Linear Equations Summary

Academic Skills Advice
Linear Equations Summary
Solving Linear Equations:
When solving a linear equation you are trying to find the value of the letter in the equation.
To do this you need to make the letter the subject of the equation.
Example:
ο‚·
Solve the equation: 6(2𝑄 + 13) = βˆ’9(𝑄 + 3)
(Do this by collecting 𝑄’s at one side and numbers at the other.)
Starting Equation:
Multiply out the brackets:
Take 78 from each side:
Tidy up:
Add 9Q to each side:
Tidy up:
6(2𝑄 + 13)
12𝑄 + 78
12𝑄 + 78 βˆ’ 78
12𝑄
12𝑄 + 9𝑄
21𝑄
=
=
=
=
=
=
βˆ’9(𝑄 + 3)
βˆ’9𝑄 βˆ’ 27
βˆ’9𝑄 βˆ’ 27 βˆ’ 78
βˆ’9𝑄 βˆ’ 105
βˆ’9𝑄 βˆ’ 105 + 9𝑄
βˆ’105
Divide each side by 21 to leave β€˜Q’
on its own:
21𝑄
21
=
βˆ’105
21
Simplify and tidy up:
𝑄
=
βˆ’5
A quick method:
When something crosses to the other side of the equals sign it does the opposite.
E.g. + becomes -, x becomes ÷ and vice versa.
Example:
ο‚·
Solve the equation: 5(3π‘˜ + 4) βˆ’ 3(4π‘˜ βˆ’ 5) = 41
Starting Equation:
Multiply out the brackets
Collect like terms (k’s and numbers):
+35 crosses the β€œ=” sign and becomes -35:
Tidy up:
3 crosses the β€œ=” sign and divides
Tidy up:
H Jackson 2011/2014 / Academic Skills
5(3π‘˜ + 4) βˆ’ 3(4π‘˜ βˆ’ 5)
15π‘˜ + 20– 12π‘˜ + 15
3π‘˜ + 35
3π‘˜
3π‘˜
π‘˜
=
=
=
=
=
=
π‘˜ =
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41
41
41
41 βˆ’ 35
6
6
3
2
1