Engineering Jump Start - Summer 2012 β Mathematics Worksheet #3 Factoring Polynomials Concepts: A linear combination of quantities is a sum of arbitrary multiples of these quantities. For example, one linear combination of A, B, C and D is 2π΄ + 3π΅ β 5πΆ + 4π·. A polynomial in x is a linear combination of non-negative integer powers of x. For example, π(π₯) = β2π₯ 5 + 3π₯ 3 + 2π₯ + 1 is a polynomial in x. The numbers in front of the powers of x are also known as the coefficients. A real polynomial is a polynomial that has only real coefficients. Check point: Is 3π₯ 5 + π₯ 3 + π₯ + π₯ β1 a polynomial? Why or why not? 1 Is βπ₯ 3 + 2π₯ + π₯ 2 a polynomial? Why or why not? An important problems associated with polynomials is factoring. One reason why factoring is important is that we know that a product is zero precisely when one or more of its factors are zero. Thus, having a factorization allows us to find the zeros of a polynomial. Another important application of factoring in calculus is to be able to find the so-called partial fraction decomposition. How to factor polynomials If you know that a polynomial is divisible by a linear factor, then you can apply synthetic division. But how do you come up with linear factors that divide the polynomial in the first place? Letβs consider the example of the polynomial π₯ 3 + 1. Itβs possible to know instantly, without attempting trial-and-error factorizations that π₯ + 1 must be a linear factor of that polynomial, in other words, that π₯ 3 + 1 can be written as (π₯ + 1) times another polynomial. Why? Try to recall the βfactor theoremβ from precalculus. Student Exercises: 1. Explain why π₯ 3 + 1 must be divisible by π₯ + 1 without performing long or synthetic division. Engineering Jump Start - Summer 2012 β Mathematics Worksheet #3 2. Use synthetic division to factor π₯ 3 + 1 into (π₯ + 1) times a quadratic polynomial. 3. This quadratic polynomial does not have real zeros. Complete the square to demonstrate that, and then use that to find the complex zeros. (A real polynomial without real zeros is called irreducible). 4. State the theorem you learned in precalculus about the imaginary zeros of real polynomials. 5. Using the factor theorem, factor the quadratic polynomial you found in 2. into a product of linear factors. In the previous exercise, we factored a cubic polynomial with real coefficients into both a real linear factor times an irreducible quadratic, and a product of linear factors, some of them with imaginary numbers. The fundamental theorem of algebra guarantees that that is always possible: Fundamental theorem of algebra: any polynomial π(π₯) of degree n with complex coefficients and leading coefficient ππ can always be written as π(π₯) = ππ (π₯ β π1 )(π₯ β π2 ) β¦ (π₯ β ππ ) where π1, π2 β¦ ππ are complex numbers. Student Exercises: 1. Demonstrate that if π1 = π + ππ and π2 = π β ππ, with real numbers a,b and b not zero, then (π₯ β π1 )(π₯ β π2 ) is a real and irreducible quadratic. 2. The fundamental theorem only guarantees that polynomials can be completely factorized into the leading coefficient times a product of linear factors. Why is it, then, that real polynomials can be factored completely into real linear factors and irreducible quadratics? 3. Factor the following polynomials completely into linear factors and irreducible quadratics: Engineering Jump Start - Summer 2012 β Mathematics Worksheet #3 a. π(π₯) = π₯ 4 β 1 b. π(π₯) = π₯ 6 β 1 c. π(π₯) = π₯ 5 β 5π₯ 3 + 4π₯ d. π(π₯) = π₯ 4 + 2π₯ 2 + 1 e. (harder) π(π₯) = π₯ 8 β 1
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