Final Review.notebook
June 08, 2015
I can solve system word problems.
1
Final Review.notebook
June 08, 2015
Two small pitchers and one large pitcher can hold 8 cups of
water. One large pitcher minus one small pitcher constitutes
2 cups of water. How many cups of water can each pitcher
hold?
Solve by any method mentioned.
If done algebraically:
2x + y = 8
‐x + y = 2
Let x = small pitcher
subtract:
y = larger pitcher
3x = 6
2x + y = 8
x=2
y‐x=2
The small pitcher holds 2 cups of water.
2(2) + y = 8
4+y=8
y=4
The large pitcher holds 4 cups of water.
2
Final Review.notebook
June 08, 2015
A test has twenty questions worth 100 points.
The test consists of True/False questions worth 3
points each and multiple choice questions worth
11 points each. How many multiple choice
questions are on the test?
Solve by any method mentioned.
If done algebraically:
x + y = 20
3x + 11y = 100
3(x + y = 20)
Let x = T/F questions
Let y = Multiple Choice questions
x + y = 20
3x + 11y = 100
3x + 11 y = 100
3x + 3y = 60
3x + 11y = 100
‐8y = ‐40
8y = 40
y=5
There are 5 multiple choice questions.
x + 5 = 20
x = 15
There are 15 T/F questions.
3
Final Review.notebook
June 08, 2015
Margie is responsible for buying a week's supply of food and
medication for the dogs and cats at a local shelter. The food and
medication for each dog costs twice as much as those supplies for a
cat. She needs to feed 164 cats and 24 dogs. Her budget is $4240. How
much can Margie spend on each dog for food and medication?
Solve by any method mentioned.
If done algebraically with substitution:
164c + 24d = 4240
Let c = cost per cat
Let d = cost per dog
164c + 24d = 4240
d = 2c
d = 2c
164c + 24(2c) = 4240
164c + 48c = 4240
212c = 4240
c = 20
She can spend $20 on each cat.
d = 2c
d = 2(20) = 40
She can spend $40 on each dog.
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Final Review.notebook
June 08, 2015
Solve by any method mentioned.
If done algebraically:
3w + 3f = 17.70
Let w = cost of water slide
Let f = cost of Ferris wheel
3w + 3f = 17.70
2w + 3f = 15.55
2w + 3f = 15.55
w = 2.15
The water slide costs $2.15 per slide.
Substitute:
2(2.15) + 3f = 15.55
4.30 + 3f = 15.55
3f = 11.25
f = 3.75
The Ferris wheel costs $3.75 per ride.
5
Final Review.notebook
June 08, 2015
The equations 5x + 2y = 48 and 3x + 2y = 32 represent
the money collected from school concert tickets
sales during two class periods. If x represents the
cost for each adult ticket and y represents the cost
for each student ticket, what is the cost for each
adult ticket?
Solve the system simultaneously. Various methods of solution can be used. One method is shown here.
5x + 2y = 48
3x + 2y = 32
subtracting gives:
and
2x = 16
x = 8.
The cost of an adult ticket is $8.
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Final Review.notebook
June 08, 2015
I can solve inequalities
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Final Review.notebook
June 08, 2015
Solve the inequality z + 5 ≥ 3 and represent its solutions using a
number line. Solve the inequality x ‐ 3 ≤ 2x and represent its solutions using a number line.
x > ‐3
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Final Review.notebook
June 08, 2015
‐6 > 5n + 5 + 4
2p ‐ 4p < ‐2
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Final Review.notebook
June 08, 2015
‐2(b + 1) + 4 < 10
‐5(1 ‐4a) > ‐5
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Final Review.notebook
June 08, 2015
I can solve multi‐step equations.
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Final Review.notebook
June 08, 2015
12 = −4(−6x − 3)
5n + 34 = −2(1 − 7n)
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Final Review.notebook
June 08, 2015
3n − 5 = −8(6 + 5n)
2(4x − 3) − 8 = 4 + 2x
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Final Review.notebook
June 08, 2015
I can determine the slope/rate of change
of a line when given two points.
14
Final Review.notebook
June 08, 2015
Find the slope of a line through the points (3,7) and (5,11)
Find the slope of a line through the following the points: (‐6,7) and (‐9,8)
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Final Review.notebook
June 08, 2015
I can use Pythagorean Theorem to
find the missing side of a right
triangle.
16
Final Review.notebook
June 08, 2015
A right triangle has one leg that is 7
cm. The hypotenuse is 12 cm. Find the
length of the other leg. (Round to the nearest
tenth is necessary.)
A right triangle has one leg that is 10 ft.
The hypotenuse is 22 ft. Find the length
of the other leg. (Round to the nearest tenth is
necessary.)
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