Therefore, the perimeter of the rectangle is ft. 6-5 Operations with Radical Expressions APPLY MATH Simplify. 35. GEOMETRY Find the area of the rectangle. 8. SOLUTION: SOLUTION: The area of a rectangle of length l and width w is A = lw. 34. GEOMETRY Find the perimeter of the rectangle. Therefore, the area of the rectangle is 2 ft . SOLUTION: The perimeter of a rectangle of length l and width w is P = 2l + 2w. Simplify. 50. SOLUTION: Therefore, the perimeter of the rectangle is ft. 35. GEOMETRY Find the area of the rectangle. SOLUTION: The area of a rectangle of length l and width w is A = lw. Therefore, the area of the rectangle is 2 eSolutions Manual - ft Powered by Cognero . Simplify. Page 1
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