Direct Variation May 2012 Learning Objective The student will learn to solve problems involving Direct Variation. Water Pressure As scuba divers go deeper under the waterβs surface, they experience increasing pressure on their bodies. The table to the right depicts the relationship between depth and pressure. π ππ·π/π π Depth x (m) Pressure y (kPa) 3 29.4 9.8 6 58.8 9.8 9 88.2 9.8 12 117.6 9.8 Direct Variation Notice that the ratio of the pressure to the depth is constant. The pressure is said to vary directly with the water pressure. This relationship is given by the following equation: ππππ π π’ππ = 9.8 × π·πππ‘β 9.8 is the constant of variation. Definition of Direct Variation A linear function defined by an equation of the form, π¦ = ππ₯ π β 0 is called a direct variation, and we say that y varies directly as x. The constant m is called the constant of variation. Example: Finding m Suppose y varies directly as x, and π¦ = 15 when π₯ = 24. Consequently, and π¦ = ππ₯. 15 = π × 24 ο 15 24 π= = 5 8 Example: Finding x Using the previous example, π¦ = ππ₯. Where, π= 15 24 = 5 8 If , π¦ = 25 find x. 25 = 8 5 5 π₯ 8 π₯ = β 25 = 40 Class work: Page 354, Oral Exercises 1-4 Homework: Page 354, Written Exercises 1-19 odd Proportion Stretched Spring y y Unloaded Loaded Loaded and stretched Example: Loaded Spring The stretch in a loaded spring varies directly with the load it supports (within the springβs elastic limit). A load of 8 g stretches a certain spring 9.6 cm. a. Find the constant of variation (the spring constant) and the equation of the direct variation. b. What load would stretch the spring 6 cm? Example: Loaded Spring Equation of direct variation: π¦ = ππ₯ where x is the load in grams, y is the resulting stretch in cm, and k is the spring constant. a. Substitute π¦ = 9.6 ππ when π₯ = 8 π. 9.6 = π β 8 9.6 π= = 1.2 ππ π 8 Example: Loaded Spring Use the equation, π¦ = 1.2π₯ to find π₯ when π¦ = 6. b. Substitute π¦ = 6 ππ, 6 = 1.2π₯ 6 π₯= =5π 1.2 Equality of Ratios The graph of π¦ = ππ₯ is a straight line that passes through the origin with slope m. π₯2 , π¦2 π₯1 , π¦1 O If neither π₯1 nor π₯2 is zero, then π¦1 π₯1 =π Therefore and π¦2 π₯2 =π π¦1 π₯1 π¦2 π₯2 = Proportion Such an equality of ratios is called a proportion. In a direct variation, y is often said to be directly proportional to x. The constant of variation, m, is called the constant of proportionality. Proportions The proportion is sometimes written, means π¦1 : π₯1 = π¦2 : π₯2 This is read, βπ¦1 is to π₯1 as π¦2 is to π₯2 β Proportions The equation for a proportion is, π¦1 π¦2 = π₯1 π₯2 If we multiply both sides by π₯1 π₯2 we get, π¦1 π₯2 = π¦2 π₯1 In any proportion, the product of the extremes equals the product of the means. Example: Direct Proportionality The electrical resistance in Ohms (ο) of a wire is directly proportional to its length: π 1 π1 = π 2 π2 , Where R is the resistance and l is the length. If a wire 110 cm long has a resistance of 7.5 ο, what length wire will have a resistance of 12 ο? Electrical Resistance Let l be the required length in centimeters. Then 7.5 12 = 110 π Solving for l gives, 110 π= 12 = 176 7.5 The wireβs length is 176 cm. Nonlinear Direct Variations An important equation is physics is, πΈ= 1 ππ£ 2 , 2 where E is energy, m is mass, and v is velocity, E is said to vary directly as m and directly as v2. Nonlinear Direct Variations The period of a pendulum is given by, π= 2π π π, where ο΄ is period, π is acceleration due to gravity, and l is length of the pendulum. The period (ο΄)is said to vary directly as the square root of the length π . Class work: Page 354, Oral Exercises 5-12 Homework: Page 356, Problems 1-19 odd Page 357: Mixed Review
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