- F-Y b'5 c '
Exqrn
Q,P. Code =743900
MODEL ANSWER
SUBIECT: NAUTICAL PHYSICS AND ELECTRONICS
EXAM.DATE
=25/Lt/zoL6
Q.P.Code t7439OO
Ql.
MOST APPROPRTATE ANSWER
i)
ii)
iii)
iv)
v)
viJ
viD
viiiJ
ix)
x)
xi)
xii)
xiii)
xiv)
Along the axis of rotation
Product of masses of these particle
Decreases
N/m
Lm
PV=RT
Nature of material
Conduction
Boyle's law
Coefficient of thermal expansion
[M-t LrT+1
Surface tension
Longitudinalwave
Virtual
xvJ dH=du+dw
Q2.
[A]
Explanation of streamline flow
Diagram of streamline flow
Explanation of turbulent flow
Diagram of turbulent flow
Statement and explanation of Bernoulli's principle
Q2.
tB]
Rs= radius of a body in space = 3 Re
Ms= mass of body in space = 2 Me
We= weight of body on earth = 90N
To find weight of body in space [ws)
Weight of body on earth
We= Fe= GMem/Re'
...(1)
.......
Weight of body in space
Ws=Fs=GMsm/Rs2
.............(Z)
Dividing Eq" (1) BY (2)
We/Ws = Me/Ms x (Rs/Re), = (L/Z)
We/Ws = Tzxg
Ws =
2xWe/9 =2x90/9
(3/r),
= 20N
Ws = 20N
OR
Q2.
[A]
Defination of elastic collision
Expression of velocities after the collision
V, = u1[mr- rnz/rr\+ mz ] + Zuzlmr/mr+ mz l
Vz = ur
Q2.[B]
m=
f2mrf m1+
mz
]
+ uz I
mz- r6t/ mr + rnz ]
1k&r= 0.3m,v= Sm/s.
I=? KE=?
V=nv
W = v/r = 16.66 rad/s
I=mrz
= 1x (0.3)'= 0.09 kgm'
K.E = YzlW, = Yzx 0.09 x (76.66),
= 12.49 |
Q3.
[A]
Explanation of effect of temp. on velocity of sound
=M/Y
o
= M/uo
V=p/ atfC
vo=po/ at
OoC
PV = RT and P"% = RTo
V1- Vo= !2
Q3,B]
A = 600, 6',= 300, Vg=?
Prism formula
Fg
= Sin (A + 6m/Z)
= Sin [60 +30
= Sin 45o
= 0.707
Fg
/
/
/
2)
sin (A/2)
/
Sin (60/2)
Sin 300
/ 0.5
= l'4L4
now
Vg= c/ve
vr=c/
Vg
=3x70r/L414
= Z.IZ x 10s
m/s
Velocity of light in glass =2.L2 x 10s m/s
OR
Q3.[A]
Defination of Doppler effect
Explanation of first four cases of Doppler effect
Q3.[B]
h, =10cm
u = -10 cm
f
= -15 cm
7/f
= 7/v +
Llv
=
7/u
I/f - L/u
= -LILS
=
-L/tS
=
t/30
- 7/-L0
+ L/70
V
= 30 cm (image is
m
=hr/hr='v/u
h,
= -v
=
virtual)
/ux [h,)
-30/(-L0) x 10
= 30 cms
Image is 30 cm high, erect, virtual and v = 30 cm
Q4.[AI
Explanation of Isothermal changes
Explanation of Adiabatic changes
Q4.B]
ce = 1.8 xL0-'/oC
qs=
\.2 x
L, - Lr =
10's /oC
0.6, LB = length of brass rod at 00c
L, = length
ofsteel rod at Ooc
For brass rod
L=Lr(1 +crt)
L-
L'=
Ln
61s
t ........ (1)
For steel rod
L = Ls(1 + ar)
L-
Lr-
Ls ors,........
(Z)
As the different between length of rod at all temp. is same
Lscnt=Lscst
Ln= cs f a" Ls
Ls= L.2 x 10€ / I.Bx 10-s Ls
L"= L.2/7.8 L,
Ls= 1.5 Lt
As Lr,Lr,
Lt-Lt = 0.6
1.5 LB - Ls= 0.5
0.5 LB= 0.6
Ls= 0.6/0.5 = 1.2 m
Ls = Ls + 0.6 = L.2 +0.6 = 1.8 m
OR
Defination of workdone of Adiabatic process
Derivation of workdone for Adiabatic process.
Q4.
tAl
Q4.
[BI
Defination and explanation of conduction
Defination and explanation of convection
Defination and explanation of radiation
Q5.
[AI
Defination of coefficient of linear expansion
Expression of coefficient of linear expansion
Q5.[B]
Characteristicsofloudness
Characteristics of Pitch
Characteristics of Quality or timbre
Q5.[C]
Defination of centre of mass
Diagram of C.M.
Expression for centre of mass of two particle
OR
Q5.
[Al
Explanation of All three Laws of Newton.s
With relevant examples
Q5.
[B]
Explain total internal reflection
Draw necessary diagram
Q5.[C]
Define
Define
Derive the relation between and
=l