Last Lecture: Projectile Motion Lecture 5 ¾ ¾ ¾ Horizontal motion Vertical motion Force and Motion. Mass and Weight, Free Body Diagrams (HR&W, Chapter 5) http://web.njit.edu/~sirenko/ Physics 105; Summer 2006 Lecture 5 Andrei Sirenko, NJIT 1 Lecture 5 Andrei Sirenko, NJIT 2 Projectile Motion; General Case Trajectory and horizontal range Newton’s Laws I. If no net force acts on a body, then the body’s velocity cannot II. III. Lecture 5 Andrei Sirenko, NJIT 3 change. The net force on a body is equal to the product of the body’s mass and acceleration. When two bodies interact, the force on the bodies from each other are always equal in magnitude and opposite in direction. Lecture 5 Andrei Sirenko, NJIT 4 Objectives Forces: Gravitational Force: ¾ • By the end of Week we should be able to – Formulate Newton’s laws in our own words – Draw free-body-diagrams (FBDs) for a given problem – Explain the difference between static and kinetic frictional force – List a few reference frames where Newton’s laws do not apply Archimedes Force ¾ Friction Force: ¾ Tension Force ¾ Spring Force ¾ ¾ Lecture 5 Andrei Sirenko, NJIT 5 F = mg Lecture 5 Normal Force Andrei Sirenko, NJIT 6 Force is a vector. Units: [Newton] Forces: 1 N = 1 kg • 1 m/s2 Force has direction and magnitude Mass connects Force and Acceleration Mass is a measure of inertia. Lecture 5 Andrei Sirenko, NJIT 7 Lecture 5 Andrei Sirenko, NJIT 8 Forces: Gravitational Force: F = mg ¾ Archimedes Force ¾ Friction Force: ¾ Tension Force ¾ Spring Force ¾ ¾ Normal Force Lecture 5 Andrei Sirenko, NJIT 9 Lecture 5 Andrei Sirenko, NJIT 10 11 Lecture 5 Andrei Sirenko, NJIT 12 Gravitational Force: F = mg; g = 9.8 m/s2 R = 6,400 km Lecture 5 Andrei Sirenko, NJIT Lecture 5 Andrei Sirenko, NJIT 13 Lecture 5 Andrei Sirenko, NJIT 14 EXAMPLES of Free Body Diagrams Picture of Situation FBD mg Lecture 5 Andrei Sirenko, NJIT 15 Lecture 5 Andrei Sirenko, NJIT mg 16 EXAMPLE 5N θ θ = 30º Find F3 so that a = 0 F net = F1 + F2 F net = ma Lecture 5 Andrei Sirenko, NJIT 10N 17 Lecture 5 Andrei Sirenko, NJIT EXAMPLE Lecture 5 Andrei Sirenko, NJIT 19 Lecture 5 Andrei Sirenko, NJIT 18 FBD 20 How do we jump ? Static and Kinetic Friction Static frictional force Kinetic frictional force Lecture 5 Andrei Sirenko, NJIT 21 Lecture 5 Andrei Sirenko, NJIT 22 Uniform Circular Motion Kinetic Friction Centripetal acceleration Top view: Kinetic frictional force: Skid marks are 290 m long! µk = 0.6 and a = const. How fast was the car going when the wheels became locked? Period Centripetal force : F = ma Lecture 5 Andrei Sirenko, NJIT 23 Lecture 5 Andrei Sirenko, NJIT 24 QZ #5 Name, ID #, Section # Problem 1: What is the acceleration (in unit vectors notation) of a particle with m =2 kg due to a combination of two forces: F1= (2N)i+(2N)j-(3N)k and F2= (-2N)i+(2N)j+(6N)k. Problem 2: What is the magnitude of the acceleration vector? Problem 3: What is the magnitude of the Net Force ? Lecture 5 Andrei Sirenko, NJIT 25
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