Titration
Objectives: define titration, use stoichiometry to calculate the molarity from titration data
 Define titration-
the slow addition of one substance to another in
stoichiometric quantities as determined by an EQUIVALENCE POINT (or
ENDPOINT)
Define endpoint (equivalence) – moles
of acid are equal to moles of base according to
the coefficients of the balanced chemical equation.
This can be determined either by using:
indicator or pH sensor
Make the following connections: balanced neutralization equations, molarity, substance A and
substance B, factor label procedure
Example #1
If you neutralize 10.0 ml of hydrochloric acid with 25.72 ml of .15M sodium hydroxide, what is the
molarity of the acid?
HCl + NaOH  NaCl + H2O
25.72 ml NaOHx
1L
.15 moles 1 mole HCl
x
x
 .003858 mole HCl
1000ml
1L
1 mole NaOH
.003858 mole 1000ml
x
 .3858 M
10.0 ml
1L
Example #2
Calculate the molarity of sulfuric acid if 35.0 ml of it is titrated with 57.24 ml of .25M sodium
hydroxide.
How can I use factor label to solve for quantities involved in chemical changes?
T. O’Toole
Example #3 Using a pH sensor and resulting
graph:
Find the largest pH jump then average the volumes. This gives you 30.3 ml.
Calculate the percent acetic acid in vinegar if 3.59 grams is titrated with .1M sodium hydroxide to the
endpoint determined from the graph and data table.
HC2H3O2 + NaOH  NaC2H3O2 + H2O
30.3mlx
.1moleA 1moleB 60.0 g
x
x
 .1818 g / 3.59 g  5 0 0
1000 ml 1moleA 1moleB
Minute Paper-Order the steps to determine the molarity of an unknown from titration data
How can I use factor label to solve for quantities involved in chemical changes?
T. O’Toole
How do I get from where I am to where I’m going?
10 Minute Makeover

Complete the appropriate section on the Portfolio Page

Review the PPT file on the website

Read pages 615-618 in the book

Extra practice problem: page 618 #3 –answer in Appendix C

Complete the SYS Assignment

Review the skills from today’s Train Your Brain
How can I use factor label to solve for quantities involved in chemical changes?
T. O’Toole