3.4: Zeros of Polynomial Functions Warm-up 1 Solve the equation 3π₯ 3 + 7π₯ 2 β 22π₯ β 8 = 0 given that β is 3 a root. Today we will be finding a lot of zeros. You may ask yourself: There exists a way to quickly determine all possible rational zeros of any function: In other words: 1. Find all the possible rational zeros of: a) π(π₯ ) = π₯ 3 + 3π₯ 2 β 6π₯ β 8 b) β(π₯ ) = 2π₯ 4 + 3π₯ 3 β 11π₯ 2 β 9π₯ + 15 c) π£(π₯ ) = 4π₯ 5 β 8π₯ 4 β π₯ β 2 Finding the zeros of a polynomial function Step 1: Find all possible rational zeros with the Rational Zero Theorem Step 2: Check possible zeros synthetic division or with the Factor Theorem: if π (π) = 0, then π₯ β π is a factor of π(π₯) Step 3: Use synthetic division to factor the polynomial Step 4: Continue to factor the remaining polynomial. 2. Find all zeros of the polynomial functions. a. π(π₯ ) = π₯ 3 β 2π₯ 2 β 11π₯ + 12 b. π(π₯ ) = 2π₯ 3 β 5π₯ 2 + π₯ + 2 c. π(π₯ ) = 2π₯ 3 + π₯ 2 β 3π₯ + 1 We can also use this same approach to solve polynomial equations. 3. Find all roots of the polynomial equation. a. π₯ 3 β 2π₯ 2 β 7π₯ β 4 = 0 b. 2π₯ 3 β 5π₯ 2 β 6π₯ + 4 = 0 c. π₯ 4 β 2π₯ 2 β 16π₯ β 15 = 0 4. Find an 3ππ degree polynomial with zeros of 4 πππ 2π such that π (β1) = β50 5. Find an 3ππ degree polynomial with zeros of β4 and 2 + 3i such that π(2) = 9. Okay, letβs put it all together. 6. Find all complex zeros of the polynomial function. a. π(π₯ ) = 2π₯ 4 + 3π₯ 3 β 11π₯ 2 β 9π₯ + 15 b. π(π₯ ) = 3π₯ 4 β 11π₯ 3 β 3π₯ 2 β 6π₯ + 8 c. π(π₯ ) = 4π₯ 5 + 12π₯ 4 β 41π₯ 3 β 99π₯ 2 + 10π₯ + 24
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