Midpoint Formula Andrew Gloag Eve Rawley Anne Gloag Say Thanks to the Authors Click http://www.ck12.org/saythanks (No sign in required) To access a customizable version of this book, as well as other interactive content, visit www.ck12.org CK-12 Foundation is a non-profit organization with a mission to reduce the cost of textbook materials for the K-12 market both in the U.S. and worldwide. Using an open-content, web-based collaborative model termed the FlexBook®, CK-12 intends to pioneer the generation and distribution of high-quality educational content that will serve both as core text as well as provide an adaptive environment for learning, powered through the FlexBook Platform®. Copyright © 2014 CK-12 Foundation, www.ck12.org The names “CK-12” and “CK12” and associated logos and the terms “FlexBook®” and “FlexBook Platform®” (collectively “CK-12 Marks”) are trademarks and service marks of CK-12 Foundation and are protected by federal, state, and international laws. Any form of reproduction of this book in any format or medium, in whole or in sections must include the referral attribution link http://www.ck12.org/saythanks (placed in a visible location) in addition to the following terms. Except as otherwise noted, all CK-12 Content (including CK-12 Curriculum Material) is made available to Users in accordance with the Creative Commons Attribution-Non-Commercial 3.0 Unported (CC BY-NC 3.0) License (http://creativecommons.org/ licenses/by-nc/3.0/), as amended and updated by Creative Commons from time to time (the “CC License”), which is incorporated herein by this reference. Complete terms can be found at http://www.ck12.org/terms. Printed: September 29, 2014 AUTHORS Andrew Gloag Eve Rawley Anne Gloag www.ck12.org C HAPTER Chapter 1. Midpoint Formula 1 Midpoint Formula Here you’ll learn how to use the midpoint formula to find the coordinates of the point that is in the middle of the line segment connecting two given points. You’ll also use that formula to find one endpoint of a line segment given its other endpoint and its midpoint. What if you were given the coordinates of two points like (4, 1) and (0, -3)? How could you find the midpoint of the line segment joining the two points? After completing this Concept, you’ll be able to find the midpoint of any line segment using the Midpoint Formula. Watch This MEDIA Click image to the left for use the URL below. URL: http://www.ck12.org/flx/render/embeddedobject/133290 CK-12 Foundation: The Midpoint Formula For a graphic demonstration of the midpoint formula, watch this video: MEDIA Click image to the left for use the URL below. URL: http://www.ck12.org/flx/render/embeddedobject/860 PatrickJMT: The Midpoint Formula Guidance In the last concept, you saw how to find the distance between two points. In this concept, you will learn how to find the point exactly half way between two points. Example A Find the coordinates of the point that is in the middle of the line segment connecting the points A = (−7, −2) and B = (3, −8). Solution Let’s start by graphing the two points: 1 www.ck12.org We see that to get from point A to point B we move 6 units down and 10 units to the right. In order to get to the point that is halfway between the two points, it makes sense that we should move half the vertical distance and half the horizontal distance—that is, 3 units down and 5 units to the right from point A. The midpoint is M = (−7 + 5, −2 − 3) = (−2, −5). The Midpoint Formula We now want to generalize this method in order to find a formula for the midpoint of a line segment. Let’s take two general points A = (x1 , y1 ) and B = (x2 , y2 ) and mark them on the coordinate plane: We see that to get from A to B, we move x2 − x1 units to the right and y2 − y1 units up. 1 In order to get to the half-way point, we need to move x2 −x units to the right and 2 y −y x2 −x1 2 1 midpoint M is at x1 + 2 , y1 + 2 . 2 y1 +y2 This simplifies to M = x1 +x . This is the Midpoint Formula: 2 , 2 The midpoint of the line segment connecting the points (x1 , y1 ) and (x2 , y2 ) is 2 y2 −y1 2 up from point A. Thus the x1 +x2 y1 +y2 . 2 , 2 www.ck12.org Chapter 1. Midpoint Formula It should hopefully make sense that the midpoint of a line is found by taking the average values of the x and y−values of the endpoints. Example B Find the midpoint between the following points. a) (-10, 2) and (3, 5) b) (3, 6) and (7, 6) Solution x1 +x2 y1 +y2 2 , 2 2+5 5) is −10+3 2 , 2 Let’s apply the Midpoint Formula: a) the midpoint of (-10, 2) and (3, b) the midpoint of (3, 6) and (7, 6) is 3+7 2 , 2 6+6 = −7 7 2 ,2 = 12 10 2, 2 = (−3.5, 3.5) = (5, 6) Example C A line segment whose midpoint is (2, -6) has an endpoint of (9, -2). What is the other endpoint? Solution In this problem we know the midpoint and we are looking for the missing endpoint. The midpoint is (2, -6). One endpoint is (x1 , x2 ) = (9, −2). Let’s call the missing point (x, y). We know that the x−coordinate of the midpoint is 2, so: 2 = 9+x2 2 ⇒ 4 = 9 + x2 ⇒ x2 = −5 We know that the y−coordinate of the midpoint is -6, so: −6 = −2 + y2 ⇒ −12 = −2 + y2 ⇒ y2 = −10 2 The missing endpoint is (-5, -10). Here’s another way to look at this problem: To get from the endpoint (9, -2) to the midpoint (2, -6), we had to go 7 units left and 4 units down. To get from the midpoint to the other endpoint, then, we would need to go 7 more units left and 4 more units down, which takes us to (-5, -10). Watch this video for help with the Examples above. MEDIA Click image to the left for use the URL below. URL: http://www.ck12.org/flx/render/embeddedobject/133291 CK-12 Foundation: The Midpoint Formula 3 www.ck12.org Vocabulary • The Midpoint Formula states that the midpoint of the line segment connecting the points (x1 , y1 ) and (x2 , y2 ) is x1 +x2 y1 +y2 . 2 , 2 Guided Practice Find the midpoint between the points (4, -5) and (-4, 5). Solution Let’s apply the Midpoint Formula: The midpoint of (4, -5) and (-4, 5) x1 +x2 y1 +y2 2 , 2 −5+5 is 4−4 2 , 2 = 0 0 2, 2 = (0, 0) Explore More Find the midpoint of the line segment joining the two points. 1. 2. 3. 4. 5. 6. 7. 8. 9. (3, -4) and (6, 1) (2, -3) and (2, 4) (4, -5) and (8, 2) (1.8, -3.4) and (-0.4, 1.4) (5, -1) and (-4, 0) (10, 2) and (2, -4) (3, -3) and (2, 5) An endpoint of a line segment is (4, 5) and the midpoint of the line segment is (3, -2). Find the other endpoint. An endpoint of a line segment is (-10, -2) and the midpoint of the line segment is (0, 4). Find the other endpoint. 10. Find a point that is the same distance from (4, 5) as it is from (-2, -1), but is not the midpoint of the line segment connecting them. 4
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