What you will learn about: Functions that model patterns of change Pumpkinβ Droppinβ At Old Dominion University in Norfolk Virginia, physics students have their own flying pumpkin contest. Each year they see who can drop pumpkins on a target from 10 stories up in a tall building while listening to music by the group Smashing Pumpkins. By timing the flight of the falling pumpkins, the students can test scientific discoveries made by Galilei, nearly 400 years ago. Galileo used clever experiments to discover that gravity exerts force on any free-falling objects so that d, the distance fallen, will be related to time t by the function π = 16π‘ 2 (π‘πππ ππ π ππππππ πππ πππ π‘ππππ ππ ππππ‘). 1. Use the table to show the estimated distance the pumpkin has fallen and height above the ground in feet at various times between 0 and 3 seconds. Time t Distance Fallen d Height Above Ground h 0 0 100 0.5 4 100 - 4 = 96 1 1.5 2 2.5 3 2. Use the data relating height and time to answer the following questions about flight of a pumpkin dropped from a position 100 feet above the ground. a. What function rule shows how the pumpkinβs height h is related to t? 1|Page b. What equation can be solved to find the time when the pumpkin is 10 feet from the ground? What is your best estimate for the solution of that equation? c. What equation can be solved to find the time when the pumpkin hits the ground? What is your best estimate for the solution of that equation? 3. Suppose a pumpkin is fired straight upward from the barrel of a compressed-air cannon at a point 20 feet above the ground, at a speed of 90 feet per second (about 60 miles per hour). a. If there were no gravitational forces pulling the pumpkin back towards the ground, how would the pumpkinβs height above the ground change as time passes? b. What function rule would relate height above the ground h in feet to time in the air t in seconds? c. How would you change the function rule in part b if the pumpkinβ chunker use a stronger cannon that fired the pumpkin straight up into the air with a velocity of 120 feet per second? d. How would you change the function rule in Part b if the end of the cannon barrel was only 15 feet above the ground? 2|Page 4. Now think about how the flight of a launched pumpkin results from the combination of three factors: ο· Initial height of the pumpkinβs release ο· Initial upward velocity produced by the pumpkin-launching device, and ο· Gravity pulling the pumpkin down towards the ground. a. Suppose a compressed air cannon fires a pumpkin straight up into the air from a height of 20 feet and provides an initial upward velocity of 90 feet per second. What function rule would combine these conditions and the effect of gravity to give a relation between the pumpkinβs height h in feet and its flight time t in seconds? b. How would you change your function rule in Part a if the pumpkin is launched at a height of 15 feet with an initial upward velocity 120 feet per second? 5. By now you may have recognized that the height of a pumpkin shot straight up into the air at any time in its flight will be given by a function that can be expressed with a rule in the general form. β = β0 + π£0 π‘ β 16π‘ 2 In those functions, h is measured in feet and t in seconds. a. What does the value β0 represent? What units are used to measureβ0 ? b. What does the value π£0 represent? What units are used to measure π£0 ? 3|Page 6. The pumpkinβs height in feet t seconds after it is launched will still be given by β = β0 + π£0 π‘ β 16π‘ 2 . It is fairly easy to measure the initial height (β0 ) from which the pumpkin is launched, but it is not easy to measure the initial upward velocity ( π£0 ). a. Suppose that a pumpkin leaves a cannon at a point 24 feet above the ground when t = 0. What does that fact tell about the rule giving height h as a function of time in flight t? b. Suppose you were able to use a stopwatch to discover that the pumpkin shot descib3d in Part a returned to the ground after 6 seconds. Use that information to find the value of π£0 . 7. Suppose that you were able to use a ranging tool that records the height of a flying pumpkin every half second from the time it left a cannon. A sample of the data for one pumpkin launch appears in the following table. Time (in seconds) 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 Height (in feet) 15 40 60 70 70 65 50 30 0 a. Plot the data on a graph and experiment with several values of π£0 and β0 in search of a function that models the data pattern well. b. Use a calculator that offers quadratic curve-fitting to find a quadratic model for the sample data pattern. Compare that automatic curve-fit to what you found with your own experimentation. 