Macroscopic Atoms In this lab activity, an analogy will be made between atoms and legos. The different colors of legos will represent different elements; the tan legos will have an element symbol T, and the grey legos element symbol G. The goal of this activity is to establish a familiarity with the concept of a mole and Avogadro’s number (both of which attempt to quantify particles at the atomic scale that we can’t see), by working with objects that we can visualize and see immediately before us. CHEMISTRY WORLD LEGO WORLD In chemistry, 1 mole is defined to be the number In lego land, 1 lole is defined to be the number of of atoms in 12 g of C-12. This is a useful, but legos in 12.06 g of G (grey legos). This will be the arbitrary reference standard. arbitrary reference standard for counting legos. 1 mole = Number of atoms in 12 g of C-12 With this definition, the mole specifies 6.022 x 1023 of any object in the chemical world: 1 mole of Mg 1 mole of Cl = 6.022 x 1023 atoms of Mg = 6.022 x 1023 atoms of Cl Since each individual carbon atom has a different mass from the magnesium or chlorine atoms, 1 mole of these elements will also have different masses. The molar mass indicates the number of grams present per mole (g/mol) of the chemical substance: Molar mass of Mg Molar mass of Cl = 24.30 g/mol = 35.45 g/mol 1 lole = Number of legos in 12.06 g of G Based on this definition, one lole specifies 28 of any object in lego world: 1 lole of G 1 lole of T = 28 grey legos = 28 tan legos Since each individual grey lego has a different mass from the tan or blue legos, 1 lole of these legos will also have different masses. The lolar mass indicates the number of grams present per lole (g/lol) of the substance: Lolar mass of T Lolar mass of G = 9.77 g/lol = 12.06 g/lol CHEMISTRY WORLD LEGO WORLD 1. Determine the total mass of magnesium (Mg) provided in the small vial. 1. Determine the total mass of the tan legos (T) provided in the small beaker. Mass of Mg (g):_____________________________ Mass of T (g): _____________________________ 2. Using the molar mass of Mg as a conversion factor, calculate the number of moles of Mg present in Step 1 above. 2. Using the lolar mass of T as a conversion factor, calculate the number of loles of T in Step 1 above. Moles of Mg: Loles of T: 3. Using Avogadro’s number as a conversion factor, calculate the number of atoms of Mg present in the number of moles from Step 2 above. 3. Using “Legogadro’s” number (1 lol = 28 legos) as a conversion factor, calculate the number of tan legos (T) present in the number of loles from Step 2 above. Number of Mg atoms: Number of T legos: 4. Consider the chemical reaction below: One atom of magnesium (Mg) combines with two atoms of chlorine (Cl) to form the ionic compound magnesium chloride (MgCl2): 4. Consider the lego reaction below: One tan lego (T) combines with two grey legos (G) to form a lego compound of TG2: Mg + Cl2 → MgCl2 Following the chemical reaction above, how many chlorine atoms (Cl) would be needed to combine with the amount of magnesium you weighed out in Step 1? Convert this to moles of chlorine atoms. Number of Cl atoms: Number of moles of Cl atoms: T + 2 G → TG2 Following the lego reaction above, how many grey blocks (G) would be needed to combine with the amount of tan blocks you weighed out in Step 1? Convert this to loles of grey legos. Number of G legos: Number of loles G legos: 5. Using the molar mass of Cl as a conversion factor, how many grams of Cl atoms would combine with the Mg from Step 1? 5. Using the lolar mas of G as a conversion factor, how many grams of G would combine with the T from Step 1? Mass of Cl (g): Mass of G (g): Summary of Steps 1-5: A sample of magnesium (Mg) was weighed. Using relative atomic masses, the mass of chlorine (Cl) needed to combine with this magnesium (Mg) to form MgCl2 was calculated. Summary of Steps 1-5: A sample of tan legos (T) was weighed. Using the relative mass of the legos, the mass of grey legos (G) needed to combine with these tan legos (T) to form TG2 was calculated. 6. Now weigh out the mass of grey legos (G) you calculated in Step 5 above. Using this sample of G, connect them to the tan legos you weighed (from Step 1) to form lego molecules with the formula TG2. Did you have the right number of each lego to fully form TG2 without any legos leftover unreacted? 7. Of course, we could have chosen to simply count out the number of tan legos (T) we had at the start, double that number, and then count of the necessary number of grey legos (G) to make the combination TG2. That method would allow us to avoid the analytical balance altogether. Why do we have to measure and calculate the masses of magnesium and chlorine to combine them in the right particle ratio? In other words, why can’t we just count out the number of each atoms of each element needed for the chemical reaction?
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