Physical oceanography, MSCI 3001 Oceanographic Processes, MSCI 5004 Dr. Katrin Meissner [email protected] Week 4 Stability in the water column Gravity acts on vertical density gradients in the ocean to either stabilise or destabilise the water column: Three examples of ocean stability are Ocean Dynamics Stable Stratification 27.25 27.5 22.25 25.5 27.25 Neutral Stratification Unstable Stratification Archimedes Principle: The upward force acting on a body within a fluid, is equal to the weight of the fluid displaced by the body Wood ρ=500kg/m3 26.75 Weight = 5000N Net upwards force (10000-5000=5000N) Upthrust = 10000N Weight = 5000N What is the vertical density gradient across the top 200m at (i) the equator, and (ii) 60S ?(iii) Estimate the meridional (north-south) gradient at 60S. Weight = mg = ρVg ρ=1000kg/m3 And a weight of 1000x10=10000N Wood block will accelerate upwards! What would happen with a concrete block ρ=2400kg/m3 1 Archimedes Principle: The upward force acting on a body within a fluid, is equal to the weight of the fluid displaced by the body PROOF F1=P1A=Dρgh2 Pressure, P=hρg P=F/A m=ρV D P1=Dρg ρ1 ρ1Vg Negatively Buoyant Weight of displaced water = mg = ρ1Vg ρ2Vg ρ2 A=h2 V=h3 ρ h Area=h2 Net Force on box, F = F1 – F2 F = Dρgh2 – (D+h)ρgh2 = -h3ρg = -Vρg = -mg = - weight of water displaced depth Stability ρ2 ρ1 Depth Stable ρ1< ρ2 Stable ρ1< ρ2 ρ2 Density small • If the balloon moves into a fluid of different density… • Buoyancy forces will try to return the balloon to its equilibrium depth Time Time Less energy required to mix • Imagine a balloon filled with seawater at rest (equilibrium depth) in two different density gradients • When set in motion the balloon will oscillate about its equilibrium depth with a frequency proportional to the density gradient large Depth Depth ρ1 • Imagine a balloon filled with seawater at rest (equilibrium depth) Depth Neutral Depth Density Depth P2=(D+h)ρg • The larger the density gradient, the higher the frequency (Brunt-Väisälä or buoyancy frequency) and the shorter the period • Large density gradient therefore gives rise to stable conditions - with little mixing Depth F2=P2 A=(D+h)ρgh2 More energy required to mix 2 ⎛ g dρ ⎞ d 2 z' = −⎜ ⎟z' dt 2 ⎝ ρ dz ⎠ Where does the buoyancy frequency come from? ρ0 Density ⎛ g dρ ⎞ N 2 = ⎜ ⎟ ⎝ ρ dz ⎠ d 2z 2 2 +N z =0 dt € oscillator simple harmonic € h ρ1 z’ Solving the equation: ρ2Vg ρ2 ρ1Vg Positively buoyant €two cases: • N2<0 Net Force, F= ρ1Vg- ρ2Vg =Vg((ρ0+kh)-(ρ0+k(h+z’))) =-Vgkz’ ρ1Va =-Vgkz’ a =-(gkz’)/ρ1 ⎛ g dρ ⎞ d 2 z' = −⎜ ⎟z' dt 2 ⎝ ρ dz ⎠ Conservation of linear momentum: F = ma F = ρ1Va d 2 z' a= 2 dt z m2+N2=0 m2=-N2 ρ2> ρ1 ρ (z)=ρ0+kz m1/ 2 = ± −N 2 z(t) = Ae • N2>0 −N 2 t + Be − −N 2 t m1/2 are complex solutions € z(t) = Acos(Nt) + Bsin(Nt) frequency f=N/(2π) period T=2π/N € € € Where does the buoyancy frequency come from? ρ0 ρ0 Density Solution 1: run away solution (if N2 is negative, if dρ/dz<0) h g dρ g dρ − t − − t ρ dz ρρ dz z(t) = Ae z’ 1 ρ2Vg ρ2 € ρ1Vg F=ma = ρ1Va Density Solution 2: simple harmonic oscillator (if N2 is positive, if dρ/dz>0) h ⎛ g dρ ⎞ ⎛ g dρ ⎞ z(t) = Acos⎜ ρ1 t ⎟+ Bsin⎜ t ⎟ ⎝ ρ dz ⎠ ⎝ ρ dz ⎠ ρ Vg + Be z’ ρ2> ρ1 ρ (z)=ρ0+kz z Where does the buoyancy frequency come from? 2 ρ2> ρ1 ρ (z)=ρ0+kz ρ2 Positively buoyant € Net Force, F= ρ1Vg- ρ2Vg =Vg((ρ0+kh)-(ρ0+k(h+z’))) =-Vgkz ρ1Va =-Vgkz a =-1/ ρ(gkz) ρ1Vg F=ma = ρ1Va Positively buoyant Net Force, F= ρ1Vg- ρ2Vg =Vg((ρ0+kh)-(ρ0+k(h+z’))) =-Vgkz ρ1Va =-Vgkz a =-1/ ρ(gkz) z 3 Buoyancy frequency The influence of stability is usually expressed by the buoyancy frequency which is also referred to as the Brunt-Väisälä Frequency : Density Gradient • The buoyancy Frequency (N) quantifies the importance of stability Buoyancy frequency • The buoyancy frequency is the frequency at which a vertically displaced parcel will oscillate within a stable environment. • Parcels that are vertically perturbed are accelerated back to their initial position by a restoring buoyancy force. • In an unstable environment, vertically displaced fluid parcels do not oscillate, but instead continue to move in the direction of their initial displacement. • Larger frequency (N) the more stable the water column http://www.es.flinders.edu.au/~mattom/Utilities/bvf.html Brunt-Väisälä Frequency Brunt-Väisälä frequency (N) Sir David Brunt D. Brunt, The period of simple vertical oscillations in the atmosphere, Quarterly Journal of the Royal Meteorological Society 53 (1927), pp. 30–32. Vilho Väisälä V. Väisälä, Über die Wirkung der Windschwankungen auf die Pilotbeobachtungen, Soc. Sci. Fenn. Commentat. Phys.