Name___________KEY_________________________
Period_____
Practice with Solubility Rules & Dissociation
For each of the following substances write the correct formula and whether they will dissociate (i.e soluble)
or not in water. To indicate phase, use the letters (aq) for substances that dissolve in water and use the letters
(s=solid) (l=liquid) (g=gas) as appropriate for the substances that remain as molecules. Use your resources
to determine the solubility of salts.
Substance
Formula
Dissociation equation
(aq)=soluble
(s), (l), (g) = molecule
or insoluble
Sodium hydroxide
NaOH(aq)
NaOH(s) Na+(aq) + OH-(aq)
Copper (II) chloride
CuCl2(aq)
CuCl2(s) Cu2+(aq) + 2Cl-(aq)
Mercury (I) sulfate
Hg2SO4(s)
N/A
Potassium carbonate
K2CO3(aq)
K2CO3(s) K+(aq) + CO32-(aq)
Sulfuric acid
H2SO4(aq)
H2SO4(s) H+(aq) + SO42-(aq)
water
H2O(l)
N/A
Lead (II) nitrate
Pb(NO3)2(aq)
Pb(NO3)2(s) Pb2+(aq) + 2NO3-(aq)
Silver chloride
AgCl(s)
N/A
Sodium acetate
NaC2H3O2(aq)
NaC2H3O2(s) Na+(aq) + C2H3O2-(aq)
Barium sulfate
BaSO4(s)
N/A
Magnesium nitrate
Mg(NO3)2(aq)
Mg(NO3)2(s) Mg2+(aq) + 2NO3-(aq)
Perchloric acid
HClO4(aq)
HClO4(s) H+(aq) + ClO4-(aq)
Tin (IV) sulfide
SnS2(s)
N/A
Aluminum phosphate
AlPO4(s)
N/A
Lead (II) iodide
PbI2(s)
N/A
Sodium permanganate
NaMnO4(aq)
NaMnO4(s) Na+(aq) + MnO4-(aq)
Strontium sulfate
SrSO4(s)
N/A
Carbon dioxide
CO2(g)
N/A
Hydrogen gas
H2(g)
N/A
Lithium oxide
Li2O(aq)
Li2O(s) Li+(aq) + O2-(aq)
Calcium hydroxide
Ca(OH)2(s)
N/A
Hydrochloric acid
HCl(aq)
HCl(s) H+(aq) + Cl-(aq)
Lead (II) fluoride
PbF2(s)
N/A
Mercury (I) nitrate
Hg2(NO3)2(aq)
Hg2(NO3)2(s) Hg22+(aq) + 2NO3-(aq)
Barium acetate
Ba(C2H3O2)2(aq)
Ba(C2H3O2)2(s) Ba2+(aq) + 2C2H3O2-(aq)
Practice with Net Ionic Equations
Write the molecular, total ionic and net ionic forms of the following equations. If all species are spectator ions,
please indicate that no reaction takes place. Note: you need to make sure the original equation is balanced
before proceeding! Use your resources to determine solubility rules.
