Factoring the Sum and Difference of Cubes Essential Question Compare/contrast sum & difference of cubes with difference of squares. Sum of Two Cubes 3 3 2 2 ππ + ππ = (ππ + ππ)(ππ β ππππ + ππ ) Sum (addition) sign Two Cubes Difference of Two Cubes 3 3 2 2 ππ β ππ = (ππ β ππ)(ππ + ππππ + ππ ) Difference (subtraction) sign Two Cubes Use this pattern: 3 3 2 2 ππ + ππ = (ππ + ππ)(ππ β ππππ + ππ ) Write a new binomial without the exponents. Use the new binomial to create the trinomial. 1. Square the first and last terms of the binomial to create the first and last terms of the trinomial. 2. Multiply the terms of the binomial to create the middle term of the trinomial. 3. Sign of the 2nd term is opposite of the binomial. 3 3 2 2 ππ + ππ = (ππ + ππ)(ππ β ππππ + ππ ) Factor: Write as a sum of 2 cubes: Write the binomial without the cubes: 3 π₯π₯ 3 +8 3 = π₯π₯ +2 = (π₯π₯ + 2)( ) 3 3 2 2 ππ + ππ = (ππ + ππ)(ππ β ππππ + ππ ) = (π₯π₯ + 2)( Square the first and last terms: Multiply the terms in the binomial: Opposite signs: = (π₯π₯ + = (π₯π₯ + = (π₯π₯ + 2 2)(π₯π₯ 2 2)(π₯π₯ 2 2)(π₯π₯ ) + 4) 2π₯π₯ + 4) β 2π₯π₯ + 4) 3 3 2 2 ππ β ππ = (ππ β ππ)(ππ + ππππ + ππ ) Factor: Write as the difference of 2 cubes: Write the binomial without the cubes: = 3 8π₯π₯ β 27 3 (2π₯π₯) 3 β3 = (2π₯π₯ β 3)( ) ππ3 + ππ 3 = (ππ + ππ)(ππ2 β ππππ + ππ 2 ) = (2π₯π₯ β 3)( Square the first and last terms: = (2π₯π₯ β 2 3)(4π₯π₯ = (2π₯π₯ β 2 3)(4π₯π₯ Multiply the terms in the binomial: Opposite signs: = (2π₯π₯ β 3)(4π₯π₯ 2 ) The sign of the last term in the trinomial is always positive! + 9) 6π₯π₯ + 9) + 6π₯π₯ + 9) Hint β’ Donβt try to factor the trinomial after factoring the sum or difference of two cubes. β’= 2π₯π₯ β 3 4π₯π₯ 2 + 6π₯π₯ + 9 β’ If the greatest common factor has already been taken out, the resulting trinomial cannot be factored using integers. 3 3 2 2 ππ + ππ = (ππ + ππ)(ππ β ππππ + ππ ) Factor: Write as a sum of 2 cubes: Write the binomial without the cubes: = = 6 π₯π₯ + 125π¦π¦ 2 3 (π₯π₯ ) 2 (π₯π₯ 3 3 +(5π¦π¦) + 5π¦π¦)( ) 3 3 2 2 ππ + ππ = (ππ + ππ)(ππ β ππππ + ππ ) Square the first and last terms: = = 2 (π₯π₯ 2 (π₯π₯ Multiply the terms 2 in the binomial:= (π₯π₯ Opposite signs: + + 5π¦π¦)( 4 5π¦π¦)(π₯π₯ 4 2 + ) 2 25π¦π¦ ) 2 + 5π¦π¦)(π₯π₯ 5π₯π₯ π¦π¦ + 25π¦π¦ ) = (π₯π₯ 2 + 5π¦π¦)(π₯π₯ 4 β 5π₯π₯ 2 π¦π¦ + 25π¦π¦ 2 ) 3 3 2 2 ππ β ππ = (ππ β ππ)(ππ + ππππ + ππ ) Factor: Write as the difference of 2 cubes: Write the binomial without the cubes: = 1β 3 (1) = (1 β 9 3 216π₯π₯ π¦π¦ β 3 3 6π₯π₯ π¦π¦ 3 6π₯π₯ π¦π¦)( ) 3 3 2 2 ππ + ππ = (ππ + ππ)(ππ β ππππ + ππ ) Square the first and last terms: 3 = (1 β 6π₯π₯ π¦π¦)( 3 = (1 β 6π₯π₯ π¦π¦)(1 Multiply the terms in the binomial: 3 3 + ) 6 2 36π₯π₯ π¦π¦ ) 6 2 = (1 β 6π₯π₯ π¦π¦)(1 6π₯π₯ π¦π¦ + 36π₯π₯ π¦π¦ ) Opposite signs: = (1 β 6π₯π₯ 3 π¦π¦)(1 + 6π₯π₯ 3 π¦π¦ + 36π₯π₯ 6 π¦π¦ 2 )
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