Red orange yellow green Blue Filter Which photons can get through? Red orange yellow UNIT 4 ENERGY AND INTERACTIONS green IV-31 © CALVIN COLLEGE 4 - 2 Light and Color Activity #5 Testing Your Conclusions In Activity # 2 (pp. 27-28) you discovered that the red, green and blue penlights did not give off just red, green and blue photons. Other colors were given off as well. In Activity #4 (p. 31) you saw that color filters are never perfect either. They often let through colors that you would not expect. Experiment by looking at the pen lights through the color filters and see that indeed light often gets through the filters even though you would not expect it to do so if the lights and the filters were perfect. There is one color filter that will almost completely block the light from one of the penlights. Find this combination of light and filter, and write down what it is. Light color _____________________ filter color _________________ Is this result consistent with what you found in Activities # 2 and # 4? Explain why you think so. UNIT 4 ENERGY AND INTERACTIONS IV-32 © CALVIN COLLEGE 4 - 2 Light and Color The Color of Objects Activity #6 The Dancing Bears The room must be nearly completely dark for these activities. It is best done where the lights can be turned off and there are no windows to the outside. Obtain three differently colored LED pen lights (red, blue and green), and six small plastic bears, each one a different color of the rainbow. Line up the bears in order such that their color sequence matches that of a rainbow. With all the lights off, illuminate the bears using the penlights. Try this with individual penlights on, and with combinations of the lights on. 1. Which bears look darkest when the red light is on alone? Why do you think that is? 2. Which bears look darkest when the blue light is on alone? Why do you think that is? 3. What combination of lights must be on in order to make all the bears at the same time look the most "natural"? 4. Why do you suppose the orange bear never seems to look its natural color? UNIT 4 ENERGY AND INTERACTIONS IV-33 © CALVIN COLLEGE 4 - 2 Light and Color Discussion The Dancing Bear activity clearly demonstrates that the color of an object depends upon the color of the light shining upon the object. This ought not to be too surprising, because the photons themselves must tell us about the color of an object. For example, if an object normally looks red, then it must be reflecting red photons into your eyes. But, if there are no red photons coming from the light source, then the object cannot possibly look red, because it cannot reflect any red photons to you. The diagram below depicts what occurs when a red box is illuminated by a white light source. Only the red photons are reflected from the box and into the man's eyes. Of course, this diagram is idealized, because no surface would just reflect red photons. A few other colors would get reflected occasionally as well. Most of the reflected photons, however, would be red if the box did indeed look red. R O Y B V C V Y R G B O G R C O R R R R R The diagram below shows a perfectly blue light source shining at the "red" box. Since blue photons will not reflect from a "red" box, the box would appear to be very dark to the man. Blue light B B B B UNIT 4 ENERGY AND INTERACTIONS IV-34 B B B B © CALVIN COLLEGE 4 - 2 Light and Color Each diagram below depicts a light source shining on a box. The color of the light source, plus the color that the box would look with a white light source, have been indicated. For each diagram draw the photons that would be present, and state what color the box would appear to be with the given light source. Red light Green White light Reddish/ Orange Blue/Green Green UNIT 4 ENERGY AND INTERACTIONS IV-35 © CALVIN COLLEGE 4 - 2 Light and Color Homework Questions 1. As more and more lights of many different colors are projected onto a white piece of paper, the bright spot illuminated on the paper looks more and more white. On the other hand, as more and more paint of different colors gets mixed together and brushed onto a piece of white paper, the painted spot appears more and more black. Explain why you obtain these two different results for mixing colors in these two different ways. 2. Given what you know about light absorption and reflection, explain why black-asphalted roads heat up more in the summer than white gravel roads. 3. What color would a red rose appear to be if it were placed in blue light? 4. Write a report to explain why the sky is blue during the day, black at night, and often orange or red at sunrise and sunset. 