Hourly I (November 4) E4 Acids, Bases, and Salts Oct. 29 - Nov. 4 Review Notes • Posted on CTools and course website Session two goals Review Sessions • Saturday, Nov. 1, 10am - noon, 1800 chem. ♦ 10-10:40 am: Experiment 1 ♦ 10:40 - 11:20 am: Experiment 2 ♦ 11:20 - noon: Experiment 3 Complete E4, Parts 3 - 5. Complete the team report and discussion presentation. • Monday, Nov.3, 6 - 8 pm, 140 Lorch Hall ♦ Question and answers Acid - Base Neutralization (Parts 3 - 5) Neutralization: CH3COOH + NaOH → acid + base → CH3COONa + HOH salt + water Acid-Base Neutralization Example: CH3COOH + NaOH CH3COONa + HOH • Adding base to a weak acid drives the reaction (donation of proton/s) to completion • At neutralization, only the products (salt and water) are present. HCl(g) + NH3(g) → NH4Cl(s) DEMO Carboxylic Acids (Parts 3 - 5) Neutralization Reaction Stoichiometry Reaction stoichiometry is dependant on the number of ionizable protons. Carboxylic acids C-based weak acids containing the group Acetic acid (Part 3): CH3COOH + NaOH → CH3COONa 1 mol + HOH 1 mol Oxalic acid (Part 4): HOOC-COOH + 2 NaOH → 2COONa + 2HOH 1 mol 2 mol 1 Carboxylic Acids and Ionizable Protons Electronegativity of the elements* 1 2 3 4 5 6 7 8 IA IIA IIIB IVB VB VIB VIIB 9 VIIIB 10 11 IB Carboxylic acids 12 13 14 15 16 17 IIB IIIA IVA VA VIA VIIA H 2.1 Li Be B C N O F 1.0 1.5 2.0 2.5 3.0 3.5 4.0 Na Mg Al Si P S Cl 0.9 1.2 1.5 1.8 2.1 2.5 3.0 K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br 0.8 1.0 1.3 1.5 1.6 1.6 1.5 1.8 1.8 1.8 1.9 1.6 1.6 1.8 2.0 2.4 2.8 Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I 0.8 1.0 1.2 1.4 1.6 1.8 1.9 2.2 2.2 2.2 1.9 1.7 1.7 1.8 1.9 2.1 2.5 Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At 0.7 The0.9electronegativity H and and1.9 therefore in the -Lu 1.3 1.5 1.7 of1.9 2.2 O 2.2differ 2.2 2.4 1.8 1.8H1.9 2.0 2.2 COOH Fr Ra group Ac This ionizable. Pa U Np- N o 1.1 1.3 1.5 1.7of H and 1.3 C are similar and therefore C-H 0.7 The0.9 electronegativity • • H | O || Part 3: Acetic acid HC2H3O2 • H− C − C − O − H • | • H • • O O || || •H − O− C − C − O − H CH3COOH Carboxylic group containing one ionizable proton Part 4: Oxalic acid H2C2O4 HOOCCOOH Two carboxylic groups each with one ionizable proton = Metalloids Metals bonds are stable and= Nonmetals H in the C-H =bond is NOT ionizable Q. How many mL of 0.10 M NaOH will be required to neutralize 5.0 mL of 0.10 M oxalic acid? Titration (Parts 3 -5) Oxalic acid HOOC-COOH + 2 NaOH → 2COONa + 2HOH • 2 mol of NaOH is required to neutralize one mol of oxalic acid: 2 (mmol acid) = mmol base 2 (5.0 mL • 0.10 M) = x mL • 0.10 M = 10 mL of 0.10 M NaOH DEMO Part 3 Acid-Base Neutralizations and Indicators Base delivered from burette Indicator color change signals the end-point or neutralization Titration (Parts 3) Compare the use of indicators for monitoring the neutralization of acetic acid with sodium hydroxide Experiment variable: • Indicators Experiment constants • Acid identity, concentration, and volume • Base identity and concentration DEMO 2 Indicator pH End Points Indicator End Point pH The pH interval at which the indicator changes color Acids are colorless Bases are pink Phenolphthalein: pH 8.2 - pH 10.1 ↑ pH 9.1 The indicator color change is observable at the mid-point of the end point pH range. Indicators have different end-point pH color changes For information on lab indicators, see the lab manual, p. 194 Equivalence Point pH Titration and Indicator pH End Points The pH of the salt and water products of the acid-base neutralization reaction = the equivalence point pH. CH3COOH + NaOH → CH3COONa + HOH Equivalence point pH ≈ pH 8 “Ideally, the indicator end point pH equals the equivalence point pH = pH 8. “ DEMO Part 5. Identification of an Unknown Acid • Identify a carboxylic acid from melting point and equivalent weight data • The melting point range will be determined using a melting point apparatus • The equivalent weight will be determined by titrating a known mass