xFall Chapter 8 Day #6 - Synthetic Division (8.3.1 Supplement

xFall Chapter 8 Day #6 ­ Synthetic Division (8.3.1 Supplement) Notes.notebook
December 01, 2016
Chapter 8 Day #6
Synthetic Division of Polynomials
Section 8.1.3 Supplement
Objectives:
Students will...
1. Use synthetic division to divide polynomials. 2. Use division methods to determine if a polynomial is a factor of another.
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xFall Chapter 8 Day #6 ­ Synthetic Division (8.3.1 Supplement) Notes.notebook
December 01, 2016
Why use synthetic division?
faster, less tedious
only uses the coefficients of the polynomial, not the variables.
allows for multiple divisions within the problem.
can only be used when the factor is linear ie. 2
xFall Chapter 8 Day #6 ­ Synthetic Division (8.3.1 Supplement) Notes.notebook
December 01, 2016
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xFall Chapter 8 Day #6 ­ Synthetic Division (8.3.1 Supplement) Notes.notebook
December 01, 2016
The volume of cookie tin is If the height of the tin is what are the length and width?
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xFall Chapter 8 Day #6 ­ Synthetic Division (8.3.1 Supplement) Notes.notebook
December 01, 2016
When the remainder = 0, then the divisor (# dividing by) is a factor of the dividend
(# being divided)
Remainder Theroem
If a polynomial is divided and has a remainder, then the remainder is the value of the polynomial at the divisor.
What does that mean?
Look back at example 1.
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xFall Chapter 8 Day #6 ­ Synthetic Division (8.3.1 Supplement) Notes.notebook
December 01, 2016
If is evaluated when , the result should be Try It!
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