ASSESSMENT: QUARTER-1
Name___________________________________
MULTIPLE CHOICE. Choose the one alternative that best answers the question.
Simplify using the power of i .
1) i36
A) -i
1)
C) i
B) -1
D) 1
2) i70
2)
A) i
B) 1
D) -i
C) -1
3) i47
3)
A) i
B) 1
C) -i
D) -1
A) -i
B) i
C) 1
D) -1
4) i33
4)
Simplify the radical, if possible. If imaginary, rewrite in terms of i and simplify.
5) -64
A) -8i
B) -32
C) 8i
D) -8
6) -
-63
A) 3i
5)
6)
7
C) -i
B) 3 7
63
Simplify the expression, writing the result in terms of i
7) 3 - -9
3
A) 1 + 9i
B) 1 + i
C) 1 - 9i
D) -3i
7
7)
D) 1 – i
Divide and write your answer in a + bi form.
8) 11
4 + 3i
A) 11 + 11 i
4
3
8)
B) 44 - 3 i
7 7
C) 44 - 3 i
25 25
Perform the indicated operation. Write the result in a + bi form.
9) (8 - 9i) - (-2 - 3i)
A) 10 - 12i
B) 4i
C) -2i
10) 4i(3 + 7i)
A) -16i
D) 44 - 33 i
25 25
9)
D) 10 - 6i
10)
B) 28 + 12i
C) 19i
A-1
D) -28 + 12i
Name the complex conjugate, then find the product.
11) -5 - i
A) 5 + i; 24
B) -5 + i; 24
11)
C) 5 + i; 26
D) -5 + i; 26
Compute the special product and write your answer in a + bi form.
12) (6 - 4i)(6 + 4i)
A) 52
B) 52 + 48i
C) 20 - 48i
12)
D) 20
Determine whether the equation is quadratic. If so, identify the coefficients a, b, and c.
13) 9 = -6x2
A) a = 0, b = 9, c = -6
B) a = 6, b = 0, c = 9
C) a = 6, b = 9, c = 0
D) not quadratic
Solve. Simplify your results.
14) x2 = -5x - 12
A) -5 ± 13
2
13)
14)
B) -5 ± i 23
2
C) -5 ± i
23
D) -5 ±
13
Solve using the zero product property. Be sure the equation is in standard form and factor out any
common factors before attempting to solve. Check all answers in the original equation.
15) (m + 5)(m + 6) = 6
15)
A) m = -8, m = -3
B) m = 8, m = 3
C) m = -5, m = -6
D) m = 1, m = 0
Solve using the square root property of equality. Write answers in exact form. If there are no real
solutions, so state.
16) Solve using the square root property of equality. Write answers in exact form. If there
16)
are no real solutions, so state.
(x + 5)2 = 7
A) 5 ± 7
B) ±5 7
C) -5 ± 7
D) no real solutions
Fill in the blank so the result is a perfect square trinomial, then factor into a binomial square.
17) x2 + 5x +
17)
5 2
A) 25 ; x +
2
4
5 2
B) 5 ; x +
4
2
C) 25; (x + 5)2
5 2
D) 25 ; x +
2
2
A-2
Solve the problem.
18) The height h in feet of an object thrown upward from a height of 5 ft, with an initial
18)
2
velocity of 30 ft/sec, is given by the equation h = -16t + 30t + 5, where h represents the
height of the object after t seconds. How long will it take the object to hit the ground?
Answer in decimal form rounded to the nearest thousandth.
A) 1.829 seconds
B) 2.329 seconds
C) 2.029 seconds
D) 3.149 seconds
Solve by completing the square. Write your answer in exact form.
19) x2 - 12x = -27
A) x = 3, x = -9
B) x = -3, x = -9
C) x = -3, x = 9
D) x = 3, x = 9
19)
Use the discriminant to determine whether the given equation has two irrational roots, two rational roots,
one repeated root, or two complex roots. Do not solve.
20) -2x2 + 3x + 9 = 0
20)
A) one repeated root
B) two irrational roots
C) two complex roots
D) two rational roots
21) 49x2 - 14x = -1
A) two complex roots
C) two irrational roots
21)
B) two rational roots
D) one repeated root
Graph the inequality on a number line.
22) -4 ≤ y < 1
A)
22)
B)
C)
D)
A-3
Solve the absolute value equation. Write the solution in set notation.
23) -2|x - 4| + 8 = 6
A) {-7, 15}
B) {-3, 11}
C) {-1, 9}
23)
D) {3, 5}
Solve the absolute value inequality. Write the solution in interval notation.
24) 3|x + 7| - 6 ≥ -3
A) (-∞, -4] ∪ [-10, ∞)
B) [-4, -10]
C) (-∞, -8] ∪ [-6, ∞)
D) [-8, -6]
24)
Determine the intersection or union of sets A, B, and C as indicated, given
A = {5, 10, 15, 20}
B = {25, 30, 35, 40}
C = {10, 20, 30, 40}.
25) Find A ∩ C.
A) {5, 10, 15, 20, 30, 40}
B) {5, 15, 30, 40}
C) { }
D) {10, 20}
26) Find A ∪ C.
A) { }
C) {10, 20}
25)
26)
B) {5, 10, 15, 20, 30, 40}
D) {5, 15, 30, 40}
27) Find A ∩ B.
A) {5, 10, 35, 40}
C) { }
27)
B) {10, 15}
D) {5, 10, 15, 20, 25, 30, 35, 40}
28) Find A ∪ B.
A) {10, 15}
C) {5, 10, 35, 40}
28)
B) {5, 10, 15, 20, 25, 30, 35, 40}
D) { }
Solve.
29) 5 - 4(3x - 2) = 2 + 3(2 x - 5)
A) 13
B) 5
9
9
29)
C) 10
9
D) 8
9
Identify the equation as an identity, a contradiction, or a conditional equation, then state the solution.
30) 2x + 10(-x - 7) = -54 - 4(2x + 3)
30)
A) Conditional; x = - 35
B) Conditional; x = 35
8
8
C) Identity
D) Contradiction
A-4
Answer Key
Testname: ASSESSMENT- QUARTER-1
1) D
2) C
3) C
4) B
5) C
6) D
7) D
8) D
9) D
10) D
11) D
12) A
13) B
14) B
15) A
16) C
17) A
18) C
19) D
20) D
21) D
22) D
23) D
24) C
25) D
26) B
27) C
28) B
29) A
30) D
A-5