Unit 5 Notes 5A I can apply all operations on monomials and polynomials. Properties of Exponents: xm • xn = ________________ (xm)n = _________________ (xy)m = ___________________ x-‐m = ____________________ ! ! !! =___________________ !! x0 = __________________ ! ! =___________________ Simplify each expression: 1) (4x2 – 5x + 6) – (3x – 1) ! !! ! ! ! ! 2) (6x4 – 7x + 8) + (-4x3 + 9x -5) −2 4) (2a – b)(4a + b)(3b – 5) 5) = ___________________ _________________ 3) (x – 4) (x2 + 4x + 16) 3 4x y 5 −6 32x y 6) (𝑥 ! + 𝑦 ! )(𝑥 ! − 𝑦 ! ) 4x y 9) 5 −6 32x y 3 −2 3 2 −2 7). (2a )(3a b )(c ) ⎛ −2a 4 ⎞ ⎜ b 2 ⎟⎠ 8) ⎝ −2 3 10) Simplify 6x 4 y 3 + 12x 3 y 2 − 18x 2 y 11) (18x2y + 27x3y2z) (3xy)-‐1 3xy 5B I can divide polynomials using long division and synthetic division. Ex. 1: Use long division to find each quotient: 2x 3 + 6x + 152 x+4 B) A) (x + 3x − 40) ÷ (x − 3) Example 2: Use Synthetic division to find each quotient: 3 2 4 3 A) 2x − 13x + 26x − 24 ÷ ( x − 4 ) B) 6b − 8b + 12b − 14 ÷ ( b − 2 ) 2 ( ) ( ) 5C I can describe features of a polynomial graph. Degree of Polynomial: highest exponent The degree of a polynomial tells how many ROOTS/SOLUTIONS the function has. Leading Coefficient: The coefficient of the term with the highest exponent. The degree of a polynomial has important implications for how the graph of the function will look Create a graph of a polynomial function with the given constraints (Consider the End Behavior, and how many roots the equation could have) -10 8 8 6 6 4 4 2 2 -5 5 10 -10 -5 5 -2 -2 -4 -4 -6 -6 -8 -8 10 Relative Maximum/Minimum: Turning Point: Any place where the graph curves. Maximum # of Turning Points= Degree-1. (If degree is 5 the graph could have at most 4 turning points. Graph a polynomial with degree 6, relative Max of 4, relative Min of -2, and 4 real zeros Graph a polynomial with degree 5, relative Max of 5, relative Min of 3, and 1 real zero 8 4 4 2 2 2 5 -2 -4 -6 -8 Describe the end behavior of the graph: 6 6 4 -5 8 8 6 -10 Graph a polynomial with degree 7, relative Max of 2, relative Min of -6, and 5 real zeros 10 -10 -5 5 -2 -4 -6 -8 Describe the end behavior of the graph: 10 -10 -5 5 -2 -4 -6 -8 Describe the end behavior of the graph: 10 5D I can solve polynomial equations by factoring. Factoring Techniques-LEARN THESE!!!!!!! # of Terms Factoring Technique GCF – What can I factor Any Number out of each term? 2 3 General Case Example 2𝑥 ! + 3𝑥 ! =𝑥 ! (2+3x) 8𝑥 ! + 4𝑥 ! − 2𝑥 ! = 2𝑥 ! (4𝑥 ! +2x-1) Difference of Squares 𝑎! − 𝑏 ! = (𝑎 + 𝑏)(𝑎 − 𝑏) 𝑥 ! − 25 = (𝑥 + 5)(𝑥 − 5) Difference of Cubes 𝑎! − 𝑏! = (𝑎 − 𝑏)(𝑎! + 𝑎𝑏 + 𝑏 ! ) 𝑥 ! − 27 = (𝑥 − 3)(𝑥 ! + 3𝑥 + 9) Sum of Cubes 𝑎! + 𝑏! = (𝑎 + 𝑏)(𝑎! − 𝑎𝑏 + 𝑏 ! ) 𝑥 ! + 64 = (𝑥 + 4)(𝑥 ! − 4𝑥 + 16) 𝑥 ! + 6𝑥 + 9 = (𝑥 + 3)! 𝑥 ! + 12𝑥 + 36 = 𝑥 + 6 𝑥 ! − 8𝑥 + 16 = (𝑥 − 4)! 𝑎𝑥 + 𝑏𝑥 + 𝑎𝑦 + 𝑏𝑦 = 𝑥 ! − 10𝑥 + 25 = (𝑥 − 5)! 4𝑥 + 16𝑥𝑧 + 3𝑦 + 12𝑦𝑧 = 𝑥 𝑎+𝑏 +𝑦 𝑎+𝑏 = 4𝑥 1 + 𝑧 + 3𝑦 1 + 𝑧 = (𝑥 + 𝑦)(𝑎 + 𝑏) (4𝑥 + 3𝑦)(1 + 𝑧) Perfect Square Trinomials ! Grouping 4 OR MORE Example 1: Factor each polynomial. If the polynomial cannot be factored, write prime. A) x6 – y6 B) a3x2 – 6a3x + 9a3 – b3x2 + 6b3x - 9b3 C) a6 + b6 D) x5 + 4x4 + 4x3 + x2y3 + 4xy3 + 4y3 E) x3 + x2 – x – 1 F) 3x3 – 9x2 + 4x – 12 G) x3 + 8 I) 16x4 + 54xy3 H) 27y3 + 125 J) 9y3 + 5x3 Example 2: Solve the following equations. A) 18x4 – 21x2 + 3 =0 B) 8x4 + 10x2 – 12 = 0 5E I can find all of the zeros of a polynomial function. Possible roots can be determined by looking at the factors of the constant term and leading coefficient, and can be written as rational fractions – these are the possible RATIONAL ROOTS. This doesn’t include irrational or complex roots that may exist: !"#$%&' !" !"#$%&#% !"#$ !"#$%&' !" !"#$%&' !"#$$%!%#&' Example 1: List all of the possible rational zeros of each function. A) f(x) = 4x5 + x4 – 2x3 -‐ 5x2 + 8x + 16 B) f(x) = x3 – 2x2 + 5x + 12 We use SYNTHETIC DIVISION to work towards identifying all of the roots. You must repeat synthetic division until you have a polynomial of degree 2 that can you can factor or use the Quadratic Formula with. Example 2: Find all of the zeros of the following functions. B) f(x) = 𝑥 ! + 9𝑥 ! + 6𝑥 − 16 A) f(x) = 2x4 – 5x3 + 20x2 – 45x + 18 C) f(x) = 5x4 – 8x3 + 41x2 – 72x – 36. D) f(x) = 5x4 – 29x3 + 55x2 – 28x
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