Energy Conversion Problems Part 1
v =d/t
KE = ½ mv2
GPE = mgh OR Fg h OR weight x height
GPE=KE therefore mgh=½ mv2
ME = KE + PE= ½ mv 2 + mgh
Wtotal =Fd = ∆KE=change in kinetic energy = KEf - KEi = ½ mvf 2 - ½
mvi 2
g= 9.8m/s2
Example: What is the potential energy of a 95 kg rock at the top of a
100m hill?
Given
Find?
Formula
Calculation
work
m=
PE?
PE= mgh
PE=
Answer with
unit
h=
1. What is the speed of a 0.145kg baseball if the kinetic energy is
109J?
2. A car has a kinetic energy of 4.32x105J when traveling at a speed
of 23m/s. What is its mass?
3. A 7.00kg ball moves at 3m/s. How much kinetic energy does the
ball have?