y = x – 2 3y = -2x + 3 -x + y = 1 x + 2y = 8 x + 4y = 12 7x + 4y = -12

1
y= x–2
3
3y = -2x + 3
-x + y = 1
x + 2y = 8
x + 4y = 12
7x + 4y = -12
1
y= x–2
3
3y = -2x + 3
Solve the linear system
below, by graphing.
-x + y = 1
x + 2y = 8
Solve the linear system
below, by graphing.
x + 4y = 12
7x + 4y = -12
© Lisa Davenport 2014
Solve the linear system
below, by graphing.
Rewrite each equation in slope- intercept form.
Graph each line, independently.
Identify the point of intersection.
1
y= x–2
3
3y = -2x + 3
𝟏
3y = -2x + 3
3
3
−𝟐
x
𝟑
x + 4y = 12
7x + 4y = -12
x + 4y = 12
-x
-x
4y = -x + 12
4
4
-x + y = 1
+x
+x
y=x+1
y = 𝟑x – 2
y=
-x + y = 1
x + 2y = 8
x + 2y = 8
-x
-x
2y = -x + 8
2
2
+1
y=
−𝟏
x
𝟐
+4
y=
+3
7x + 4y = -12
-7x
-7x
4y = -7x – 12
4
4
−𝟕
y= 𝟒x–3
(3,-1)
(2,3)
−𝟏
x
𝟒
(-4,4)
1
y= x–2
3
3y = -2x + 3
Solve the linear system
below, by graphing.
-x + y = 1
x + 2y = 8
Solve the linear system
below, by graphing.
x + 4y = 12
7x + 4y = -12
© Lisa Davenport 2014
Solve the linear system
below, by graphing.
Directions:
Print pages 1 & 2 (3 & 4 for the answer key). On my printer, I use the
option to print double-sided and to flip along the short edge.
Once photocopied, cut off the extra strip of paper at the bottom (below
the dotted line). Then, have students lay the paper so that page 2 is face
up (the side with the space for writing the 3 steps and working out the
examples). Fold up the bottom section so that the rectangular tabs are
completely visible. Then, the top tab will fold down to meet the other 3
tabs. Cut along the dotted lines, creating 3 tabs.
The final product should look like this: