p. 598-599 # 14-34 EVEN ONLY
Solve each equation. Check your solutions.
14. (q + 4)(3q ! 15) = 0  {-4, 5}
5 7
16. (4a + 5)(3a ! 7) = 0  { ! , }
4 3
18. x 2 ! x ! 56 = 0  {-7, 8}
20. 5s ! 2 s 2 = 0  {0,
5
}
2
22. m 2 ! 24m = !144  {12}
24. 5b 3 + 34b 2 = 7b  {-7, 0,
26. t 2 !
1
}
5
t 35
7 5
=
 {! , }
6 6
3 2
28. ( x + 8)( x + 1) = !12  {-4, -5}
30. (3 y + 2)( y + 3) = y + 14  {-4,
2
}
3
32. Find two consecutive odd integers whose product is 1023.
x(x+2) = 1023
x2 + 2x – 1023 = 0
(x + 33)(x – 31) = 0
x = -33 OR x = 31
Therefore, two consecutive odd integers are x and x + 2  -33 and -31 OR 31 and 33
34. Write an equation with integral coefficients that has {-3, 0, 7} as its solution set.
There are many answers; one is: x3 – 4x2 – 21x = 0