Bell Quiz 8-4 Factor the expression. 5 pts 1. 10x – 5x2 5 pts 2. x2 – 2x – 48 10 pts possible Section 8-5 1 8-5 Chapter 8: Rational Functions Section 8-5 2 8-5 Chapter 8: Rational Functions Section 8-5 3 Key Concept Adding or Subtracting with Like Denominators To add or subtract rational expressions with like denominators, simply add (or subtract) their numerators and carry the denominator across the equal sign. Property: ࢇ ࢉ ࢈ ࢉ ൌ ࢇା࢈ ࢉ Example: ൌ ା ൌ __________________________________________________ Property: ࢇ ࢉ ࢈ ࢉ െ ൌ ࢇି࢈ ࢉ Example: Section 8-5 ࢞ ࢞ ૠ ࢞ ൌ ࢞ାૠ ࢞ 4 EXAMPLE 1 Add or subtract with like denominators Perform the indicated operation. a. 7 + 3 b. 2x – 5 x+6 x+6 4x 4x Section 8-5 5 EXAMPLE 1 Add or subtract with like denominators Perform the indicated operation. a. 7 + 3 b. 2x – 5 x+6 x+6 4x 4x SOLUTION a. 7 + 3 = 7 + 3 = 10 = 5 4x 4x 2x 4x 4x Add numerators and simplify result. b. 2x – 5 = 2x – 5 x+6 x+6 x+6 Subtract numerators. Section 8-5 6 GUIDED PRACTICE for Example 1 Perform the indicated operation and simplify. a. 7–5 = 2 = 1 7 – 5 = 12x 12x 6x 12x 12x Subtract numerators and simplify results . b. 2+1 = 3 = 1 2 + 1 = 3x2 3x2 x2 3x2 3x2 Add numerators and simplify results. c. 4x–x = 3x = 3x Subtract numerators. 4x – x = x–2 x–2 3x – 2 x–2 x–2 Factor numerators and simplify results . d. 24x + 22 = 4x2 + 2 x +1 x +1 x +1 Section 8-5 7 Key Concept Adding or Subtracting with Unlike Denominators To add (or subtract) two rational expressions with unlike denominators, find a common denominator. Rewrite each rational expression using the common denominator. Then add (or subtract). You can always find a common denominator by multiplying the 2 denominators together. Property ௗ ൌ ௗ ௗ ௗ ൌ ௗା ௗ Section 8-5 ௗ െ ൌ ௗ ௗ െ ௗ ൌ ௗି ௗ 8 EXAMPLE 2 Find a least common multiple (LCM) Find the least common multiple of 4x2 –16 and 6x2 –24x + 24. Section 8-5 9 EXAMPLE 2 Find a least common multiple (LCM) Find the least common multiple of 4x2 –16 and 6x2 –24x + 24. SOLUTION STEP 1 Factor each polynomial. Write numerical factors as products of primes. 4x2 – 16 = 4(x2 – 4) = (22)(x + 2)(x – 2) 6x2 – 24x + 24 = 6(x2 – 4x + 4) = (2)(3)(x – 2)2 Section 8-5 10 EXAMPLE 2 Find a least common multiple (LCM) STEP 2 Form the LCM by writing each factor to the highest power it occurs in either polynomial. LCM = (22)(3)(x + 2)(x – 2)2 = 12(x + 2)(x – 2)2 Section 8-5 11 EXAMPLE 3 Add with unlike denominators x Add: 7 + 9x2 3x2 + 3x Section 8-5 12 EXAMPLE 3 Add with unlike denominators x Add: 7 + 9x2 3x2 + 3x SOLUTION To find the LCD, factor each denominator and write each factor to the highest power it occurs. Note that 9x2 = 32x2 and 3x2 + 3x = 3x(x + 1), so the LCD is 32x2 (x + 1) = 9x2(x 1 1). 7 7 + x x Factor second denominator. = + 9x2 3x(x + 1) 9x2 3x2 + 3x 7 9x2 x+1 x + x + 1 3x(x + 1) 3x 3x LCD is 9x2(x + 1). Section 8-5 13 EXAMPLE 3 Add with unlike denominators 3x2 7x + 7 = 9x2(x + 1)+ 9x2(x + 1) Multiply. 2 + 7x + 7 3x = 9x2(x + 1) Add numerators. Section 8-5 14 EXAMPLE 4 Subtract: Subtract with unlike denominators x + 2 – –2x –1 2x – 2 x2 – 4x + 3 Section 8-5 15 EXAMPLE 4 Subtract with unlike denominators x + 2 – –2x –1 2x – 2 x2 – 4x + 3 Subtract: SOLUTION x+2 – 2x – 2 x+2 = 2(x – 1)– x+2 = 2(x – 1) –2x –1 x2 – 4x + 3 – 2x – 1 (x – 1)(x – 3) Factor denominators. x – 3 – – 2x – 1 2 x – 3 (x – 1)(x – 3) 2 2–x–6 x – 4x – 2 = 2(x – 1)(x – 3) – 2(x – 1)(x – 3) Section 8-5 LCD is 2(x − 1)(x − 3). Multiply. 16 EXAMPLE 4 Subtract with unlike denominators 2 – x – 6 – (– 4x – 2) x = 2(x – 1)(x – 3) Subtract numerators. 2 + 3x – 4 x = 2(x – 1)(x – 3) Simplify numerator. (x –1)(x + 4) = 2(x – 1)(x – 3) Factor numerator. Divide out common factor. x+4 = 2(x –3) Simplify. Section 8-5 17 GUIDED PRACTICE for Examples 2, 3 and 4 Find the least common multiple of the polynomials. 5. 5x3 and 10x2–15x Section 8-5 18 GUIDED PRACTICE for Examples 2, 3 and 4 Find the least common multiple of the polynomials. 5. 5x3 and 10x2–15x STEP 1 Factor each polynomial. Write numerical factors as products of primes. 5x3 = 5(x) (x2) 10x2 – 15x = 5(x) (2x – 3) STEP 2 Form the LCM by writing each factor to the highest power it occurs in either polynomial. LCM = 5x3 (2x – 3) Section 8-5 19 GUIDED PRACTICE for Examples 2, 3 and 4 Find the least common multiple of the polynomials. 6. 8x – 16 and 12x2 + 12x – 72 Section 8-5 20 GUIDED PRACTICE for Examples 2, 3 and 4 Find the least common multiple of the polynomials. 6. 8x – 16 and 12x2 + 12x – 72 STEP 1 Factor each polynomial. Write numerical factors as products of primes. 8x – 16 = 8(x – 2) = 23(x – 2) 12x2 + 12x – 72 = 12(x2 + x – 6) = 4 3(x – 2 )(x + 3) STEP 2 Form the LCM by writing each factor to the highest power it occurs in either polynomial. LCM = 8 3(x – 2)(x + 3) = 24(x – 2)(x + 3) Section 8-5 21 GUIDED PRACTICE 7. 3 – 4x 8. for Examples 2, 3 and 4 = 1 7 21 – 4x 28x x 1 + 3x2 9x2 – 12x x2 + 3x – 4 3x2 (3x – 4) Section 8-5 22 GUIDED PRACTICE 9. for Examples 2, 3 and 4 x 5 + 12x – 48 x2 – x – 12 = Section 8-5 17x + 15 12(x +3)(x - 4) 23 HOMEWORK Sec 8-5 (pg 586) 3-30 every 3rd, 41 Section 8-5 24
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