Review For Exam 2

Math 9
Review for Exam 2 – Rational expressions, radicals, rational exponents, geometry topics
(04, 05, 06_08)
1
25π‘₯ 3 βˆ’3π‘₯ 5
2
βˆ’5π‘₯ 2
2
π‘₯ βˆ’2π‘₯βˆ’15
3
π‘₯ 2 βˆ’3π‘₯ βˆ’10
4βˆ’π‘₯ 2
4
π‘₯ 2 +2π‘₯βˆ’8
50π‘₯
5
π‘₯ 2 βˆ’3π‘₯βˆ’10 10π‘₯
25βˆ’9π‘₯ 2
3π‘₯βˆ’5
8π‘₯ 2
÷
7
3
7
8
3π‘₯ 2
4π‘₯
π‘₯ 2 βˆ’2π‘₯+4
10
11
12
13
14
15
16
17
18
19
20
21
22
7
+
2π‘₯+5
π‘₯+1
+
4π‘₯
=
=
=
π‘₯+2
1
π‘₯ 2 βˆ’π‘₯
5
π‘Žπ‘
π‘Ž 𝑏
+
𝑏 π‘Ž
3
4βˆ’ 2
π‘₯
1
2βˆ’
π‘₯
3
π‘₯βˆ’5
βˆ™
π‘₯
9
=
=
6
βˆ’
=
+
βˆ’
5
π‘₯2
5
=
12π‘₯
4+2π‘₯βˆ’5π‘₯ 2
(2π‘₯+5)
=
=
=
=
βˆšβˆ’27 =
6
√π‘₯ 12 𝑦 30 =
5
Simplify: √π‘₯ 24
4
Simplify: √162 =
Simplify: √50π‘₯ 25 𝑦 3 =
3
Simplify: √128 =
3
3
5 √5 + √40 =
√320 βˆ’ √45 =
(5√3)(2√3) =
√5π‘₯ 3 π‘¦βˆš5π‘₯𝑦 5 =
(3 + 5√3)(2 βˆ’ 3√3) =
23 √8π‘₯ 5 𝑦
√2π‘₯𝑦
24
25
26
27
=
Rationalize the denominator:
Rationalize the denominator:
1
16 βˆ’4
( )
81
6
=
5√3
3+√2
2+3√2
=
=
2
3
(βˆ’27) =
2
28
(8π‘₯ 6 𝑦 30 )3 =
29
π‘₯ 1/5 π‘₯ 2/7 π‘₯ 3/5 =
30 If one leg of a right triangle is 5, and the other is 12, what is the length of the hypotenuse?
31 Find the second leg of a right triangle with hypotenuse 7 and leg 3.
32 Determine if 7,24,25 are the lengths of the sides of a right triangle.
33 Find the area and perimeter of a rectangle with length 5 and width 3.
34 Find the area of a triangle whose height is 4 and base is 7.
35 Find the area and circumference of a circle with radius 4.
Answers:
π‘₯(25 βˆ’ 3π‘₯ 2 )
βˆ’5
βˆ’5 βˆ’ 3π‘₯
5
2π‘₯
2
9
π‘₯ + 6π‘₯ βˆ’ 5
π‘₯ 2 (π‘₯ βˆ’ 1)
2
5
13 π‘₯ 𝑦
3
17
4√2
21
5π‘₯ 2 𝑦 3
1
25
√2
2
29
π‘₯ 35
𝐴 = 15, 𝑃 = 16
33
38
2
6
10
14
18
22
26
π‘₯+3
π‘₯+2
π‘₯ 2 + 2π‘₯ βˆ’ 21
3(π‘₯ + 2)
5
2
π‘Ž + 𝑏2
5
π‘₯ 4 √π‘₯ 4
3
7√5
βˆ’39 + √3
3
2
15
βˆ’2 βˆ’ π‘₯
π‘₯+4
7 + 2π‘₯
3π‘₯ 2
4π‘₯ 2 βˆ’ 3
2π‘₯ 2 βˆ’ π‘₯
4
3√2
19
23
5√5
2π‘₯ 2
3
7
11
27 9
30 13
31
√40
34 14
35
𝐢 = 8πœ‹, 𝐴 = 16πœ‹
4
8
5
π‘₯+2
(6π‘₯ 2 βˆ’ 4π‘₯)
2π‘₯ + 5
12 -3
16
20 30
24
5π‘₯ 12 π‘¦βˆš2π‘₯𝑦
28
2√3
5
4π‘₯ 4 𝑦 20
32
𝑦𝑒π‘