s By Shanelle P pd.8 } } } } } 1. Find the largest perfect square and simplify it. This will divide evenly and there will be no decimals, remainders, or fractions. 2. Write the number under the radical as a product of the perfect square and your answer from dividing. This will help you to simplify. 3. Reduce the radical which you have now created. 4. if the radical has a perfect square, that goes outside the radical sign and the number that cannot be reduced stays inside. 5. if it is raised to an index over 2, you find the root. It can be the cubed root, fourth root etc. 2^3=64. and √64 raised to the cubed root is 2. If there is no index, it is 2. Base- the number used as a factor. In 5^3, 5 is the base. } Exponent- the number that tells you how many times the base is used as a factor. In 5^3, 3 is the exponent. } Radicand -is the expression under the radical sign. In , 3 is the radicand. } Index- tells you how you should simplify the base. For example, in , 3 is the index. } Perfect Square Perfect Cube 4, 9, 16, 25, 36, 49, 64,81,100 2 4 6 8 x , x , x , x , 2 2 2 4 6 8 x y ,x y , 16x y , These powers are even. 8, 27, 64, 125,216,343,512,72 9,1000 x3, x6, x9, x12, ... x 3y 3, x 3y 6, 27x6y9, ... These powers are multiples of 3 } To simplify means to find another expression with the same value. } HINT – A Simplified Radical doesn’t have a fraction under it. √72= √36x2= 6√2 } The largest perfect square in 72 is 36. 36x2=72. When you find the square root of 36, you get 6 , because 6x6 is 36. Since 6 is the actual square root, It goes outside the radical sign. 2 is left inside the radical sign because it cannot be simplified anymore. } √16x^4=4x^2 } This radical has a variable inside. We know that the index is 2 because it isn’t expressed. X^4 can be simplified to x^2 because x^4 is a perfect square. 16 is also a perfect square, which is reduced to 4. And that is how you get 4x^2 } √75 = √25x3 = 5 √3 } 75 has the square factor of 25. 25 times 3 is 75. 25 unsquared is 5, which goes outside of the radical sign but 3 is left inside because it cannot be broken down anymore, 3 isn’t a perfect square. } √54= √9x6= 3 √6 } The largest perfect square in 54 is 9. 9 unsquared is 3, 6 isn’t a perfect square so it will be left inside of the radical sign and 3 will be put on the outside. } 3 √320= 3 √64x5= 4 3√5 } Here, we have the radical raised to the third root. The largest cubed root in 320 is 64. 64 multiplied by 5 is 320. 4x4x4 or 4^3 is 64. 4 is moved to the outside and 5 stays inside because it isn’t a perfect square and it cannot be simplified anymore. } } } √4500 = √100x45= √10x9x5= √10x3x5= 30√5 4,500 is a large number. The largest perfect square in 4500 is 100. 100x45=4500 so both numbers will be under the radical sign. 100 unsquared is 10 and 45 can be broken down. The largest perfect square in 45 is 9. 9 unsquared is 3. 10 and 3 are multiplied because they are both perfect squares. 30 goes outside of the radical sign and 5 remains since it can no longer be broken down } In this problem, we have two different variables and a number already outside of the radical. The perfect square in 18 is 9. 9x2=18. We can them split up the problem. We combine the 2 with the a because they cannot be simplified. It becomes 2a. 2a stays inside the radical. B^4 is simplified and that goes outside the radical. So 3ab^2 is outside the radical. But wait there’s already a three outside. Whenever there is a number outside of the radical, you multiply it by whatever you took out the radical sign. So you multiply 3x3ab^2. That is how you get 9ab^2 on the outside of the radical and 2a inside the radial. 3 is the index } ^3 √48=3^ √8x6= √4x6=2 ^3√6 } There is a number in the index so we have to find the largest perfect cube. In this case it is 8. 2x2x2=8. 8x6=48. The 2 goes outside of the radical and the 6 in left inside. Notice the index remains there. } √4x5/4= 2√5/4 = √5/4 In this problem, we have a fraction. First we are going to focus on the numerator. √20 is 4x5. 4 is a perfect square. 2x2=4. The numerator becomes 2√5/4. We know that 4 is divisible by 2 so we can simplify. 2/2=1, 4/2=2. The answer can be simplified to √5/4. } 8√50+3√2= √25x2+3√2=8x5√2=40√2+3√2=43√2 } Whenever a number is outside of the radical, we must multiply it. 50 can be simplified to 25x2. 5 goes outside the radical so we multiply it by the 8.3√2 can no longer be simplified. So 40√2+3√2=43√2. } If the numbers inside the radical are different, you cannot combine them. } Ex- 22√2+34√4. the radicals cannot be combined. } Simplify } √4a^2b^4 } √180 } √300 1. 2ab^2. } 6√5 } 10√3 }
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