Answer on Question #47022 – Math – Algebra sqrt 8^x-3 = ^3sqrt 4^2-x Solution: 3 √8x−3 = √42−x x−3 2 x−3 (23 ) 2 3(x−3) 2 2 8 35 2−x 3 2−x (22 ) 3 2(2−x) 2 3 =4 = = 3(x − 3) 2(2 − x) = 2 3 9(x − 3) = 4(2 − x) 9x − 27 = 8 − 4x 13x = 35 35 x= 13 Answer: x = 13 www.AssignmentExpert.com
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