ππ¦ π¦ β² = ππ₯ sin(π₯ 2 + π¦) = π¦ β2 + π₯ 3 sin(π₯ 2 + π¦) = π¦ β2 + π₯ 3 ππ¦ ππ¦ cos(π₯ 2 + π¦) β (2π₯ + ) = β2π¦ β3 + 3π₯ 2 ππ₯ ππ₯ ππ¦ ππ¦ 2 2 2π₯ cos(π₯ + π¦) + cos(π₯ + π¦) = β2π¦ β3 + 3π₯ 2 ππ₯ ππ₯ ππ¦ ππ¦ 2 β3 2 cos(π₯ + π¦) + 2π¦ = 3π₯ β 2π₯ cos(π₯ 2 + π¦) ππ₯ ππ₯ ππ¦ (cos(π₯ 2 + π¦) + 2π¦ β3 ) = 3π₯ 2 β 2π₯ cos(π₯ 2 + π¦) ππ₯ ππ¦ 3π₯ 2 β 2π₯ cos(π₯ 2 + π¦) = ππ₯ cos(π₯ 2 + π¦) + 2π¦ β3 π π πππ β ππ ππ¨π¬(ππ + π) = π π ππ¨π¬(ππ + π) + ππβπ 1 4 25 π¦ π₯ ππ₯ 1 = β ππ‘/π ππ ππ‘ 4 ππ¦ =? ππ‘ π‘ = 12 π ππ 1 β π₯ = 10 β (12) = 10 β 3 = 7 4 2 β β π¦ = 25 β 72 = 24 π₯ 2 + π¦ 2 = 252 ππ₯ ππ¦ 2π₯ + 2π¦ =0 ππ‘ ππ‘ 1 ππ¦ 2(7) (β ) + 2(24) =0 4 ππ‘ 1 ππ¦ 2(7) (β ) + 2(24) =0 4 ππ‘ ππ¦ 7 = β 0.073 ππ‘/π ππ ππ‘ 96 π ππ ππ/πππ
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