1. silver nitrate(aq) + potassium chloride(aq) 
Molecular: AgNO3 (aq) + KCl (aq)  AgCl (s) + KNO3 (aq)
Total Ionic: Ag+ (aq) + NO3¯ (aq) + K+ (aq) + Cl¯ (aq)  AgCl (s)
Net Ionic:
Ag+ (aq) + Cl¯ (aq)  AgCl (s)
+ K+ (aq) + NO3¯ (aq)
2. nickel(III)nitrate(aq) + potassium bromide(aq) 
Molecular: Ni(NO3)3 (aq) + 3 KBr (aq)  NiBr3 (aq) + 3 KNO3 (aq)
Total Ionic: Ni3+ (aq) + 3 NO3¯ (aq) + 3 K+ (aq) + 3 Br¯ (aq)  Ni3+ (aq) + 3 NO3¯ (aq) + 3 K+ (aq) + 3 Br¯ (aq)
Net Ionic: No Reaction
3. Potassium phosphate + aluminum nitrate 
Molecular: K3PO4 (aq) + Al(NO3)3 (aq)  AlPO4 (s) + 3 KNO3 (aq)
Total Ionic: 3 K+ (aq) + PO43- (aq) + Al3+ (aq) + 3 NO3¯ (aq)  AlPO4 (s) + 3 K+ (aq) + 3 NO3¯ (aq)
Net Ionic: Al3+ (aq) + PO43- (aq)  AlPO4 (s)
4. strontium bromide(aq) + potassium sulfate(aq) 
Molecular: SrBr2 (aq) + K2SO4 (aq)  SrSO4 (s) + 2 KBr (aq)
Total Ionic: Sr2+ (aq) + 2 Br¯ (aq) + 2 K+ (aq) + SO42- (aq)  SrSO4 (s) + 2 K+ (aq) + 2 Br¯ (aq)
Net Ionic: Sr2+ (aq) + SO42- (aq)  SrSO4 (s)
5. lithium hydroxide(aq) + hydrobromic acid(aq) 
Molecular: LiOH (aq) + HBr (aq)  H2O (l) LiBr (aq)
Total Ionic: Li+ (aq) + OH¯ (aq) + H+ (aq) + Br¯ (aq) H2O(l) + (aq) + Li+ (aq) + Br¯ (aq)
Net Ionic: H+ (aq) + OH- (aq)  H2O(l)
6. manganese(II)chloride + ammonium carbonate 
Molecular: MnCl2 (aq) + (NH4)2CO3 (aq)  MnCO3 (s) + 2 NH4Cl (aq)
Total Ionic: Mn2+ (aq) + 2 Cl¯ (aq) + 2 NH4+ (aq) + CO32- (aq)  MnCO3 (s) + 2 NH4+ (aq) + 2 Cl¯ (aq)
Net Ionic: Mn2+ (aq) + CO32- (aq)  MnCO3 (s)
7. chromium(III)nitrate + iron(II)sulfate 
Molecular: 2 Cr(NO3)3 (aq) + 3 FeSO4 (aq)  3 Fe(NO3)2 (aq) + Cr2(SO4)3 (aq)
Total Ionic: 2 Cr3+(aq)+6 NO3¯(aq)+ 3 Fe2+(aq) + 3 SO42-(aq)  2 Cr3+(aq) + 6 NO3¯(aq) + 3 Fe2+(aq)+3 SO42- (aq)
Net Ionic: No Reaction

8. acetic acid + strontium hydroxide 
Molecular: 2HC2H3O2 (aq) + Sr(OH)2 (aq)  2H2O (l) + Sr(C2H3O2)2 (aq)
Total Ionic: 2H+ (aq) + 2 C2H3O2¯ (aq) + Sr2+ (aq) + 2OH- (aq) 2H2O(l) + Sr2+ (aq) + 2 C2H3O2¯ (aq)
Net Ionic: 2H+ (aq) + 2OH- (aq) 2H2O(l) simplifies to: H+ (aq) + OH- (aq)  H2O(l)
9. calcium hydroxide + iron(III)chloride 
Molecular: 3 Ca(OH)2 (aq) + 2 FeCl3 (aq)  3 CaCl2 (aq) + 2 Fe(OH)3 (s)
Total Ionic: 3 Ca2+ (aq) + 6 OH¯ (aq) + 2 Fe3+ (aq) + 6 Cl¯ (aq)  3 Ca2+ (aq) + 6 Cl¯ (aq) + 2 Fe(OH)3 (s)
Net Ionic: 2 Fe3+ (aq) + 6 OH¯ (aq)  2 Fe(OH)3 (s) simplifies to: Fe3+ (aq) + 3 OH¯ (aq)  Fe(OH)3 (s)