[email protected] the following chart suggests that x' does not equal x ­ vt One point P... in one frame erroneously gets assigned two different coordinations. Call that point either x or x' or P...it is but one point in S and can have but one and only one coordination allowed per point..
1 the point x in S is at ( x, 0 )
2 the point x' in S is at ( x­vt, 0 ) This establishes the equation...
x = x ­ vt which obviously is only correct when t = 0. This is done by Einstein's mathematical sleight of hand !
His allowance of a second coordination for the same point in the same frame, is cloaked in deception, and has traditionally been very, very difficult to spot.
Indeed motion as well as time can be ignored, by letting VT = D,
[ Velocity times Time = Distance ]
and still the inequality persists. X = X' + D, since once again, point X' in S is point X is point P. He neither tranforms a point nor a coordinete...indeed he transforms a mere line segment length into S. This x' distance in S must begin from the origin and not be counted off backwards from point P.
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