-Math. 2 19 (1925), pp. 1–46. 4 Brunt-Väisälä Oscillation or Buoyancy Oscillation • The frequency with which a parcel of seawater will oscillate when displaced a small vertical distance from its equilibrium position Strait of Gibraltar Internal Waves Somalia The period is given by T = 2 π /N If the stratification is strong, then N is large and T is small Fast oscillations in a strongly stratified ocean. If the stratification is weak (deep ocean) then N is small and T is large • These oscillations are called internal waves – they occur along density gradients An internal wave travelling up the Derwent River estuary in Hobart, Tasmania. The effect of the wave is visible by streaks of smooth water produced by the convergences above the wave troughs.The wave seen here is of the shortest possible wavelength (compare the distance between the streaks with the yacht) and has a period of 10 - 20 minutes. Brunt Väisälä frequency 100 200 ? ? Taken from Matthias Tomczak’s webpage: http://www.es.flinders.edu.au/~mattom/IntroOc/ notes/lecture10.html 5 Classify these ocean scenarios: Brunt Väisälä frequency N=0.014s-1 T=? N=0.003s-1 T=? Are they stable, unstable or neutral? Units: s-1 Increasing Property T=2π/N Depth (m) The time taken to make one oscillation S S T T S T Acts as a barrier for mixing of nutrients up into photic zone What happens if Convective overturning • Leads to the formation of winter mixed layers • E.g. night time cooling during winter, cold water overlies warm water… UNSTABLE Depth ρ1 Unstable ρ1> ρ2 ρ2 6 Mixing How are properties transferred in water? • Water can be mixed through convective overturning (previous examples…) • Water can also be mixed through turbulent diffusion (e.g. wind driven mixing) Molecular diffusion is much slower than turbulent diffusion How are properties transferred in water? Molecular Diffusion Turbulent Diffusion clear fluid + red dye = pink water Just like shaking a container will speed up the mixing rate 7 The diffusive flux is proportional to the gradient (and of opposite sign) Salt transport and molecular diffusion Γ = ρsu u = velocity of the fluid (in m/s) Fick’s Law of diffusion Γ = −ρK D ∇s ρ = density of fluid (in kg/m3) € € u Γ = rate of transport of salt across the unit area normal to the direction of Γ ∂s ∂x ∂s Γy = −ρK D ∂y ∂s Γz = −ρK D ∂z Γx = −ρK D € due to fluid motion € Γ is the flux2 of salinity per unit area € (in kg/(m s)), it is also called the advective flux. There is another means of transporting salt: molecular diffusion € u Our total flux per unit area becomes: € Γ = ρsu − ρK D ∇s KD is the molecular diffusivity of salt in water (~10-9 m2/s) € But do we really know € u? We cannot calculate/measure changes in u on very short timescales and very small spatial scales… Γ = ρsu = ? € € BUT we try to take their effects on the main circulation into account! € In analogy with molecular diffusion (which is based on thermodynamics), we define an “eddy viscosity” (eddy diffusion, which is based on nothing) to take into account the mixing due to turbulence that we cannot resolve. Flux of salinity per unit area due to turbulence: € Γ = −ρK E ∇s 8 The full flux of salinity per unit area is therefore: Diffusion - the flow from higher to lower concentrations Γ = ρsu − ρK E ∇s − ρK D ∇s Flux due to large scale fluid motion (the mean flow) If box 2 contains water containing 1kg of salt per cubic meter and box 1 contains fresh water. If L =1m and KD=10-9m2s-1 what will the initial flux be? Flux due to molecular