EZO-IX (UT-192) EZO-IX (UT-192) ¶ß±Ó¬fl¡ ¬Û±Í¬Sê˜ ( B.D.P.) ø˙鬱¬ı¯∏«±ôL ¬Û¬ı˛œé¬± ( Term End Examination ) øÎ¬À¸•§¬ı˛, 2013 › Ê≈√Ú, 2014 ‹ø26√fl¡ ¬Û±Í¬Sê˜ ( Elective ) ‡¡] ŒS걘±ÀȬ±¢∂±˜ fl¡±Àfl¡ ¬ıÀ˘ ∑ Œfl¡±Úƒ ŒS걘±ÀȬ±¢∂±øÙ¬ÀÓ¬ ¤øÈ¬ ¬ı…¬ı˝√√±¬ı˛ fl¡¬ı˛± ˝√√˚˛ ∑ ¤¬ı˛ ¸±˝√√±À˚… ∆Ê√¬ı ’Ì≈¬ı˛ ¬Û‘Ôfl¡œfl¡¬ı˛Ì ¬ÛXøÓ¬øÈ¬ ø‰¬S¸˝√√fl¡±À¬ı˛ ¬ı̫ڱ fl¡èÚ º 2+1+7 õ∂±Ìœø¬ı√…± ( Zoology ) ·¡] Ú¬ı˜ ¬ÛS ( 9th Paper : Biophysics and Biometry ) ¸˜˚˛ – ≈√˝◊√ ‚KI◊± ¬ ۔̫˜±Ú – 50 Time : 2 hours 2 ¶®…±øÚ— ’Ì≈¬ıœé¬Ì ˚ÀLa¬ı˛ ø¬ıøˆ¬iß ’—À˙¬ı˛ Ú±˜ › Ó¬±À√¬ı˛ fl¡±˚«õ∂̱˘œ ø‰¬S¸˝√√fl¡±À¬ı˛ ά◊À~‡ fl¡èÚ º ¤˝◊√ ’Ì≈¬ıœé¬ÀÌ ¬Û˚«À¬ıé¬À̬ı˛ ¬Û”À¬ı« ¬ıdÀfl¡ øfl¡ˆ¬±À¬ı q©® fl¡¬ı˛± ˝√√˚˛ ∑ q©® Full Marks : 50 ¬ıd-Ú˜≈Ú±¬ı˛ ›¬Û¬ı˛ øfl¡ øfl¡ Ò±Ó≈¬¬ı˛ õ∂À˘¬Û Œ√›˚˛± ˝√√˚˛ ∑ [ ˜±ÀÚ¬ı˛ &èQ – 70% ] 7+2+1 Weightage of Marks : 70% ¬¬Ûø¬ı˛ø˜Ó¬ › ˚Ô±˚Ô Î¬◊M√À¬ı˛¬ı˛ Ê√Ú… ø¬ıÀ˙¯∏ ˜”˘… Œ√›˚˛± ˝√√À¬ıº ’qX ¬ı±Ú±Ú, ’¬Ûø¬ı˛26√ißÓ¬± ¤¬ı— ’¬Ûø¬ı˛©®±¬ı˛ ˝√√ô¶±é¬À¬ı˛¬ı˛ Œé¬ÀS Ú•§¬ı˛ Œfl¡ÀȬ ŒÚ›˚˛± ˝√√À¬ıº ά◊¬Û±ÀôL õ∂Àùü¬ı˛ ˜”˘…˜±Ú ¸”ø‰¬Ó¬ ’±ÀÂ√º Special credit will be given for precise and correct answer. Marks will be deducted for spelling mistakes, untidiness and illegible handwriting. The figures in the margin indicate full marks. ø¬ıˆ¬±· - fl¡ 1º 10 × 1 = 10 ŒÙ¬Êƒ√ fl¡Ú¬∏C±à ’Ì≈¬ıœé¬Ì ˚La fl¡±Àfl¡ ¬ıÀ˘ ∑ ¤˝◊√ ’Ì≈¬ıœé¬Ì ˚ÀLa¬ı˛ ˜”˘ÚœøÓ¬ øfl¡ ∑ ŒÙ¬Ê√ƒ fl¡Ú¬∏C±à ’Ì≈¬ıœé¬À̬ı˛ fl¡±˚«¬ÛXøÓ¬ ø‰¬S¸˝√√ ¬ı̫ڱ fl¡èÚ º 2+2+6 B.Sc-5656-Y Œ˚-Œfl¡±ÀÚ± ¤fl¡øÈ¬¬ õ∂Àùü¬ı˛ ά◊M√¬ı˛ ø˘‡≈Ú – [ ¬ÛÀ¬ı˛¬ı˛ ¬Û‘ᬱ˚˛ ^©Ü¬ı… 10 × 1 = 10 [fl¡] ¬Ûø¬ı˛¸—‡…± øÚÀ¬ı˙Ú ¬ı˘ÀÓ¬ øfl¡ Œ¬ı±Á¡±˚˛ ∑ ά◊√±˝√√¬ı˛Ì¸˝√√ Œ|Ìœ¬ıX ¬Ûø¬ı˛¸—‡…± øÚÀ¬ı˙ÀÚ¬ı˛ ø¬ıøˆ¬iß ∆¬ıø˙©Ü…&ø˘ ø¬ıÀù≠¯∏Ì fl¡èÚ º ¬Ûø¬ı˛¸—‡…± øÚÀ¬ı˙ÀÚ¬ı˛ ≈√øÈ¬ ¸≈ø¬ıÒ± › ≈√øÈ¬ ’¸≈ø¬ıÒ± ά◊À~‡ fl¡èÚ º Œ˚-Œfl¡±ÀÚ± ¤fl¡øÈ¬ õ∂Àùü¬ı˛ ά◊M√¬ı˛ ø˘‡≈Ú – fl¡] 2º 1+6+3 [‡] ¬ÚœÀ‰¬ 16 Ê√Ú ¬ı…øMê√¬ı˛ ∆√ø˝√√fl¡ ›Ê√Ú Œ√›˚˛± ˝√√˘º ¤¬ı˛ ŒÔÀfl¡ ·Î¬ˇ ∆√ø˝√√fl¡ ›Ê√Ú › ¸˜fl¡ ø¬ı‰≈¬…øÓ¬ øÚÌ«˚˛ fl¡èÚ º 52, 65, 55, 60, 62, 58, 57, 61, 59, 60, 61, 62, 67, 48, 54 ¤¬ı— 63 º B.Sc-5656-Y 2+8 3 3º 4º EZO-IX (UT-192) [·] ’±˚˛Ó¬À˘‡ fl¡±Àfl¡ ¬ıÀ˘ ∑ ¤¬ı˛ ¸≈ø¬ıÒ± › ’¸≈ø¬ıÒ±&ø˘ øfl¡ øfl¡ ∑ ÚœÀ‰¬ ¤fl¡øÈ¬ ¬Û≈fl≈¡À¬ı˛ ά◊¬Ûø¶öÓ¬ fl¡±Ó¬˘± ˜±ÀÂ√¬ı˛ ∆√‚«… › Ó¬±À√¬ı˛ ¸—‡…± Œ√›˚˛± ˝√√˘ º ¬ı˛±ø˙Ó¬Ô…øÈ¬Àfl¡ ¤fl¡øÈ¬ ’±˚˛Ó¬À˘À‡¬ı˛ ¸±˝√√±À˚… õ∂fl¡±˙ fl¡èÚ – fl¡±Ó¬˘± ˜±ÀÂ√¬ı˛ ∆√‚«… ˜±ÀÂ√¬ı˛ ¸—‡…± [ Œ|Ìœ õ∂¸±¬ı˛ ] [ Œ|Ìœ ¬Ûø¬ı˛¸—‡…± ] 15 3·5 - 6·5 ˝◊√ø= 23 6·5 - 9·5 ˝◊√ø= 28 9·5 - 12·5 ˝◊√ø= 10 12·5 - 15·5 ˝◊√ø= 35 15·5 - 18·5 ˝◊√ø= 2+3+5 ø¬ıˆ¬±· - ‡ Œ˚-Œfl¡±ÀÚ± ¤fl¡øÈ¬ õ∂Àùü¬ı˛ ά◊M√¬ı˛ ø˘‡≈Ú – 6 × 1=6 [fl¡] ’±À˘±fl¡ ’Ì≈¬ıœé¬Ì ˚ÀLa¬ı˛ ø¬ıÀù≠¯∏fl¡ ¬é¬˜Ó¬± fl¡±Àfl¡ ¬ıÀ˘ ∑ ¤øÈ¬ øfl¡ˆ¬±À¬ı øÚÌ«˚˛ fl¡¬ı˛± ˚±˚˛ ∑ ø¬ıÀù≠¯∏Ì ˜±S±¬ı˛ ¸±ÀÔ ¤¬ı˛ ¸•Ûfl«¡ øfl¡ ∑ 2 + 3 +1 [‡√√¡√] Ó¬±¬Û·øÓ¬¸—Sê±ôL õ∂Ô˜ ¸”SøÈ¬¬ı˛ ¬ı…±‡…± fl¡èÚº ë¤ÚÔ…±˘ƒø¬Ûí fl¡±Àfl¡ ¬ıÀ˘ ∑ 4+2 [·¬] ŒÎ¬Úø¸øÈ¬ Œ¢∂øÎ¬À˚˛KI◊ Œ¸øKCøÙ¬Î¬◊À·˙Úƒ ¬ÛXøÓ¬øÈ¬ ø‰¬S¸˝√√fl¡±À¬ı˛ ¬ı̫ڱ fl¡èÚ º Œ˚-Œfl¡±ÀÚ± ¤fl¡øÈ¬¬¬ õ∂Àùü¬ı˛ ά◊M√¬ı˛ ø√Ú – 6 × 1= 6 [fl¡√¬¬] ·Î¬ˇ ø¬ı‰≈¬…øÓ¬ fl¡±Àfl¡ ¬ıÀ˘ ∑ ¤¬ı˛ ’¸≈ø¬ıÒ± › ¸≈ø¬ıÒ±&ø˘ øfl¡ øfl¡ ∑ 2+4 [‡√] ¤fl¡øÈ¬ fl¡ø•Ûά◊Ȭ±À¬ı˛¬ı˛ õ∂À¸ø¸— ˝◊√ά◊øÚÀȬ¬ı˛ ø¬ıøˆ¬iß ’—À˙¬ı˛ Ú±˜ › Ó¬±À√¬ı˛ fl¡±Ê√ ¸—øé¬5ˆ¬±À¬ı ά◊À~‡ fl¡èÚ º 2+4 B.Sc-5656-Y [¬ÛÀ¬ı˛¬ı˛ ¬Û‘ᬱ˚˛ ^©Ü¬ı… EZO-IX (UT-192) 5º 6º 4 [·√] Œ˜±Àά˜ fl¡±Àfl¡ ¬ıÀ˘ ∑ ˝◊√KI◊±¬ı˛ÀÚÀȬ¬ı˛ ¬ı…¬ı˝√√±ø¬ı˛fl¡ ¸≈ø¬ıÒ±&ø˘ ’±À˘±‰¬Ú± fl¡èÚ º 2+4 ø¬ıˆ¬±· - · Œ˚-Œfl¡±ÀÚ± øÓ¬ÚøÈ¬ õ∂Àùü¬ı˛ ά◊M√¬ı˛ ø√Ú – 3 × 3= 9 [fl¡√¬] ’±À˘±fl¡ ’Ì≈¬ıœé¬Ì ˚La › ¬∏C±kø˜˙Ú ˝◊√À˘"™√Ú ’Ì≈¬ıœé¬Ì ˚ÀLa ¬ı…¬ı˝√√+Ó¬ Œ˘Àk¬ı˛ ∆¬ıø˙©Ü… › ¬Û±Ô«fl¡… ά◊À~‡ fl¡èÚº [‡] ά±˝◊√ÀSê±ø˚˛fl¡ √¬Û«Ì øfl¡ ∑ ¤øÈ¬ Œfl¡±Ô±˚˛ ¬ı…¬ı˝√√+Ó¬ ˝√√˚˛ ∑ 2+1 [·] ¤Ú.¤˜.’±¬ı˛. Œ¶Ûfl¡À¬∏C±À¶®±ø¬Û ¸•ÛÀfl«¡ ¸—øé¬5 Ȭœfl¡± ø˘‡≈Ú º [‚] ŒÓ¬Ê√ø¶ç¡˚˛Ó¬± øfl¡ ∑ Ê√œ¬ıø¬ı:±ÀÚ øfl¡ˆ¬±À¬ı ¤Àfl¡ õ∂À˚˛±· fl¡¬ı˛± ˝√√˚˛ ∑ 1+2 [„√√] ¤¸ƒ. øÎ¬. ¤¸.-¬Ûø˘’…±Sê±˘±˜±˝◊√ά ŒÊ√˘ ˝◊√À˘fl¡À¬∏C±ÀÙ¬±À¬ı˛ø¸¸ƒ ‰¬±˘Ú±¬ı˛ ¬Û”À¬ı« Œõ∂±øÈ¬Ú ^¬ıÌÀfl¡ øfl¡ˆ¬±À¬ı õ∂dÓ¬ fl¡¬ı˛± ˝√√˚˛ ¤¬ı— Œfl¡Ú Ó¬± fl¡¬ı˛± ˝√√˚˛ ¬ı…±‡…± fl¡èÚ º [‰¬] ŒÊ√˘ øÙ¬˘À¬∏C˙Ú ¬ÛXøÓ¬øÈ¬ ø‰¬S¸˝√√ ¬ı̫ڱ fl¡èÚ º Œ˚-Œfl¡±ÀÚ± øÓ¬ÚøÈ¬ õ∂Àùü¬ı˛ ά◊M√¬ı˛ ø√Ú – 3 × 3= 9 [fl¡√¬] ¬Ûø¬ı˛¸—‡…±ÀÚ Ú˜≈Ú± ¬ı˘ÀÓ¬ øfl¡ Œ¬ı±Á¡±˚˛ ∑ ’±√˙« Ú˜≈Ú± øÚ¬ı«±‰¬ÀÚ¬ı˛ øfl¡Â≈√ ά◊√±˝√√¬ı˛Ì ø√Ú º 1+2 [‡] ø¬ıô¶‘øÓ¬ fl¡±Àfl¡ ¬ıÀ˘ ∑ ø¬ıô¶‘øÓ¬¬ı˛ ’±À¬Ûøé¬fl¡ ¬Ûø¬ı˛˜±¬Ûfl-¡ &ø˘¬ı˛ Ú±˜ ά◊À~‡ fl¡èÚ º 1+2 [·√¬] ˜Ò…˜±ÀÚ¬ı˛ ¬ı…¬ı˝√√±À¬ı˛¬ı˛ ≈√øÈ¬ ¸≈ø¬ıÒ± › ¤fl¡øÈ¬ ’¸≈ø¬ıÒ±¬ı˛ ά◊À~‡ fl¡èÚ º 2+1 [‚] fl¡ø•Ûά◊Ȭ±À¬ı˛¬ı˛ ’ø'˘±¬ı˛œ Œ˜À˜±¬ı˛œ ¬ı˘ÀÓ¬ øfl¡ Œ¬ı±Á¡±˚˛ ∑ ¤fl¡ ø··±¬ı±˝◊√Ȭ fl¡Ó¬ øfl¡À˘±¬ı±˝◊√ÀȬ¬ı˛ ¸˜±Ú ∑ 2+1 [„√√¡√¬] ¬Û±˝◊√ø‰¬S ¬ı…¬ı˝√√±À¬ı˛¬ı˛ ≈√øÈ¬ ¸≈ø¬ıÒ± › ¤fl¡øÈ¬ ¬ı…¬ı˝√√±ø¬ı˛fl¡ õ∂À˚˛±· ά◊À~‡ fl¡èÚ º 2+1 B.Sc-5656-Y EZO-IX (UT-192) EZO-IX (UT-192) ( English Version ) (c) Group-A 1. 2. Answer one question. 