newest physics for HKDSE Revision Notes 1 Kendy Contents Part I Heat and Gases Temperature, Heat and Internal Energy 1 1.2 Transfer Processes 7 1.3 Change of State 12 1.4 Gases 19 Chapter 1.1 Part II Force and Motion Position and Movement 27 2.2 Force and Motion 40 2.3 Projectile Motion 49 2.4 Work, Energy and Power 52 2.5 Momentum 57 2.6 Uniform Circular Motion 61 2.7 Gravitation 68 Chapter 2.1 1 1.1 Temperature, Heat and Internal Energy 1. Temperature and thermometers Temperature is the degree of hotness of an object. Temperature is a quantity associated with the average kinetic energy (KE) of molecules due to their random motions. temperature ɥ ɦ average KE ɥ Average kinetic energy of molecules depends only on temperature. 1 gram of water at 90oC and 100 gram of meat at 90oC have the same amount of average kinetic energy of molecules. Thermometer must have temperature-dependent properties. temperature ɦ volume or resistance…or length… 3 common temperature scales ¾ ¾ ¾ Celsius scale Fahrenheit scale Kelvin scale In the calibration process of thermometer, the thermometer is put into melting ice and graduation is made on the thermometer. This is repeated in boiling water. The range between lower and higher fixed point is divided into 100 equal divisions. A single division is called 1 degree Celsius (1oC). lower fixed point of Celsius scale ¾ upper fixed point of Celsius scale ¾ 0oC (melting ice) 100oC (boiling water) Kelvin scale is also known as absolute temperature scale. Temperature in Kelvin scale must be positive. The lowest possible temperature is 0 K, it is the absolute zero. temperature in Kelvin = temperature in Celsius + 273 1 1.1 Temperature, Heat and Internal Energy What is the lower fixed point in absolute temperature scale? A. 273 K B. 0K C. 273 K D. 373 K lower fixed point in Celsius scale: 0oC temperature in Kelvin = temperature in Celsius + 273 lower fixed point in absolute temperature scale = 0 + 273 = 273 K Answer: C Degree Celsius was used for a unit increment in Kelvin scale. o 1 K = 1 C The temperature of a block of copper was reduced from 425oC to 100oC. Express the decrement in Kelvin scale. A. 152 K B. 325 K C. 373 K D. 698 K decrement in Kelvin scale = decrement in Celsius scale = 325 K Answer: B 2 1.1 Temperature, Heat and Internal Energy 2. Heat and internal energy Heat is the energy transferred as a result of temperature difference between objects. If 2 objects have the same temperature, there is no net heat flow. Internal energy (IE) is the sum of the kinetic energy (KE) and potential energies (PE) of molecules. For the same substance: ¾ ¾ ¾ mass IE temperature internal energy (temperature average KE of molecules ) IE in gas state > IE in liquid state > IE in solid state (average separation between gas molecules is the largest largest average PE of molecules) internal energy (IE) = KE of molecules + PE of molecules Relationship between heat and internal energy (temperature: A > B): ¾ ¾ Net heat flows from A to B IE of A & IE of B until thermal equilibrium (same temperature) is reached. 3. Heat capacity and specific heat capacity Heat capacity (C) of a substance is the energy required to raise its temperature by 1oC . ¾ ¾ depends on mass and material unit of C: JK1 / J oC1 Q = CT ¾ where Q is the heat Specific heat capacity (c) of a substance is the energy required to raise the temperature of 1 kg of it by 1 oC. ¾ ¾ depends on material only unit of c: Jkg1K1 / Jkg-1 oC 1 Q = mcT Relationship between heat capacity and specific heat capacity: C = mc 3 1.1 Temperature, Heat and Internal Energy Practical importance of the high specific heat capacity of water A substance with high specific heat capacity, such as water, a large amount of energy is needed to raise its temperature by a little amount. Its temperature is relatively stable. In contrast, a substance with low specific heat capacity, such as copper, only a little amount of energy is needed to raise its temperature by a large amount. Its temperature is relatively unstable. Specific heat capacity of water is high (c = 4200 Jkg1 oC1) ¾ coolant in motor car and central air conditioning system ¾ maintenance of body temperature even when the surrounding temperature changes sharply ¾ mild weather in coastal area Each object is heated separately with the same heater for the same period of time. Which of the following object will have the greatest increase in temperature? (Given: Specific heat capacity of copper = 400 Jkg1 oC1 Specific heat capacity of water = 4200 Jkg1 oC 1) A. 1 kg of copper B. 5 kg of copper C. 1 kg of water D. 5 kg of water The question requires us to compare different objects instead of different materials. i.e. heat capacity should be considered, NOT specific heat capacity. heat capacity (J oC 1) A. 400 B. 2000 C. 4200 D. 21000 smallest heat capacity, largest increment largest heat capacity, smallest increment Answer: A 4 1.1 Temperature, Heat and Internal Energy 4. Experiment Determine the specific heat capacity of water Schematic diagram Equation: c Q m'T Sources of error Underestimate the specific heat capacity ¾ water spills out ¾ stir water vigorously Overestimate the specific heat capacity ¾ heat loss to surroundings ¾ heat requires to heat up the apparatus ¾ the heater is not totally immersed in water ¾ final temperature is taken once the heater is switched off Precautions ¾ to reduce heat loss, polystyrene cup with lid should be used ¾ to ensure uniform temperature, water should be stirred gently throughout the experiment ¾ to reflect the actual temperature, the bulb of thermometer should not be placed too close to heater Determine the specific heat capacity of copper Schematic diagram immersion heater Equation: c Q m'T 5
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