of the acid with NaOH See Table, p.118 Name 2-hydroxybenzoic acid acetate Formula COOH MW EW MP 180 180 135 OCOCH3 trans-cinnamic acid CH CH COOH Cl 2-chlorobenzoic acid 148 148 135136 157 157 140 COOH cis-butenedioic (maleic) acid H HOOC H COOH 116 58 139140 3 Part 5. Identification of an Unknown Acid • • • Practice melting point and equivalent weight skills with known compounds BEFORE attempting to identify the unknown Determine the approximate range of the unknown’s melting point (e.g., 110 -130ºC) BEFORE determining the actual melting point range. Note: Unknown melting points 99°C - 200°C Equivalent Weight (EW) Mass (grams) of compound providing one mole of H+ EW = Molecular Wt/# ionizable protons Examples: H2SO4 = molecular weight of 98 H2SO4 = equivalent weight of 49 Determine the approximate volume of NaOH needed to neutralize the unknown acid BEFORE determining the volume quantitatively EW of Oxalic Acid (Part 4) Q. What is the equivalent weight of oxalic acid? Oxalic acid: MW = 90.04 HOOC-COOH + 2 NaOH → 2COONa + 2HOH 0.5 mol 1 mol 45.02 g HCl = molecular weight of 36.5 HCl = equivalent weight of 36.5 Carboxylic Acid Structure and Equivalent Weight Benzoic acid • • • • • COOH One ionizable proton. 1 mol (or 1000 mmol) Benzoic acid = C 6 H5COOH MW = EW No ionizable protons. Not an acid. • O H H H H O Adipic acid • || | | | | || HOOC(CH 2 )4COOH H-O−C−C−C−C−C−C−O−H • | | | | • H H H H Two ionizable protons. Molecular Weight = 146 73 Equivalent weight = _____________? Q. An acid has an equivalent weight (EW) of 88.92. The EW = molecular wt/#ionizable protons. List the number of any compound from the table that may be the acid. 1. 2. 3. 4. Compound Ethanoic acid Butanoic acid Oxalic acid 1-methyl, 1,2 benzene dicarboxylic acid Formula CH3COOH CH3CH2CH2COOH HOOC-COOH CH3C6H3(COOH)2 MW 60 88 90 180 Answer. Compounds # 2 and # 4. 4 A teammate titrates a carboxylic acid and calculates the EW of the acid to be 72.50. The result is correct within 2%. The MW of the acid = 1.5 x 102 A. How many ionizable protons/mol are in the acid?that EW from Experiment Data Determine the equivalent weight of an unidentified carboxylic acid by titration • Let X = # ionizable protons. EW = 72.50 = MW/X = 150/X X= ~ 2 B. Circle each structure that is consistent with the data. Adipic Acid, MW = 146: HO2CCH 2CH2CH2CH2CO2H Trans-cinnamic acid, MW=148 -CH=CH-COOH Citric Acid, MW = 192: HO2C-CH2-C(OH)-CH 2-CO2H CO 2H • EW = Mass (g) of acid providing 1 mol H+ or neutralizing 1 mol OH-. EW = mass acid (g) moles of OH- neutralized Oxalic acid, MW = 90 HO 2C—CO2H EW from Experiment Data (Part 5) EW of Oxalic Acid (Part 4) Determine the EW of an acid by titration Q. 10.0 mL of 1.0 M NaOH neutralizes 0.4502 grams of an unknown acid. What is the equivalent weight of the acid? Answer. Fact: 0.4502 g neutralized 10.0 mmol of NaOH. The mass of acid needed to neutralize 1 mol = 45.02g = EW Q. You titrate 0.175 g of an acid. 30.00 mL of 0.10 M NaOH neutralizes the sample. 1) What is the acid’s EW based on the data? 2) Identify the acid from the list below. Name 2-hydroxybenzoic acid acetate Formula COOH OCOCH3 trans-cinnamic acid CH CH COOH 2-chlorobenzoic acid cis-butenedioic (maleic) acid Cl H HOOC COOH H MW 180 MP 135 148 135-136 157 140 116 139-140 Equivalent weight determination. 1) Determine mol of NaOH the acid has neutralized. Fact: The acid mass neutralized 30.00 mL of 0.10 M NaOH mol OH- = V(L) x M NaOH = 0.0300L x 0.10 mol L = 3.0 x 10-3 mol COOH 5 Equivalent Weight determination. 2) Determine the mass of acid that would neutralize one mol of hydroxide ions. Known: 0.175 g X g acid = 0.0030 mol OH1 mol OH- X = 58 g Q. What is the identity of the acid? Name 2-hydroxybenzoic acid acetate Formula COOH OCOCH3 trans-cinnamic acid CH CH COOH 2-chlorobenzoic acid cis-butenedioic (maleic) acid √ Cl H HOOC COOH H MW 180 MP 135 148 135-136 157 140 116 139-140 COOH Questions? Contact [email protected] 6
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