Lesson 7 β Factoring a Sum or Difference of Cubes Sum of Cubes An expression that contains two perfect cubes added together can be factored as follows: π΄3 + π΅3 = (π΄ + π΅)(π΄2 β π΄π΅ + π΅2 ) Note: 3 βπ΄3 = π΄ Difference of Cubes An expression that contains perfect cubes where one is subtracted from the other can be factored as follows: π΄3 β π΅3 = (π΄ β π΅)(π΄2 + π΄π΅ + π΅2 ) Example 1: Example 2: Prove the Sum of Cubes Formula using the factor theorem. Factor each of the following: a) 8π₯ 3 + 64 c) 125(π₯ β 8)3 + 8(2π₯ + 1)3 b) π₯ 9 β 1
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