Solutions - Fanny Dos Reis

Differential Equations
Math 308, Spring 2013
Texas A&M University
c
!2013,
Dr. F. Dos Reis
Week-in-review 4 – Sections 3.1, 3.3
Exercise 1. Find the solution of the given differential equations
1. 4y !! − 9y = 0.
2. y !! + 3y ! + 2y = 0.
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Differential Equations
Math 308, Spring 2013
Texas A&M University
c
!2013,
Dr. F. Dos Reis
3. y !! − 2y ! + 2y = 0.
4. 9y !! + 4y = 0.
2
Differential Equations
Math 308, Spring 2013
Texas A&M University
c
!2013,
Dr. F. Dos Reis
Exercise 2. Find the solution to the given initial value problem. Sketch the graph of the
solution and describe its behavior for increasing t.
1. y !! + 4y ! + 3y = 0,
2. y !! + 8y ! − 9y = 0
y(0) = 2,
y(1) = 1,
y ! (0) = −1.
y ! (1) = 0.
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Differential Equations
Math 308, Spring 2013
3. y !! + 4y = 0,
Texas A&M University
c
!2013,
Dr. F. Dos Reis
y(0) = 0,
4. y !! − 2y ! + 5y = 0
y ! (0) = 1.
y(π/2) = 0,
y ! (π/2) = 2.
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Differential Equations
Math 308, Spring 2013
Texas A&M University
c
!2013,
Dr. F. Dos Reis
Exercise 3. Solve the initial value problem
y !! − y ! − 2y = 0,
y(0) = α,
Find α so that the solution approaches zero as t → ∞.
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y ! (0) = 2.
Differential Equations
Math 308, Spring 2013
Texas A&M University
c
!2013,
Dr. F. Dos Reis
Exercise 4. Determine the value α, if any, for which all (non zero) solutions tend to zero
as t → ∞; also determine the vales of α, if any, for which all (non zero) solutions become
unbounded as t → ∞.
y !! + (3 − α)y ! − 2(α − 1)y = 0
6
Differential Equations
Math 308, Spring 2013
Texas A&M University
c
!2013,
Dr. F. Dos Reis
Exercise 5. Consider the initial value problem
2y !! + 3y ! − 2y = 0,
y(0) = 1,
y ! (0) = −b
where b > 0.
1. Solve the initial value problem.
2. Plot the solution for b = 1. Find the coordinates (t0 , y0 ) of the minimum point of the
solution in this case.
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Differential Equations
Math 308, Spring 2013
Texas A&M University
c
!2013,
Dr. F. Dos Reis
3. Find the smallest value of b for which the solution has no minimum point.
Exercise 6. Consider the initial value problem
3u!! − u! + 2u = 0,
u(0) = 2,
1. Find the solution u(t) of this problem.
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u! (0) = 0.
Differential Equations
Math 308, Spring 2013
Texas A&M University
c
!2013,
Dr. F. Dos Reis
2. For t > 0, find the first time at which |u(t)| = 10.
3. Find the smallest value of t for which y = 0.
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