Algebra Review β Homework Answer Key
Math 140 β Prof. Beydler
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Homework Answer Key
2
1. Find an equation of the line through (0, β4) with slope 3. Then rewrite the equation in slopeintercept form. Finally, graph the line.
π
π + π = π (π β π) (This is point-slope form.)
π
π = π π β π (This is slope-intercept form.)
2. Find an equation of the line through (2, 5) with slope β1. Then rewrite the equation in slopeintercept form. Finally, graph the line.
π β π = βπ(π β π) (This is point-slope form.)
π = βπ + π (This is slope-intercept form.)
1
2
3. Find an equation of the line through (β1, 2) and (0 , β 3). Then rewrite the equation in slopeintercept form.
π
π
π β π = β π (π + π)
π
π
π = βππ β π
π
π
(This is point-slope form. You could also write π + π = β π (π β π).)
(This is slope-intercept form.)
4. Graph the line π₯ = β2. What is the slope of the line?
The slope is undefined.
Math 140
Algebra Review β Homework Answer Key
5. Graph the line π¦ = 6. What is the slope of the line?
The slope is 0.
6. Write an equation for the following line. What is the slope of the line?
Equation: π = π
Slope: π
7. Graph π (π₯ ) = π₯ 2 β 2 by finding and plotting the vertex, π₯-intercepts, and π¦-intercept.
Vertex: (π, βπ)
π-intercepts: (βπ, π) and (ββπ, π)
π-intercept: (π, βπ)
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Algebra Review β Homework Answer Key
Math 140
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8. Graph π (π₯ ) = 2π₯ 2 + 4π₯ β 6 by finding and plotting the vertex, π₯-intercepts, and π¦-intercept.
Vertex: (βπ, βπ)
π-intercepts: (βπ, π) and (π, π)
π-intercept: (π, βπ)
1 β 3π₯ if π₯ β€ 4
2
. Find π(8), π(0), and π(β1).
if π₯ > 4
π₯
π(π) = π π(βπ) = π
9. Suppose π (π₯ ) = {
π
π (π) = π
βπ₯ + 14 if π₯ < β6
10. Suppose π (π₯ ) = { 2π₯ 2 + 1 if β 6 β€ π₯ β€ β1. Find π(β10), π(β6), π (β1), π (0), and π (27).
3
if π₯ > β1
βπ₯
π(βππ) = π
π(βπ) = ππ
π(βπ) = π
π (π) = π
π(ππ) = π
11. Find π(π₯ + 1) where π (π₯ ) = π₯ 2 β 3π₯ + 2. Simplify.
π (π + π) = π π β π
π₯
12. Find π(π₯ + β) where π (π₯ ) = π₯+1.
π+π
π(π + π) = π+π+π
13. Find
π(π₯+β)βπ(π₯)
β
π(π+π)βπ(π)
π
14. Find
=π
π(π₯+β)βπ(π₯)
β
π(π+π)βπ(π)
π
where π (π₯ ) = 2π₯ β 3. Simplify.
where π (π₯ ) = π₯ 2 . Simplify.
= ππ + π
π₯+1
15. Find the domain of π (π₯ ) = π₯2 βπ₯β2.
All real numbers except -1 and 2.
16. Find the domain of π (π₯ ) = β6 β 2π₯.
All real numbers such that π β€ π.
17. Find the domain of π (π₯ ) =
π₯β1
βπ₯+2
.
All real numbers such that π > βπ.
Algebra Review β Homework Answer Key
Math 140
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18. Factor completely.
a) 3π₯ 4 + 4π₯ 3
ππ (ππ + π)
b) 12π₯ 2 + 36π₯ β 48
ππ(π β π)(π + π)
c) 6π₯ 2 + 6π₯ β 12
π(π β π)(π + π)
d) π₯ 2 β 2π₯ + 1
(π β π)π
e) 4π₯ 2 β 9
(ππ β π)(ππ + π)
f) π₯ 3 β 4π₯ 2 β 3π₯ + 12
(π β π)(ππ β π)
19. Rewrite the following using rational exponents.
π
a) βπ₯ = ππ
5
e) π₯2 = ππ
βπ
π
4
b) βπ₯ = ππ
1
f) π₯5 = π
βπ
g)
1
βπ₯
20. Rewrite the following using radicals or fractions.
1
π
a) π₯ 3 = βπ
π
e) π₯ β3 = ππ
3
π
b) π₯ 4 = βππ
2
f) π₯ β3 =
π
5
c) βπ₯ 2 = ππ
=π
π
π
3
d) = ππβπ
π₯
β
1
c) π₯ 2 = βπ
π
π
d) 4π₯ β1 = π
π
βπ π
21. Suppose the demand function for π₯ hundred units of a textbook is:
π·(π₯ ) = β0.37π₯ + 47 (in dollars)
and the cost of producing π₯ hundred textbooks is:
πΆ (π₯ ) = 1.38π₯ 2 + 15.15π₯ + 115.5 (in hundreds of dollars).
Find the revenue π
(π₯ ) and profit π (π₯ ).
πΉ(π) = βπ. ππππ + πππ
π·(π) = βπ. ππππ + ππ. πππ β πππ. π
22. Suppose that when the price of a water bottle is π dollars per unit, then π₯ thousand units will be
purchased by consumers, where π = β0.01π₯ + 4. The cost of producing π₯ thousand bottles is
πΆ (π₯ ) = 0.005π₯ 2 + π₯ + 120 thousand dollars.
a) Find the profit function, π(π₯). (Notice that big π and little π mean two different things. Like
passwords, math is case sensitive! ο)
π·(π) = βπ. πππππ + ππ β πππ
b) Using π(π₯), determine the level of production π₯ that results in maximum profit.
π = πππ thousand bottles = πππ, πππ bottles
Math 140
Algebra Review β Homework Answer Key
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c) What unit price π corresponds to maximum profit?
π = $π per bottle
23. You start a company that produces mechanical pencils whose lead does not break while writing.
Your total cost consists of a fixed overhead of $6000 plus production costs of $5 per pencil.
a) Find the total cost function πΆ(π₯), where π₯ is the number of pencils produced.
πͺ(π) = ππππ + ππ
b) Sketch the graph of πΆ(π₯).
24. Youβre in the cut-throat iPhone case business. You estimate that you can sell a case for $2 more
than it costs to produce it. Your fixed costs are $11500.
a) Express total profit π(π₯) as a function of the level of production π₯ (that is, π₯ represents the
number of cases produced).
π·(π) = ππ β πππππ
b) How much profit (or loss) is generated when 5000 cases are produced?
π·(ππππ) = β$ππππ (loss)
c) What is the level of production at the break-even point? (Hint: Recall that the break-even
point occurs when π
(π₯ ) = πΆ (π₯ ). Equivalently, it happens when π(π₯ ) = 0.)
π = ππππ cases
25. Suppose the supply and demand functions are π(π₯ ) = 4π₯ + 200 and π· (π₯ ) = β3π₯ + 480,
respectively. Find the value of π₯π for which equilibrium occurs and the corresponding equilibrium
price ππ .
ππ = ππ and ππ = πππ
                
    
            
    
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