Sctt-UTlot'l
GE 201STATICS
2nd Semester,1429-30
SecondMid-Term Exam
Time allowed:90 minutes
Maximum Marks: 40
Dateof Exam: 18-05-1430
Name (in Arabic):
StudentNo.:...
Section:
Q.No.
I
Max. Marks
l0
2
l0
a
J
10
4
10
TOTAL
40
Marks Obtained
Q.l
Determine the reactions at the supportsof a simply supportedbeam, shown in Fig. 1.
Assume the supportsat A and D as roller and pin supportsrespectively.
Da
Figure l.
3 D , Z( 7 = o
D*- 6c ut 6oo
=O
= 3 l < - ! . .f
" 'Dl
+{ 2 Fy = o
il
\/
b
g
rr0-s:-6Sin63=o
= t0.)- Fru
' b*td
'r1 +sY 6 + ( 6G n6; ) t 3: o
>MD= o
otr
= 5'l
od=
o")
-{il
S 'l
Dy = f'o
Exl
L\,
tzAl
Q.2(a) The 50-kg homogeneoussmooth sphererests on the 300 incline A and bears against
the smooth vertical wall B (Fig. 2). Calculatethe contact forces at A and B.
For <qpi' tf bti tlt/\/,,i -l\'te-t
-+-U=
n' V
1 fr^l,
ea$/4- lnf'
#,' ot'^'*J
lt..
$^I
J
-b
'r'r\u*'L-
o2SQ
V
Fu - o
6 sir,tgB i' trh=2Q
-0 )
Z Fl=o
+tzF s =u
=O
I crn3oo- 5o ] 1'gt
- FA= 5,66.h
f r^r.,t))
Fu,
N
'* l,
Figure2.
<i_t
= > g 2.2 N
Q.2(b)Determinethe force P requiredto maintainthe 200 kg block in the position(Fig. 3)
The diameterof the pulley at B is negligible.
Ll
-J ---
t
?-€tltz"o
t-
n
( 2 - 2 fi ?o
I
,P
^
(g* l,'
--ts,^3 t
L P -'so
c(.: lgd- (2.'t9f
o
= 6o
200kg
Yf
Figure3.
> aoY l , < , 1
$ zft = o
-T . f rn 6 o o tPsi n r !o:o
: T= P#"
=0 .3 P
al
'rt -zF,
rl -u
o'g?Qn68+Pcrttf-- 2-oo\,'el
=
T e{r61.+ ?6,,.- zaot,?,gr o 6(
-: ?=
:
" 4r TC?,'fgl = l
6
d
+
C
{
'
(
r
S
)
e. Z
E N s1 ' zN
Identify zeroforcemembersin a trussshownin Fig. 4.
Q.3(a)
E(
,nt
F-
lo kN
qn --l-
+n
4 m_
Si ng z Sfs =o.6
trr(D = VfS'=o,9
Figure4.
calculatethe forces.inthe membersAF andAB of the truss,shownin Fig. 4,
using Method of Joints. Assumethe supportsat A and D as roller and pin
supportsrespectively.
Q.3(b)
R-oaqA,fis:
z$-o:Ay +D1= to
QzMo=o
g!,B
)
Dx= 5 zM ('.' ZFr=oS
-fr xl> +foX€+s)? =o .
F*r'
-n
nl z3 =o
+>F* =o
*q"
= ? ' ? > f\h YOD> = 2' ogKt.l
v
5
F o p gn9t?g>
6,r t m }
=-tg'>(^
:Yk-.= - v . 9 > = -re
o.C
#
=o
+ F*:o
-t?. >tr o'9
+ tr613-o
56 I
- Fxg- F'
7.?-
Q. 3(c)
Calculatethe forcesin the membersBE, BC andFE of the sametruss,shown
in Fig. 4, usingMethodof Sections.
7v-rn
"'FaE
g
Frzc;
Q =M€ =o
*t
*f
tr=
vE
s,u7 kN (tl
?.7_?rcNcT)
'Bc
rF€ = - lo. s? tsN
cc)
t-:
tto*Q:o
Fu"*3 - *'72**
, Fo,c= 7.7q yxl
z Q=,
'
2Fr-o
J
Fu*^$
+ FFe * F*" --t
=o
7 . 1 > + % e g i' 4 8 - lo
+ ' 1 >+ f r e v ' 0 ^ 6- t o : o
:- Fee =9-\J kN
S,,.bsht'll ; t7.tit
r,u{Aorl{.,
3 . u V x o .€ + fa + 7 .2 i:o
e
' fre - -to,Sf ts\J
-'ti)
Q. 4(a)
!- Z A-o
n | ,,
=o
@ZNe'o
Calculatethe reactionsat the supportsA andE,shownin Fig. 5. The supportI
is a roller supportandE is a pin support.
€ . r 't7 'g
=o
r y t!=o
-lo
-qi)
Y7
A ,X g
Aqa t
l0'6
E ^t t
Q.4 (b)
_-____-___Eigure 5.
= I?,9krt|_ _
Ian
|
-o '6 3
*tY'!YJso
3 ri-N
kN
Calculatethe horizontaland vertical componentsof forceson memberCDE
andpin B, shownin Fig. 5.
jm
D * t9+l]'3x(=o
QZt l " =o
Dtr =
-JY'3!-6.= -ltl'(
tzr't
Dl. -- -3q' 6 Et'l
+
'ts
2F7 =o
* J",."
b,.
,." Jf t7.\
*.,,to'
D*
(n z t4s=o
- t o x g , s-
*T 5r J = o
-Y
Dv
> , x / , s= o
BJ = -CDt+t)
-DJ -tts= o
.bv
= -2 3 ' ! k N
= - C - z? ' z + t E = l3 ' 3 l' N
bJ = l3'3 kNr
1",
c.'-->
CV
2(*=o
B r*
C7 = o
B r, = -Cr" :
z!=o
l? , 9 * L Y
+'to -6 g
+rat-
i-+ '?'e
Vi,,
,+*1,.n,
*to'6e=o
-v t O ' 6 e
=o
tg
l l -'
or* Pi- B
fzs')e
b) *9
t7'9 kNl
-----------*=-
B = G T W ; : J r? .e > + ' 3 ' e -
,ffi,
=
zl'82
Ll'-I