10 × 1 = 10 (a) What is phase-contrast microscope ? What is its basic principle ? Describe the operation process of phase-contrast microscope with diagram. 2+2+6 (b) What is chromatogram ? In which type of chromatography is it utilized ? Describe with diagram, the separation process of bio-molecules by chromatography. 2+1+7 (c) Mention the name of different parts of scanning electron microscope and state their functions with proper diagram. How is the specimen for this microscope dried ? After drying, which metal-coats are given on specimen ? 7+2+1 Answer one question : (a) (b) 10 × 1 = 10 What is meant by frequency distribution ? Explain different characteristics of frequency distribution with examples. State two advantages and two disadvantages of frequency distribution. 1+6+3 The body weight of 16 persons are given below. Calculate their mean body weight and standard deviation : 52, 65, 55, 60, 62, 58, 57, 61, 59, 60, 61, 62, 67, 48, 54 and 63. 2+8 B.Sc-5656-Y [ ¬ÛÀ¬ı˛¬ı˛ ¬Û‘ᬱ˚˛ ^©Ü¬ı… 2 What is histogram ? Mention its merits and demerits. The number and length of catla fish present in a pond are given below. Draw a histogram with the data : Length of Catla fish ( class-interval) Number of fish ( Class-frequency ) 3·5 – 6·5 Inches 15 6·5 – 9·5 Inches 23 9·5 – 12·5 Inches 28 12·5 – 15·5 Inches 10 15·5 –18·5 Inches 35 2+3+5 Group-B 3. Answer one question. (a) 6×1=6 Explain the resolving power of light microscope. How can it be determined ? What is its relation with resolution ? (b) Explain limit of 2+3+1 the first law of thermodynamics. What in enthalpy ? 