Day 6 Empirical and Molecular Formula.notebook Empirical and Molecular Formulas April 07, 2016 How do we find the E.F. of a compound? E.F. is the lowest whole number ratio of elements in a chemical formula M.F. is a multiple of the E.F.; it is the actual ratio of elements in a real compound. Using percentage composition data of course! Example Substance Molecular Formula Empirical Formula Lowest Ratio 1:1 hydrogen peroxide H2O2 HO water H2O H2O 2:1 glucose C6H12 O6 CH2O 1:2:1 1:1 benzene C6H6 CH acetylene C2H2 CH 1:1 aniline C6H7N C6H7N 6:7:1 Apr 69:39 AM Apr 69:49 AM Example #1: Find the E.F. of a compound that is 85.6% carbon and 14.4% hydrogen. Nov 238:43 AM Apr 610:03 AM More on Molecular Formula Recall: Molecular Formula (M.F.) = n x Empirical Formula (E.F.) where n = 1, 2, 3 ... E.F. = CH2 O M.F. Molar Mass X 1 Example #2: Find the E.F. of a compound containing 81.7% carbon and 18.3% hydrogen. Name of Compound Therefore, if we know the E.F. of a molecule and the molar mass of a molecule, we can determine its M.F. The molar mass of the E.F. can be easily calculated. M.F. (find) = E.F. (given) molar mass of M.F. (given) molar mass of E.F. (use PT to get it) X 2 X 3 X 4 X 5 X 6 Apr 98:37 AM Apr 98:48 AM 1 Day 6 Empirical and Molecular Formula.notebook April 07, 2016 Example #3: The E.F. of ribose (a sugar) is CH2O. A mass spectrometer was used to determine that the molar mass of ribose is 150 g/mol. What is the molecular formula of ribose? Nov 238:33 AM Nov 2510:12 AM 2
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