powerpoints

GRAPHING TRIG FUNCTIONS
WARM-UP: SKETCH
f x = sin π‘₯
ο‚’Find the following points:
ο‚’All x where sin(x) = 0
ο‚’All x where sin(x) = ±1
ο‚’All x where sin(x) = ±1/2
ο‚’
SKETCHING COSECANT
ο‚’ Start
by sketching y= sin(x)
1
ο‚’ Remember csc x =
, which
sin(π‘₯)
allows you to plot key points:
ο‚’ There will be a vertical asymptote
whenever sin(x) = 0 (occurs at x=nΟ€)
ο‚’ When sin(x) = ±1, csc (x) = ±1 (occurs
πœ‹
at x = + 𝑛π)
2
ο‚’ When sin (x) = ±½ , csc(x) = ±2
π‘›πœ‹
(occurs at x= , for odd values of n)
4
CSC(X)
ο‚’ Domain:
all real numbers such that
x≠nπ
ο‚’ Range: (-∞, -1] U [1, ∞)
ο‚’ Symmetry: origin
ο‚’ Vertical Asymptotes: x=nΟ€
SKETCH
ο‚’
𝑓 x = 4csc 2π‘₯ +
πœ‹
3
βˆ’5
SKETCHING
SECANT
ο‚’ Start
by sketching y= cos(x)
1
ο‚’ Remember sec x =
, which allows
cos(π‘₯)
you to plot key points:
ο‚’ There will be a vertical asymptote
Ο€
whenever cos(x) = 0 (occurs at x = + 𝑛π)
2
ο‚’ When
cos(x) = ±1, sec (x) = ±1 (occurs at
x =nΟ€)
ο‚’ When cos (x) = ±½ , sec(x) = ±2 (occurs at
πœ‹
πœ‹
x= + 𝑛 )
4
2
SEC(X)
ο‚’ Domain:
πœ‹
all real numbers such that
xβ‰  + 𝑛π
2
ο‚’ Range: (-∞, -1] U [1, ∞)
ο‚’ Symmetry: y-axis
πœ‹
ο‚’ Vertical Asymptotes: x = + 𝑛π
2
SKETCH
ο‚’
f x = βˆ’3sec
1
π‘₯
2
+
πœ‹
3
ο‚’Hint:
+1
Start by sketching
1
πœ‹
𝑔(π‘₯) = βˆ’3cos π‘₯ + + 1
2
3
SKETCHING TANGENT AND COTANGENT
f(x) = tan (x)
ο‚’ Period: Ο€
πœ‹
ο‚’ Domain: all x β‰  + π‘›πœ‹
ο‚’
ο‚’ Range
2
(-∞,∞)
πœ‹
ο‚’ Vertical asymptotes: x = + π‘›πœ‹
2
SKETCHING TANGENT AND COTANGENT
Sketch y = atan(bx βˆ’ 𝑐) +d
ο‚’ First, draw a line at y=d (this is your new midline)
ο‚’ Then, find and sketch the vertical asymptotes:
βˆ’πœ‹
ο‚’ Left asymptote will be at 𝑏π‘₯ βˆ’ 𝑐 =
ο‚’
2
πœ‹
=
2
Right asymptote will be at 𝑏π‘₯ βˆ’ 𝑐
ο‚’ The midpoint between the two asymptotes will be
the x-intercept. Plot a point. (On the midline)
ο‚’ At the midpoint between the left asymptote and
the x-intercept, go down a units and plot a point
(reverse if a is negative)
ο‚’ At the midpoint between the x-intercept and the
right asymptote, go up a units and plot a point
(reverse if a is negative)
ο‚’ Finish sketching the function, and add another
period.
ο‚’
SKETCHING TANGENT AND COTANGENT
Sketch y = -3tan(2x)+4
ο‚’ Sketch a line at y=4 (this is the new
midline)
πœ‹
ο‚’ Left asymptote at 2x=βˆ’
2
πœ‹
ο‚’ Right asymptote at 2x=
2
ο‚’ The midpoint between the two
asymptotes plot the x-intercept
ο‚’ At the midpoint between the L.A. and
the x-intercept, go up 3 (because -3)
ο‚’ At the midpoint between the x-intercept
and the R.A., go down 3 (because -3)
ο‚’ Finish the sketch and add a second
period
ο‚’
SKETCHING TANGENT AND COTANGENT
f(x) = cot (x)
ο‚’Period: Ο€
ο‚’Domain: all x β‰  π‘›πœ‹
ο‚’Range (-∞,∞)
ο‚’Vertical asymptotes: x = π‘›πœ‹
ο‚’
SKETCHING COTANGENT - GENERAL
Sketch y = acot(bx βˆ’ c)+d
ο‚’ First, draw a line at y=d (this is your new midline)
ο‚’ Then, find the asymptotes:
ο‚’ Left asymptote will be at 𝑏π‘₯ βˆ’ 𝑐 = 0
ο‚’ Right asymptote will be at 𝑏π‘₯ βˆ’ 𝑐 = Ο€
ο‚’ The midpoint between the two asymptotes will be
the x-intercept. Plot a point. (should be on the new
midline)
ο‚’ At the midpoint between the left asymptote and
the x-intercept, go up a units (from the midline)
and plot a point (reverse if a is negative)
ο‚’ At the midpoint between the x-intercept and the
right asymptote, go down a units (from the
midline) and plot a point (reverse if a is negative)
ο‚’
SKETCHING TANGENT AND COTANGENT
π‘₯
-4cot( )+1
3
Sketch y =
ο‚’ Draw the new midline (y=a)
ο‚’ Sketch the left asymptote
ο‚’ Sketch the right asymptote
ο‚’ At the midpoint between the two asymptotes
plot the x-intercept
ο‚’ At the midpoint between the L.A. and the xintercept go down 4 units and plot a point
(because -4)
ο‚’ At the midpoint between the x-intercept and
the R.A. go up 4 units and plot a point
(because -4)
ο‚’ Sketch in the graph and include another
period.
ο‚’