4+2 (c) Discuss the process of density gradient centrifugation with diagram. B.Sc-5656-Y 3 4. EZO-IX (UT-192) Answer one question. (a) Define mean 6×1=6 deviation. Write advantages and disadvantages. (b) (f) its 2+4 unit of computer mention their functions in brief. 6. Answer three questions. and (a) 2+4 3×3=9 Mention the characteristics and differences of the lens used in light microscope and that used in transmission electron microscope. mean by sample in sampling. (b) (c) 1+2 Define dispersion. Mention the names (c) Add a short spectroscopy. note on N.M.R (d) What is radioactivity ? How is it applied in life science ? 1+2 (e) Explain why and how the protein solution is prepared before passing through SDS-polyacrylamide gel electrophoresis. [¬ÛÀ¬ı˛¬ı˛ ¬Û‘ᬱ˚˛ ^©Ü¬ı… State two advantages and one disadvantage of the use of median. 2+1 (d) What is meant by auxiliary memory of computer ? How many kilobytes are What is dichroic mirror ? Where is it used ? 2+1 B.Sc-5656-Y What do you of relative measures of dispersion. 1 + 2 Answer three questions. (b) 3×3=9 statistics ? Give few examples of proper 2+4 Group-C (a) Describe the process of gel filtration with the help of diagram. What is modem ? Discuss the facilities of internet-use. 5. 4 Write the name of different parts of the processing (c) EZO-IX (UT-192) equal to one gigabyte ? (e) 2+1 Write two advantages of pie-chart and also mention one of its practical use. 2+1 B.Sc-5656-Y
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