MTH 095 - May 6, 2009 1. Today we will . . . - see how to use factoring to solve equations (5.8) - take the HW Quiz over 7.2, 7.3, 5.4 - 5.6 (both assignments) 2. Friday we will do Activity #3 3. Monday we will go over 5.7 and 5.8 HW and review for the Mod 3 Test Sec 5.8 is the last one in this mod! DEADLINE for Mod 3 Test is Friday, May 15. Jan 45:52 PM ONE MORE EXAMPLE FROM 5.7 Sometimes more than one type of factoring must be used. Example: Factor the following polynomials. (a) 8y3 - 50y (b) 6x2 - 12x + 6 May 59:21 AM 1 Sec 5.8: Solving Equations by Factoring and Problem Solving One reason to factor polynomials is that it allows us to solve certain kinds of equations. This technique depends on a special property of zero called the zero-factor property. May 19:48 AM Let's use the zero-factor property to solve some equations. Example: Solve: (a) (x - 4)(x + 2) = 0 (b) (3x + 8)(x -1)(2x + 1) = 0 May 69:40 AM 2 If the equation is not already factored, we may have to factor first. Example: Solve: (a) x2 - 2x - 15 = 0 (b) x2 + 5x + 6 = 0 May 69:42 AM Example: Solve: (a) y2 - 10y + 24 = 0 (b) 3y2 - y - 14 = 0 May 69:43 AM 3 We may also have to get the equation into the proper form before factoring. Example: Solve: (a) x2 - 12x = -20 (b) n(2n - 3) = 2 May 69:44 AM One special application of factoring involves the Pythagorean Theorem, which describes how the sides of a right triangle are related. May 69:46 AM 4 EXAMPLE: Suppose that the longer leg of a right triangle is 4 feet longer than the other leg. If the hypotenuse is 20 feet long, find the lengths of the two legs. May 69:48 AM 5 Attachments Student Guide to Online Math Help Spring 2009.pdf
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