diffusion Flux due to “eddy diffusion” (= non-resolved fluid motion) € Γx = −K KE >> KD In oceanography we usually do not take molecular diffusion into account. Γ ≈ ρsu − ρK E ∇s What will the initial flux be if we consider eddy diffusion instead of molecular diffusion (KE=10-1m2s-1)? This transport equation can be written for every scalar in the fluid (oxygen, nutrients, temperature, CFCs,…). Fick’s Law of diffusion K is the diffusion constant SI unit m2s-1 € € Flows from high concentrations to low concentrations the flux is ‘down gradient’ Flux (kgm-2s-1) dC dx Γ = −ρK E ∇s ∂s Γx = −ρK E,h ∂x ∂s Γy = −ρK E,h ∂y ∂s Γz = −ρK E,v ∂z Concentration gradient (could be salinity, temperature, oxygen,…) Vertical or horizontal diffusivity (m2/s) Molecular versus Turbulent (Eddy) Diffusivity Eddy (turbulent) diffusivities are usually many orders of magnitude larger than their molecular counterparts. Example: Molecular diffusivity of salt in water KD ~ 10-9 m2/s Vertical diffusion in the ocean, KE,v ~ 10-5 - 10-3 m2/s Horizontal diffusion in the ocean, KE,h ~ 1 - 1000 m2/s • Deep ocean mixing occurs near rough topography • Surface layer turbulence can be caused by wind mixing Diffusion effects will therefore be strongest in regions with high concentration gradients € This is very important in estuaries where there is a SALT gradient…. More appropriate to consider mixing along and across isopycnals 9 The Gulf Stream Richardson Number: Predicts the onset of turbulence Remember N2 can be <0 Where N is the Brunt Väisälä frequency, and u the horizontal velocity. If Ri < 0 (i.e. N2 < 0) the water column is unstable – turbulent convective mixing If Ri > 0 (i.e. stable stratification) then velocity shear (du/dz) must be large to generate turbulence. If Ri > ¼ no turbulence is found If Ri < ¼ turbulence may be found. • Where will diffusive effects be strongest? … In regions with high concentration gradients Determine if turbulence will occur in the following examples: What is du/dz? Transport of Volume, Heat & Salt Flux: Amount of heat, salt or volume that flows through a unit area per unit time (e.g. in Jm-2s-1 (for heat), kgm-2s-1 (for salt) or m3m-2s-1=ms-1 (for volume)). Volume transport: The volume of moving water measured between two points of reference and expressed in cubic meters per second or in Sverdrup (Sv). 1 Sv = 1 million cubic meters per second = 106 m3/s Upper Ocean Deep Ocean Harald Sverdrup 10 The amount of salt in a parcel of water moving through the ocean remains relatively constant (unless the parcel is in contact with the surface, then river discharge, evaporation, precipitation, sea ice, will change it!) Salinity is conservative. In most instances the advective flux will dominate, so the diffusive part can be ignored. We are also usually interested in 1D flow (e.g. flow through a channel or across a section) Volume transport of an ocean current with velocity ‘u’ through an area A is given by: Volume transport = u . A = u.H.L The flux of salt into the cube includes an advective contribution (ρsu) and a diffusive contribution (-Kρds/dx) Diffusive flux (turbulent and molecular) of salt has a negative sign because it is directed in the opposite direction to the salinity gradient u A Volume swept out Advective Flux Diffusive Flux The conversation equation for salt per unit volume is given by But don’t panic... Transport of Volume, Heat & Salt Total Heat and Salt Fluxes If we know the heat (or salt) per m3 we can convert volume flux into heat (or salt) flux. VT = u × L × H QT = ρc p uT × L × H Heat per m3 = ρcpT Salt per m3 = ρS S fT = ρuS × L × H So, multiplying by uA Q=ρcpTuA Sf=ρSuA ρ is density, cp ~ 4000 J/Ckg, salinity is in absolute units, 35kg/ 1000kg m3/s J/s Kg/s T, S € UNITS heat flux – Watts (1 Watt = 1 J/s). Salt flux - kg/s 11 Example Calculate the total volume, heat and salt fluxes a) Past Tasmania b) Through the Drake Passage. Assume the ocean currents persist over the upper 1000m only. c) Why might the volume flux be different? 12
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