“Answer on Question #63583, Chemistry / General Chemistry”
1. What is the concentration of a solution made 130 grams of Сu3(PO4)2 in 3.9 L of
water?
2. What is the concentration of Copper (II) ions in the above solution?
3. What is the concentration of Phosphate ions in the above solution?
1.
Сu3(PO4)2) =382 g/mol
2. Cu3(PO4)2 = 3Cu2+ + 2 PO43[Cu2+] = 3*0.087=0.261mol/L
3. Cu3(PO4)2 = 3Cu2+ + 2 PO43[PO43-] = 2*0.087=0.174mol/L
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