5. a. People living in hot sunny climates often wear white clothing. Use your model of light to explain why this is so. b. People who live in the very hottest and sunniest climates of all actually wear black clothing. In this case their outer clothing becomes much hotter than their skin temperature, causing breezes to blow through their clothing. Explain how this happens. (Hint: Think back to Unit 1) 6. What color would a white piece of paper appear under the following lights: WHITE RED GREEN BLUE YELLOW 7. Both light and sound can be represented with a wave model. Therefore, it is not surprising that sound and light have many things in common. List as many common characteristics between light and sound as you can. (One example would be that both light and sound can reflect off objects.) Also list a few characteristics that definitely differ between the two. 8. Given that color pigments are not perfect in their ability to absorb light, explain why you would expect a mixture of red paint and yellow paint to make orange paint. 9. Get a sheet of white paper, a red report cover (which will act as a red filter), and a box of markers. Use your markers to draw a picture that contains a hidden picture or message that is revealed when the picture is viewed through the red report cover. (Your instructor can show you an example of this.) Explain how this works. UNIT 4 ENERGY AND INTERACTIONS IV-36 © CALVIN COLLEGE Models of Light The Photon Model of Light Content Overview A good scientific model for light must be useful for explaining most of the phenomena that we experience with light and with seeing. Scientists have actually developed two different models for light that have proven to be very useful in this regard; the Photon Model and the Wave Model. Of these two, the Photon Model is easier to understand and to apply. The Photon Model for light states that light is a stream of photons; small bundles of energy that have no mass and that travel in straight lines at high rates of speed. Photons move at a rate of about 186,000 miles in a second! We have pictured these bundles of energy as tiny balls flying through the air. When photons strike an object they will either reflect (bounce off), get absorbed, or get transmitted (pass through). Glass is an example of a material that transmits photons well. That is to say, light passes through glass easily. If an object absorbs light, then the energy from the photons is given to the object, and the object generally heats up. Dark objects tend to absorb photons better than light objects, and so dark objects heat up faster in light than do light objects. We "see" an object only when photons reflect off that object and go into our eye. Photons come in different "colors". The amount of energy a photon has determines its color. Blue photons have slightly more energy than cyan photons, which have slightly more energy than green photons, which have slightly more energy than yellow photons, etc. Red photons are the least energetic photons that we can see. The colors that we perceive with our eyes are simply a combination of the colors of the photons that are entering our eyes. When photons of all the visible colors of the rainbow enter our eyes at once, we perceive the color to be white. Most of the colors seen by the human eye can be replicated by combining the right proportions of red, green, and blue photons. For example, combinations of just red, green, and blue lights produce the colors we see on color TVs and computer monitors. Many photons exist with energies that are higher than violet photons or with energies that are lower than red photons. Human eyes cannot detect these photons, so this is often called nonvisible light. X-rays, ultraviolet rays, infrared light, microwaves, and radio waves are all examples of photons that are invisible to the human eye. The visible colors of the rainbow make up a very small portion of all the photons that actually exist. UNIT 4 ENERGY AND INTERACTIONS II-37 © CALVIN COLLEGE Models of Light The Wave Model of Light Content Overview In addition to the Photon Model of Light, scientists long ago also developed a Wave Model of Light. Perhaps it is more common to hear people speaking of light waves than it is to hear them refer to photons, but it is also probably true that the wave model for light is harder to understand than the photon model. Nevertheless, there are certain phenomena associated with light that are more naturally or more easily described using a wave model than the photon model, and so both models are used extensively in science. WAVES In order to understand the Wave Model of Light, you must first understand something about waves in general. You can start by thinking about water waves. There are large waves in oceans and other bodies of water, and smaller waves in swimming pools, bathtubs, and sinks. Perhaps most people picture large ocean waves breaking near the shore when they are asked to think about waves. Unfortunately, these breaking waves, highly coveted by surfers, represent somewhat of a special case when it comes to waves. For most of this discussion, think about the waves further out from shore that can travel more or less undisturbed through the water. Nonetheless, one thing that breaking waves at the shore show well is that all waves carry energy! What is a wave? It is a traveling "disturbance" that