Calculus Chapter 2: Limits Section 2.8: The Intermediate Value Theorem (IVT) SWBAT: use the intermediate value theorem to prove that continuous functions have values at a given point on a given interval. Standard: F.IF. Øο Understand the concept of a function and the use of function notation. βDo Nowβ Sketch the graph π(π₯). At each point of discontinuity, determine the type of discontinuity and state whether it is left or right continuous. π₯ πππ π₯ < 1 π π₯ = 3 πππ 1 β€ π₯ β€ 3 π₯ πππ π₯ > 3 Graph the following: π₯ ! + 1, β3 β€ π₯ β€ 0 β π₯ = ! ! β1 β π₯ β π₯ , 0 < π₯ β€ 2 Calculus Chapter 2: Limits Draw a continuous function, π(π₯) that meets the following conditions: π 2 = β3 πππ π 5 = 4 Intermediate Value Theorem: If π(π₯) is continuous on a closed interval π, π πππ π(π) β π(π), then for every value M between π π πππ π(π), there exists at least one value π β (π, π) such that π π = π. Øο Speeding up in a car Øο Altitude of a plane taking off Example: Prove that π π₯ = 2π₯ ! β 1 has at least one solution in the interval [0, 2]. Step 1: Check to see that the function is continuous on the given interval. Step 2: Evaluate the function at each endpoint. Step 3: Make a statement using the IVT. Calculus Chapter 2: Limits Example: Prove that π π₯ = π₯ ! takes on the value 0.5 in the interval [0, 1]. Step 1: Check to see that the function is continuous on the given interval. Step 2: Evaluate the function at each endpoint. Step 3: Make a statement using the IVT. Example: Why canβt we use the intermediate value theorem to say that π(π₯) takes on a particular value in the interval [0, 2]. π₯! β 1 π π₯ = π₯β1 Calculus Chapter 2: Limits ! Example: Show that π π₯ = !!! takes on the value 0.599 for some π₯ β [1, 2]. Closure: What characteristic must the function possess in order to use the intermediate value theorem? Homework: Pg. 109 #βs 1 β 5
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