Big Idea: Matter & Atoms The Mole Stoichiometry Limiting Reactants Percent Yield Avogadro’s Number (NA) ◦ 6.022 𝑥 1023 𝑎𝑡𝑜𝑚𝑠/𝑚𝑜𝑙 The mole… 1 mol of Ne atoms = 6.022 𝑥 1023 𝑎𝑡𝑜𝑚𝑠 𝑜𝑓 𝑁𝑒 = 20.18 g 1 mol of Cl- ions = 6.022 𝑥 1023 𝑎𝑡𝑜𝑚𝑠 =35.45 g The mole is a fundamental unit for counting particles on the macroscopic level. It allows us to draw quantitative connections between macroscopic experiments & atomic level chemical processes. Molecular weight = 12.01 amu + 2(16.00 amu) = 44.01 amu/CO2 molecule = 44.01 g/mol CO2 1 mol CO2 molecules = 6.022 x 1023 molecules = 44.01 g How many moles of NaCl are there in 48.0 g of NaCl? Now many grams of C2H6 are there in 18.7 moles of C2H6? How many water molecules are contained within 56.0 g pure sample of water? How many hydrogen atoms are contained within 56.0 g pure sample of water? gfm=gram formula mass… Same as molar mass C=12.01 amu H=4(1.01) amu O=4(16.00) amu 12.01 amu 4.04 amu 64.00 amu C=12.01 amu 12.01 amu H=4(1.01) amu 4.04 amu O=4(16.00) amu 64.00 amu 80.05 amu 80.05 amu What mass of water is produced when a car burns 264.4 g of methane gas? Step 1: Write the balanced chemical equation. Step 2: Convert to Mass of Water How many grams of carbon dioxide and iron are produced when 114.0 g of carbon monoxide gas is added to a vessel containing excess hot iron (III) oxide? Step 1: Write balanced chemical equation. Step 2: Calculate masses of carbon dioxide & iron. Calculate the mass of solid sodium bicarbonate needed to produce 32.0 g of sodium carbonate in a decomposition reaction. If you have set quantities of two different reactants, one will get used up & some amount of the other will be left over. Limiting Reactant ◦ The reactant that is used up limits how far the reaction will proceed. Excess Reactant ◦ The reactant that has some left over when the reaction is complete. What is the limiting reactant when 28.0 g of glucose reacts with 14.0 g of oxygen gas in a combustion reaction? What is the mass of carbon dioxide produced? 𝐴𝑐𝑡𝑢𝑎𝑙 𝑌𝑖𝑒𝑙𝑑 𝑓𝑟𝑜𝑚 𝐿𝑎𝑏 𝑇ℎ𝑒𝑜𝑟𝑒𝑡𝑖𝑐𝑎𝑙 𝑌𝑖𝑒𝑙𝑑 𝑓𝑟𝑜𝑚 𝐸𝑞𝑛 × 100% = 𝑃𝑒𝑟𝑐𝑒𝑛𝑡 𝑌𝑖𝑒𝑙𝑑 Calculate the percent yield if 15.0 grams of carbon dioxide were produced in lab from the previous example.
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