4|Page c. Use the rule you found in Part b to write and solve equations and inequalities matching these questions about pumpkin shot. i. When was the pumpkin 60 feet above the ground? ii. For which time(s) was the pumpkin at least 60 feet above the ground? d. Use the rule you found in Part b to answer the following questions. i. What is your best estimate for the maximum height of the pumpkin? ii. How do you know if you have a good estimate? When does the pumpkin reach that height? 5|Page What you will learn about: Suspension Bridges: Some of the longest bridges in the world are suspended from cables that hang in parabolic arcs between towers. One of the most famous suspension bridges is the Golden Gate Bridge in San Francisco, CA. 1. Use the function π¦ = 0.002π₯ 2 β π₯ + 150 to answer the following questions. a. What is the approximate height (from the bridge surface) of the towers from which the cable is suspended? b. What is the shortest distance from the cable to the bridge surface, and where does it occur? c. For what interval(s) is the suspension cable 75 feet above the bridge surface? 6|Page Fundraising: Suppose that a group of students decided to organize a local event. ο· The relationship between number of tickets sold s and price x in dollars can be approximated by the linear equation π = 4,000 β 250π₯. ο· Expenses for promoting and operating the concert will include $1,000 for advertising and $3,000 for pavilion rental, $1,500 for security, and $2,000 for catering and event T-shirts for volunteer staff and band members. a. Find a function that can be used to predict income I for any ticket price x. b. Find a function that can be sued to predict profit P for any ticket price x. c. What ticket price(s) seem likely to give maximum income and maximum profit for the concert? What are those maximum income and profit values? How many tickets will be sold at the price(s) that maximize income and profit? d. If event planners are more interested in attracting a large audience without losing money on the event that in maximizing profit, what range of ticket prices should they consider? Explain your reasoning. 7|Page The Break-even point is the ticket price for which the eventβs income will equal expenses. Another way to think of the break-even point is the ticket price when profit is zero. a. Write and solve an equation that can be used to find the break-even ticket price for this particular planned concert. b. Write and solve an inequality that can be used to find ticket prices for which the planned concert will make a positive profit. c. Write and solve an inequality that can be used to find ticket prices for which the planned concert will lose money. 8|Page What you will learn about: Use strategies to rewrite quadratics in equivalent forms 1. Use the distributive property to expand and combine like terms to write each of the following expressions in equivalent standard form. ππ₯ 2 + ππ₯ + π a. (3 + π₯)π₯ b. 5π₯(4π₯ β 11) c. 7π₯(11 β 4π₯) d. 7π₯(π₯ + 2) β 19 e. β9(5 β 3π₯) + 7π₯(π₯ + 4) 2. Use the distributive property to write each of these quadratic expressions in equivalent form as a product of two linear factors. a. 7π₯ 2 β 11π₯ 9|Page b. 12π₯ + 4π₯ 2 c. β3π₯ 2 β 9π₯ 3. Use what you know about ways of writing algebraic expressions in equivalent forms to produce simplest possible expanded and where possible factored forms of these expressions. a. (14π₯ 2 + 3π₯) β 7π₯(4 + π₯) b. βπ₯ + 4π₯(9 β 2π₯) + 3π₯ 2 c. 5π₯(2π₯ β 1) + 4π₯ 2 β 2π₯ d. (5π₯ 2 β 4) β 3(4π₯ + 8π₯ 2 ) β 25π₯ 10 | P a g e 4. Special Products (π₯ + π)2 = (π₯ + π)(π₯ + π) a. (π₯ + 5)2 b. (π₯ β 3)2 c. (π₯ + 7)2 d. (2π₯ β 3)2 e. (π₯ + 4)(π₯ β 4) f. (π₯ β 8)(π₯ + 8) g. (3π₯ β 1)(3π₯ + 1) h. (4π₯ + 5)(4π₯ β 5) 11 | P a g e What you will learn about: Algebraic Methods to Solve Quadratic Equations 1. Solve each quadratic by talking the square root. a. π₯ 2 = 25 b. π₯ 2 = 12 c. 5π₯ 2 = 75 d. 5π₯ 2 + 8 = 8 e. 5π₯ 2 + 15 = 60 f. 5π₯ 2 + 75 = 60 g. β5π₯ 2 + 75 = 60 12 | P a g e 2. Solve by factoring a. 0 = π₯ 2 + 4π₯ b. 0 = 3π₯ 2 + 10π₯ c. βπ₯ 2 β 5π₯ = 0 d. β2π₯ 2 + 6π₯ = 0 e. π₯ 2 β 7π₯ + 10 = 0 f. π₯ 2 + 12π₯ + 32 = 0 g. 2π₯ 2 β 18π₯ β 72 = 0 h. π₯ 2 + 5π₯ = 6 13 | P a g e π¦ = ππ₯ 2 + ππ₯ + π 3. Solve by using the Quadratic Formula Quadratic Formula βπ βπ 2 β 4ππ π₯= ± 2π 2π a. π₯ 2 β 7π₯ + 10 = 0 b. π₯ 2 β π₯ β 8 = 0 c. βπ₯ 2 β 3π₯ + 10 = 0 d. 2π₯ 2 β 12π₯ + 18 = 0 e. 13 β 6π₯ + π₯ 2 = 0 f. βπ₯ 2 β 4π₯ β 2 = 2 14 | P a g e 15 | P a g e
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