11.7 Solve by Factoring With Coefficient Not 1
Name ___________________________
Learning Objective: A.SSE.2
I will rewrite a trinomial with a coefficient NOT 1 into factored form
A.SSE.3
I will find the factors of a quadratic function and then solve to find the zeros
A.APR.3
I will factor a quadratic function to determine the zeros
A.REI.4
I will solve a quadratic equation by factoring first with a trinomial with a coefficient not 1
F.IF.8
I will use factoring to find the zeros of a quadratic function
Solve each quadratic equation by factoring and applying the Zero-Product Property.
1. 6x2 – 5x – 4 = 0
2. 12x2 – 8x – 7 = 0
3. 5x2 + 28x – 12 = 0
4. 2x2 – 11x – 40 = 0
5. 2x2 + 21x – 11 = 0
6. 8x2 – 14x + 3 = 0
7. 3x2 + 2x – 21 = 0
8. 6x2 + 11x – 2 = 0
9. 5x2 + 17x – 12 = 0
Solve each equation by factoring first.
10. 6n2 – 24n = 0
11. 81x2 – 25 = 0
12. 24x2 – 4x – 30x + 5 = 0
13. x2 – 4x – 32 = 0
14. x2 + 14x + 40 = 0
15. 3x2 + 6x – 45 = 0
Answers: 1. (2x + 1)(3x – 4) = 0, x = 
1
4
,x=
2
3
3. (5x – 2)(x + 6) = 0, x =
2
, x = –6
5
1
7
, x = –11 7. (3x – 7)(x + 3) = 0, x = , x = –3
3
2
3
5
9. (5x – 3)(x + 4) = 0, x = , x = –4 11. (9x + 5)(9x – 5) = 0, x = 
9
5
–
2
13. (x + 4)(x – 8) = 0, x = 4, x = 8 15. 3(x + 2x – 15) = 0, 3(x + 5)(x – 3) = 0, x = –5, x = 3
5. (2x – 1)(x + 11) = 0, x =