Use the graph of the function to find the approximations of the given values. a) π (β1) b) π (0) c) π (1) d) π(3)βπ(1) 3β1 Solutions: This question is similar to the previous one. One difference here is that this is a piecewise function, so we have to be aware that a closed circle means that point is actually part of the graph, while the open circle means that that point is not part of the graph. For a), go left one unit, and find that you have to go up two units to reach the graph (the closed circle). Thus, π(β1) = 2. For b) you just stay at the π¦-axis (donβt go left or right at all) and find that you have to go down one unit to reach the graph. Thus, π(0) = β1. For c), go right one unit, and find that you donβt have to go up or down at all to reach the graph (again, the closed circle). Thus, π(1) = 0. For d), first find π(3) (since we found π(1) already in part c). For π(3), we go right three units and find that we have to go up three units to reach the graph. Thus, π (3) = 3. Then, we plug these numbers into the given formula: π(3) β π(1) 3 β 0 3 = = 3β1 3β1 2
© Copyright 2026 Paperzz