carries energy from one place to another, but with no overall movement of matter. You can convince yourself that water waves carry energy without actually carrying away any water if you position yourself in a boat in the middle of a lake and begin to tap the water with your hand. You will clearly see a succession of waves moving away from the boat, and these waves will jostle any objects they encounter as they travel along, but you will not find that the level of water in the part of the lake you are floating in is decreasing. The waves you produced carried away energy from you, but they did not actually carry away any water. Water waves can be described very well by using a particular mathematical model called a wave equation. As it turns out, this same mathematical wave equation can be used to describe many other phenomena as well. Whenever energy is being carried from one place to another without the overall movement of matter, then the wave equation works as a good model for the phenomena. Scientists classify all such phenomena as waves. Sound and light are two examples of such phenomena. The sketch on the next page shows a side view of part of a simple wave (such as a water wave) traveling left to right at speed v. The distance between successive peaks is called the wavelength and is denoted by λ. The amplitude A of the wave gives the maximum displacement from the equilibrium (no-wave) situation. The crests of the wave are a distance A above equilibrium and the troughs a distance A below the equilibrium situation. UNIT 4 ENERGY AND INTERACTIONS II-38 © CALVIN COLLEGE Models of Light λ 2Α v Imagine a piece of wood floating in a lake or in the middle of the ocean. As waves pass by, the wood moves up and down with the water (always remaining on the surface of the water), but it would not travel along with the wave. The total time it takes for the piece of wood to move up and then back down again is called the period of the wave, and the letter T usually denotes it. The frequency of the wave is the number of up and down oscillations that occur per unit time, and it is given by frequency f = 1/T. For example, if the wood bobs up and down so that it returns back to the same location every 2 seconds, then the period of the wave is 2 seconds, and the frequency is 1/2 cycles per second. Think about what the wave would look like a time T after the time shown in the diagram. An object oscillating in the wave must return to the same location--so the wave will look just like the one in the diagram, except it will have moved over exactly a distance λ. That way an object that was at a peak will again be at a peak. Since distance = speed x time, we conclude that λ = v T. And since T = 1/f, we have λ = v/f or λf = v. This last equation gives an important relation between wavelength, frequency, and speed of the wave. Example: If a wave has frequency 2 cycles per second, and the distance between crests is 1.5 meters, what is the speed of the wave? Answer: The speed is given by v = λf where λ = 1.5 m and f = 2 cycles per second, v = 1.5 x 2 m/s = 3 m/s. At a sophisticated level, we can think of light as oscillating electric and magnetic fields carrying energy. Because of the oscillations of these fields we can talk about light as a wave, and we can ascribe particular wavelengths to all the colors of the rainbow. Different wavelengths refract and diffract differently, which allows us to separate colors using prisms or diffraction gratings. And, like other waves, light shows interference effects. That is, when light waves are combined they can cancel each other out in some cases or reinforce each other (add together to form a bigger wave) in other cases. Diffraction gratings work on the basis of UNIT 4 ENERGY AND INTERACTIONS II-39 © CALVIN COLLEGE Models of Light interference. The bright colors that we see arise at regions where light waves from different slits in the grating reinforce each other. Different wavelengths reinforce in different places, and so each wavelength becomes visible at different places. Visible light is actually only a small part of what is called “electromagnetic radiation.” Beyond red (longer wavelengths) are the infrared, microwaves (such as are used in microwave ovens), and radio waves. Beyond violet (shorter wavelengths) are ultraviolet light and x-rays. All are electromagnetic radiation. Visible light is just a narrow band in which the sun is most intense and to which our eyes are most sensitive. The visible colors of light, along with their approximate wavelengths (in nanometers) are given below. RED 620-700 ORANGE 600 YELLOW 580 GREEN CYAN 500-550 490 BLUE VIOLET 470 400-450 There are many characteristics of light that could be studied using the wave model. One of these is polarization, the direction of oscillation of the electric field, which is essential to understanding how Polaroid glasses work. UNIT 4 ENERGY AND INTERACTIONS II-40 © CALVIN COLLEGE
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