College Algebra Chapter 4, section 5 Created by Lauren Atkinson Mary Stangler Center for Academic Success This review is meant to highlight basic concepts from Chapter 4. It does not cover all concepts presented by your instructor. Refer back to your notes, handouts, the book, MyMathLab, etc. for further prepare for your exam. 4.5: The Fundamental Theorem of Algebra • This section covers: – The Fundamental Theorem of Algebra – The Number of Zeros Theorem – Complex zeros The Fundamental Theorem of Algebra • A polynomial function with degree of 1 or larger, has at least one complex zero. Degree of polynomials= number of real zeros + number of complex zeros • Real Zero= graph either hits or crosses through the x-axis • Complex zero= graph doesn’t hit or cross through the x-axis f ( x) ( x 2) 3 2 All of these functions have a degree of 2, therefore they, at most, have 2 zeros. This graph doesn’t touch the x-axis or cross it at all, therefore it has 2 imaginary zeros (0 real zeros) f ( x) ( x 2) 2 This graph bounces off the xaxis, therefore it has 1 real zero and one imaginary zero f ( x) ( x 2) 2 4 This graph touches the x-axis twice, therefore it has 2 real zeros (0 imaginary zeros) Number of Zeros Theorem • A polynomial of degree n has at most n distinct zeros (x-intercepts, factors) • Examples: Find the complete factored form of a polynomial with real coefficients 𝑓(𝑥) that satisfies the conditions: Degree 4; 𝑎𝑛 = 10; zeros 1,-1,3𝑖, −3𝑖 Degree 2; 𝑎𝑛 = -5; zeros 1 + 𝑖, 1 − 𝑖 = 10(𝑥 − 1)(𝑥 + 1)(𝑥 − 3𝑖)(𝑥 + 3𝑖) = −5 𝑥 − 1 + 𝑖 𝑥− 1−𝑖 = −5(𝑥 − 1 − 𝑖)(𝑥 − 1 + 𝑖) Complex Zeros: • It is true that if 𝑎 + 𝑏𝑖 is a zero, then the conjugate (𝑎 − 𝑏𝑖) is also a zero. • Examples: If one zero is −2𝑖 then another zero (by default) is 2𝑖. Similarly, if one zero is 1 + 3𝑖 then another zero is − 1 + 3𝑖 = −1 − 3𝑖 Additional Examples: Find all zeros of 𝑓 𝑥 : 𝑓 𝑥 = 3𝑥 3 + 3𝑥 = 3𝑥 𝑥 2 + 1 = 3𝑥 𝑥 + 𝑖 𝑥 − 𝑖 Zeros=0, ±𝑖 𝑓 𝑥 = 𝑥 3 + 2𝑥 2 + 16𝑥 + 32 = 𝑥 2 𝑥 + 2 + 16 𝑥 + 2 = 𝑥 + 2 𝑥 2 + 16 = (𝑥 + 2)(𝑥 + 4𝑖)(𝑥 − 4𝑖) Zeros= −2, ±4𝑖 The whole point … • The sections we have covered so far are supposed to prepare you to solve all equations, which is why a majority of the problems in section 4.5 ask you to solve polynomial equations. Examples: Solve: 𝑥 3 = 2𝑥 2 − 7𝑥 + 14 𝑥 3 − 2𝑥 2 + 7𝑥 − 14 = 0 𝑥2 𝑥 − 2 + 7 𝑥 − 2 = 0 𝑥 − 2 𝑥2 + 7 = 0 𝑥 = 2, ±𝑖 7 Solve: 𝑥 4 − 2𝑥 3 + 𝑥 2 − 2𝑥 = 0 𝑥 3 𝑥 − 2 + 𝑥(𝑥 − 2) = 0 (𝑥 3 + 𝑥) 𝑥 − 2 = 0 𝑥 𝑥2 + 1 𝑥 − 2 = 0 𝑥 𝑥+𝑖 𝑥−𝑖 𝑥−2 =0 𝑥 = 0, ±𝑖, 2
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