Chemistry Acids & Bases SALT SOLUTIONS Salts Salts are simply ionic compounds. They are the result of a strong acid and a strong base (i.e. acid-base neutralization reaction). Salts can be acidic, basic, or neutral in an aqueous environment. Overview Strong Acid Strong Acid weak acid weak acid + + + + Strong Base weak base Strong Base weak base neutral salt acidic salt basic salt Ka > Kb = acidic salt Kb > Ka = basic salt Strong Acid + Strong Base: HCl + NaOH H+ + Cl– + Na+ + OH– NaOH + H2O NaOH is a neutral salt because at equilibrium the reaction is completely shifted to the right. Strong Acid + weak base HCl + NH3 H+ + Cl– + NH3 + The ammonia will react with the H : H+ + NH3 + Cl– NH4Cl + NH3 is a weak base making NH4 a relatively strong conjugate acid. The ammonium ion (a relatively + + strong conjugate acid) will then react with water to produce: NH4 + H2O NH3 + H3O Thus making an NH4Cl an acidic salt. H+ + C2H3O2– + Na+ + OH– Na+ + C2H3O2– + H2O – Because HC2H3O2 is a weak acid, the basic conjugate form predominates (C2H3O2 ). Because water is the predominate species in an aqueous environment, the basic salt is formed from the hydrolysis reaction: – – C2H3O2 + H2O HC2H3O2 + OH – It is the formation of the OH that makes NaC2H3O2 a basic salt. weak acid + Strong Base: HC2H3O2 + NaOH weak acid + weak base HF + NH3 NH4F + H2O NH4+ + F– If the Ka of NH4+ (tendency for NH3 to form NH4+) is stronger than the Kb for F– (tendency to form HF), then the reaction will proceed to the right: NH4F is an acidic salt (NH4+ + H2O NH3 + H3O+). – Conversely, if Kb of F (tendency to for HF) is stronger, then the reaction will proceed to the left: NH4F is a basic salt (F– + H2O HF + OH–). Thus, there is a competition between Ka and Kb. –10 KaNH4 = 5.6 x 10 KbF = 1.4 x 10–11 Ka > Kb so NH4F is an acid salt (pH ~6.2) Helpful Group 1 cations & heavier Group 2 (Ca2+, Sr2+, Ba2+) and Mg2+ are neutral = spectator ions. Transition metals & Al3+ are slightly acidic. Strong acids produce neutral cations. Strong bases produce neutral anions. Both drive the reactions to the far left. (e.g., HCl H+ + Cl–) Summary Salt NH4I Na3PO4 KClO4 Cation + NH4 (acidic) + Na (spectator) + K (spectator) Anion – I PO4 – ClO4 (spectator) (basic) (spectator) Salt acidic basic neutral E:\2014-2015\340_Masterton\340_Sections\340.13_Acids_and_Bases\340.14.08.Salt Acid-Base Properties .docx; Masterton Ch. 13: Acids & Bases Chemistry Strong Acids Strong Bases HCl HNO3 LiOH Ca(OH)2 HBr HClO4 NaOH Sr(OH)2 H2SO4 HI (note: halogen but not HF, H3PO4 are weak acids) Ba(OH)2 KOH (group 1 & heavy group 2) 77. Write formulas for two salts that: 3+ Ni+ is slightly acidic; want spectator anion (from a. contain Ni and are acidic strong acid) b. contain Na+ and are basic – c. contain ClO4 and are neutral + d. contain NH4 and are acidic Na+ is neutral; want basic anion (from weak acid) 2– c. Br– and are neutral d. contain ClO4 and are acidic – + NH4 is acidic; want spectator anion (strong acid) 2– Because CO3 is a basic salt (comes from a weak acid HCO3–), want neutral (spectator) ion – Br is neutral (strong acid); want neutral (spectator) e.g., cation from strong base or group or heavier group 2 – 1. NaF 2. Na3PO4 ClO4 is a spectator ion; want spectator cation (from 1. NaClO4 strong base or neutral ion) 2. KClO4 78. We may need to do some of these using a Ka/Kb table (see text) + + a. NH4 and are NH4 Ka = 5.6 x 10–10; want Kb > Ka basic (e.g., anion from weak acid) –4 Kb ClO– = 3.6 x 10–7; Kb CO32– = 2.1 x 10 b. CO3 and are basic 1. NiCl3 2. Ni(NO3)3 – ClO4 is neutral (strong acid); want acidic cation 3+ 2+ (eg., transition, Al , or to a lesser extent, Mg 1. NH4Cl 2. NH4NO3 1. NH4ClO 2. NH4CO3 1. Na2CO3 2. MgCO3 1. NaBr 2. MgBr2 1. Al(ClO4)3 2. Sr(ClO4)2 Chemistry 79. State whether 1 M solution of the following salts in water would be acidic, basic, or neutral. + 2– basic salt a. K2CO3 K = spector; CO3 = basic – + slightly acidic salt (Ka > Kb) b. NH4F NH4 = slightly acidic; F = slightly basic –10 –11 pKa = 5.6 x 10 ; Kb = 1.4 x 10 ; c. LiH2PO4 Li = spectator; H2PO4 = ? – for H2PO4 : – 2– + H2PO4 (aq) + H2O(l) HPO4 (aq) + H3O (aq) or – – H2PO4 (aq) + H2O(l) H3PO4(aq) + OH (aq) – + + –12 basic – neutral Na = spectator; NO2 = basic e. Ba(ClO4)2 Ba = spectator; ClO4 = spectator (both come from strong) –8 Kb = 1.4 x 10 Ka > Kb acidic – d. NaNO2 2+ Ka = 6.2 x 10 81. Write the net ionic equations to explain the acidity or basicity of the various salts in #79. + a. K2CO3 (basic) K is spectator, so doesn’t participate in reaction. 2– CO3 is basic and makes the salt basic. (Remember: aqueous solutions are composed mostly of water. Even in strong acids and strong bases.) 2– CO3 (aq) + H2O(l) b. NH4F (acidic) – – HCO3 (aq) + OH (aq) – (the produced OH makes the salt basic) + NH3(aq) + H+(aq) or – – F (aq) + H2O(l) HF(aq) + OH (aq) NH4 (aq) Ka = 5.6 x 10 –10 Kb = 1.5 x 10 –11 Ka > Kb acidic c. LiH2PO4 (acidic) – 2– H2PO4 (aq) + H2O(l) – H2PO4 (aq) + H2O(l) + HPO4 (aq) + H3O (aq) or – H3PO4(aq) + OH (aq) e. Ba(ClO4)2 + (Na is spectator) – NO2 (aq) + H2O(l) 2+ –8 Kb = 1.4 x 10 –12 Ka > Kb acidic + (Li is spectator) d. NaNO2 (basic) Ka = 6.2 x 10 basic – HNO3(aq) + OH (aq) (Ba is heavy group 2 spectator) – ClO4 (comes from strong acid = spectator ion) (neutral salt) Chemistry 83. Arrange the following 0.1 M aqueous solutions in order of decreasing pH (highest to lowest) Remember: Strong or weak = amount of dissociation. This differs from the concentration of an acid or base, which refers to molarity. That’s why question makes concentrations the same. Compare Ka’s and Kb’s. NaF Ba(NO3)3 HNO3 NH4NO3 Al(NO3)3 1. Highest pH will be from the strongest acid. HNO3 is the only strong acid. #1 = HNO3 2. F– is the conjugate base of a weak acid ( relatively strong base) (Na+ = spectator) #5 = NaF + NH4 is strong conjugate acid of weak base; 3+ Al = weak acid (comparable to transition metals) 1 – NaF spectator + weak base 2 – Ba(NO3)2 spectator + spectator 3 – NH4NO3 weak acid (Ka = 5.6 x 10 4 – Al(NO3)3 weak acid (aqueous as Al(H2O6) ; Ka = 1.2 x10 ) + spectator 5 – HNO3 strong acid –10 ) + spectator 3+ –5
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