LECTURE 11 CIRCULAR MOTION Instructor: Kazumi Tolich Lecture 11 2 ¨ Reading chapter 6-5 ¤ ¤ ¤ Uniform circular motion Centripetal and tangential acceleration of non-uniform circular motion Dynamics of circular motion n n n Centripetal force Unbanked and banked curves Loop-the-Loop Centripetal force and acceleration 3 ¨ ¨ ¨ Centripetal force, 𝐹"# , is any form of force (normal force, tension, gravity, etc) applied toward the center of the circle that keeps an object in a circular motion. Centripetal acceleration, 𝑎"# , is an acceleration of an object caused by a centripetal force. The magnitude of a net centripetal force required for an object with a mass 𝑚 going around in a circular path with a radius 𝑟 with a uniform speed 𝑣 is given by ( 𝐹"# = 𝑚𝑎"# 𝑣+ =𝑚 𝑟 Velocity and acceleration of a circular motion 4 ¨ The direction of the velocity is always tangential to the path, perpendicular to the circle’s radius. ¨ An object under a uniform circular motion moves at constant speed and has a centripetal acceleration. ¨ An object in a circular motion with varying speed has both centripetal and tangential accelerations. 𝐚-.-/0 = 𝐚"# + 𝐚- Quiz: 1 ¨ You are in the front passenger seat of a car. While the car makes a sharp left turn, you found yourself leaning toward the passenger door (to your right). Which of the following statements is/are correct? Choose all that apply. A. B. C. D. Centrifugal force is pushing you to the right. Centripetal force is pushing you to the right. The seat is exerting a leftward frictional force on you. The seat is exerting a rightward frictional force on you. Quiz: 11-1 answer ¨ ¨ ¨ ¨ ¨ The seat is exerting a leftward frictional force on you. For you to make the turn, there must be centripetal force acting on you toward the center of the curvature. The static frictional force by the seat on your bottom is supplying that centripetal force. Meanwhile, your head tends to keep going in a straight path due to its inertia. This fictitious “force” to the right is sometimes called “centrifugal force.” But there is no such force. Why don’t satellites fall into Earth? 7 Q. A. Why don’t satellites fall into Earth because of Earth’s gravity? They do. The tangential velocity of the satellite is fast enough so that the distance the satellite falls towards Earth, and the distance it travels in the tangential direction in a given time follow the satellite’s orbit. Example: 1 8 ¨ Igor is an engineer in a spacecraft orbiting Earth at an altitude ℎ = 520 km with a constant speed 𝑣 = 7.6 km/s. Igor’s mass is 𝑚 = 79 kg. a) b) What is his acceleration? What (centripetal) gravitational force does Earth exert on Igor? Quiz: 2 9 ¨ You drive your dad’s car too fast around a curve, and the car starts to skid. What is the correct description of this situation? Choose all that apply. A. The car’s engine is not strong enough to keep the car from being pushed out. B. Static friction between the tires and the road is not strong enough to keep the car in the circle. C. Kinetic friction between the tires and the road is not strong enough to keep the car in the circle. D. The car is too massive to make the turn. Quiz: 11-2 answer 10 ¨ ¨ ¨ ¨ ¨ ¨ Static friction between the tires and the road is not strong enough to keep the car in the circle. On a unbanked road, static friction by the road on the car provides the centripetal force necessary for the car to follow a curve. It is static friction, not kinetic friction, because no slipping occurs at the point of contact between road and tires. The maximum speed the car can go without skidding is limited by the maximum static friction the road can exert on the tire. The maximum speed is independent of mass of the car. The car’s engine is internal to the car, so it does not provide centripetal force to the car. Example: 2 11 A bicyclist travels at a constant speed of 𝑣 = 9.00 m/s in a circle of radius 𝑟 = 25.0 m on a flat ground. The combined mass of the bicycle and rider is 𝑚 = 85.0 kg. ¨ a) b) Calculate the magnitude of the force of friction exerted by the road on the bicycle. If the coefficient of static friction between the tires and this road is 𝜇4 = 1.0, what is the maximum speed the bicycle can go before skidding? Quiz: 3 12 ¨ A car is following a banked curve without skidding. The road is very icy, so it is not providing any frictional force. What is providing the centripetal force? Choose all that apply. A. B. C. D. Normal force by the road Weight of the car Actually, this is not possible. Friction is always needed. Actually, centripetal force is not necessary. Quiz: 11-3 answer 13 ¨ ¨ ¨ On a banked road, the normal force by the road will have a component in the centripetal direction. The banking angle 𝜃 is usually chosen so that no friction is needed for a car to complete the curve at the specified speed. Banking angle is given by 𝑣+ tan 𝜃 = 𝑟𝑔 Quiz: 4 14 ¨ You are riding a bicycle and comfortably making around a loop-theloop. Which of the following forces are providing the centripetal force at the top of the loop-the-loop? Choose all that apply. A. B. C. D. Weight of you and bicycle Normal force by the track Frictional force by the track Nothing. Centripetal force is not needed. Quiz: 11-4 answer 15 ¨ ¨ ¨ The combination of weight of you and bicycle and normal force by the track is providing the centripetal force. If you are making the loop-the-loop, the bike is touching the track, so the normal force on the bike is non-zero and pointing down, towards the center of the loop. Weight is also downward towards the center of the loop. Example: 3 16 ¨ The radius of curvature of the track at the top of a loop-the-loop on a roller-coaster ride is 𝑟. The mass of the roller-coaster is 𝑚. a) b) ¨ Calculate the speed of the coaster, 𝑣, as a function of the normal force on the coaster by the track, 𝑁;< . What is the minimum speed at which the coaster must be going at the top of the loop-the-loop to barely make it? Loop-the-loop fails when you do not have enough speed at the top. ¤ http://www.youtube.com/watch?v=tzQJNeqiGG4
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