Lesson 7 – Factoring a Sum or Difference of Cubes

Lesson 7 – Factoring a Sum or Difference of Cubes
Sum of Cubes
An expression that contains two perfect cubes added together can be factored as follows:
𝐴3 + 𝐡3 = (𝐴 + 𝐡)(𝐴2 βˆ’ 𝐴𝐡 + 𝐡2 )
Note:
3
√𝐴3 = 𝐴
Difference of Cubes
An expression that contains perfect cubes where one is subtracted from the other can be factored as
follows:
𝐴3 βˆ’ 𝐡3 = (𝐴 βˆ’ 𝐡)(𝐴2 + 𝐴𝐡 + 𝐡2 )
Example 1:
Example 2:
Prove the Sum of Cubes Formula using the factor theorem.
Factor each of the following:
a) 8π‘₯ 3 + 64
c) 125(π‘₯ βˆ’ 8)3 + 8(2π‘₯ + 1)3
b) π‘₯ 9 βˆ’ 1