Clayton College & State University
Department of Natural Sciences
October 25, 2004
Physics 1112 – Quiz 6
Name ________SOLUTION___________________________
1. In the Figure below, let B = 0.600 T, V = 8.00 m/s, L = 15.0 cm, and R = 25.0 ,
and assume that the resistance of the rods and rails is negligible. Find
a. The induced emf in the circuit.

 = BVL = (0.600 T)(8.00 m/s)(0.150 m) = 0.720 V
b. The current in the circuit.
I = / R = (0.720 V) / (25.0  0.0288 A
c. The direction of the current in the circuit.
Clockwise.
d. The force needed to move the rod with constant velocity.
F = I B L = (0.0288 A)(0.600 T)(0.150 m) = 0.00259 N
Clayton State University
Department of Natural Sciences
October 24, 2007
Physics 1112 – Quiz 8
Name ______SOLUTION_______________________________
Part of a single rectangular loop of wire with dimensions shown in below is situated
inside a region of uniform magnetic field of 0.880 T. The total resistance of the loop
is 10.0 .
a. With what constant velocity do you need to pull the loop out of the field in
order to generate electrical current of 10.0 A in the loop? Neglect gravity.
=vBL
=IR
I R= v B L
v = (I R)/ (B L)
v = (10.0 A) (10.0 )/[ (0.880 T) (0.350 m)] = 325 m/s
b. What force do you need to apply to the loop in order to move it with this
constant velocity?
F = B L I = (0.880 T) (0.350 m)(10.0 A) = 3.08 N
Department of Natural Sciences
Clayton College & State University
March 18, 2004
Physics 1112 – Quiz 7
Name _____SOLUTION________________________________
A coil consists of 40 turns of wire wound around a square frame that is 20.0 cm on a side.
a. How rapidly must this coil to be withdrawn from a perpendicular magnetic field
with a strength of 0.600 T in order to produce an emf of 3.20 V?
= N /t
=f -i

f = 0 Wb
i = B A = B (a)2 = (0.600 T) (0.200 m)2 = 0.0240 Wb
t = N /= 0.300 s
b. What is the direction of the current induced in the coil?
Clockwise.
Clayton State University
Department of Natural Sciences
March 20, 2008
Physics 1112 – Quiz 8
Name ___SOLUTION__________________________________
The rod moves with a speed of 3.50 m/s is 30.0 cm long, and has a negligible resistance
The magnetic field is 0.150 T, and the resistance of the U-shaped conductor is 25.0 
at a given instant. Calculate
(a) the induced emf,
 = v B l = (3.50 m/s)(0.150 T)(0.300 m) = 0.158 V
(b) the current in the U-shaped conductor.
I = /R = (0.158 V)/(25.0 ) = 0.00630 A
(c) In what direction should we move the rod for the direction of the current in the
loop to be clockwise?
Downward