Academic Skills Advice Linear Equations Summary Solving Linear Equations: When solving a linear equation you are trying to find the value of the letter in the equation. To do this you need to make the letter the subject of the equation. Example: ο· Solve the equation: 6(2π + 13) = β9(π + 3) (Do this by collecting πβs at one side and numbers at the other.) Starting Equation: Multiply out the brackets: Take 78 from each side: Tidy up: Add 9Q to each side: Tidy up: 6(2π + 13) 12π + 78 12π + 78 β 78 12π 12π + 9π 21π = = = = = = β9(π + 3) β9π β 27 β9π β 27 β 78 β9π β 105 β9π β 105 + 9π β105 Divide each side by 21 to leave βQβ on its own: 21π 21 = β105 21 Simplify and tidy up: π = β5 A quick method: When something crosses to the other side of the equals sign it does the opposite. E.g. + becomes -, x becomes ÷ and vice versa. Example: ο· Solve the equation: 5(3π + 4) β 3(4π β 5) = 41 Starting Equation: Multiply out the brackets Collect like terms (kβs and numbers): +35 crosses the β=β sign and becomes -35: Tidy up: 3 crosses the β=β sign and divides Tidy up: H Jackson 2011/2014 / Academic Skills 5(3π + 4) β 3(4π β 5) 15π + 20β 12π + 15 3π + 35 3π 3π π = = = = = = π = Except where otherwise noted, this work is licensed under http://creativecommons.org/licenses/by-nc-sa/3.0/ 41 41 41 41 β 35 6 6 3 2 1
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