NPTEL – Chemistry and Biochemistry – Coordination Chemistry (Chemistry of transition elements) Point Groups and Molecular Symmetry K.Sridharan Dean School of Chemical & Biotechnology SASTRA University Thanjavur – 613 401 Page 1 of 8 Joint Initiative of IITs and IISc – Funded by MHRD NPTEL – Chemistry and Biochemistry – Coordination Chemistry (Chemistry of transition elements) Table of Contents 1 Point groups and molecular symmetry ........................................................................................ 3 1.1 Point group ...................................................................................................................... 3 1.2 What is the need of point group? ................................................................................... 3 1.3 How to assign the point group to a molecule? ........................................................... 4 2. Flow chart for deriving the point group of a molecule ............................................................... 5 3. Derivation of point group of molecules ...................................................................................... 7 4. References ................................................................................................................................... 8 Page 2 of 8 Joint Initiative of IITs and IISc – Funded by MHRD NPTEL – Chemistry and Biochemistry – Coordination Chemistry (Chemistry of transition elements) 1 Point groups and molecular symmetry 1.1 Point group Symmetry operations generated by the symmetry elements present in a molecule form a symmetry group or a point group. 1.2 What is the need of point group? It is a simple way of labeling a molecule and a short hand description of the molecule. It is very much useful in probing the properties of a molecule. Example 1: The point group of [FeCl 4 ]- is T d . It means that the complex ion is having tetrahedral shape as shown in Figure 1.2.1. We can predict the spectral transition of this ion from its shape. Cl Fe Cl Cl Cl Fig 1.2.1 [FeCl 4 ]- ion, T d Example 2: The point group of [PtCl 4 ]2- is D 4h . It means that this complex ion has square planar geometry.as shown in Figure 1.2.2 Cl Cl Pt Cl Cl Fig 1.2.2 PtCl 4 ion, D 4h Example 3: Page 3 of 8 Joint Initiative of IITs and IISc – Funded by MHRD NPTEL – Chemistry and Biochemistry – Coordination Chemistry (Chemistry of transition elements) This molecule has the point group C 2v . This molecule has a butterfly structure as shown in Figure 1.2.3 Cl Cl Te Cl Cl Fig 1.2.3 TeCl 4 , C 2v 1.3 How to assign the point group to a molecule? Step 1: Get the shape of the molecule Step 2: Find out all the symmetry elements Step 3: Follow the flow chart to get the point group Page 4 of 8 Joint Initiative of IITs and IISc – Funded by MHRD NPTEL – Chemistry and Biochemistry – Coordination Chemistry (Chemistry of transition elements) 2. Flow chart for deriving the point group of a molecule Start Is C ∞ present? Yes No Is i present? Is C n present? yes No D ∞h No I Cs, Ci, C1 Yes No Is 6C 5 present? Yes C ∞v i? Yes O No Ih No i? Yes Is 3C 4 present? Yes Oh Td Yes 6σ? No N No i? Yes Is 4C 3 present? Y T Th B No No nC 2 ┴ C n ? Yes A Page 5 of 8 Joint Initiative of IITs and IISc – Funded by MHRD NPTEL – Chemistry and Biochemistry – Coordination Chemistry (Chemistry of transition elements) A D nh yes B Is σ h present? Is S 2n present? No D nd Y Y S 2n No Is nσ v present? Is σ h present? No Y C nh Dn No Cn No Is nσ v present? Y C nv Page 6 of 8 Joint Initiative of IITs and IISc – Funded by MHRD NPTEL – Chemistry and Biochemistry – Coordination Chemistry (Chemistry of transition elements) 3. Derivation of point group of molecules Example 1: PF 5 Outermost electronic configuration of P is 3s23p3 Number of valence electrons =5 Number of electrons from five F = 5 Total number of electrons = 10 Number of bond pairs = 10/2 = 5 Hence, the shape of PF 5 is trigonal bipyramid C3 C2 F F F P F C2' σh F C2" 1. 2. 3. 4. C 3 axis is present Three C 2 axes ┴ the principal axis, C 3 σ h plane is present Hence, the point group is D 3h Example 2: H 2 O Outermost electronic configuration of oxygen = 2s22p4 Number of valence electrons of oxygen =6 Number of electrons from two hydrogens = 2 Total number of electrons =8 Page 7 of 8 Joint Initiative of IITs and IISc – Funded by MHRD NPTEL – Chemistry and Biochemistry – Coordination Chemistry (Chemistry of transition elements) Total number of electron pairs = 8/2 = 4 Number of bond pairs = 2 Number of bond pairs = 4-2 = 2 Structure is tetrahedral and two lone pairs occupy two corners of the tetrahedron and the shape is V C2 σv O H H σv' 1. C 2 axis is present 2. Two σ v planes 3. Hence, the point group is C 2v 4. References 1. “Inorganic Chemistry: Principles of Structure and Reactivity”, James E.Huheey, Ellen A.Keiter, Richard L.Keiter, Okhil K.Medhi, Pearson Education, Delhi, 2006 2. ‘Chemical Applications of Group Theory”, 2/e, F.Albert Cotton, Wiley Eastern, New Delhi, 1986 Page 8 of 8 Joint Initiative of IITs and IISc – Funded by MHRD
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