7
Practice in Multiplying Two Binomials
Set # 534
#1. If each of a, b, and c is a number such that for each number x, f(x) = ax2 + bx + s, and for
each number x, f(x) = (x - 2Xx - 3), then bz - 4ac =
*
c, and for
+ bx
*
9, and for
#4. If each of 4 b, and c is a number such that for each number x, f(x) = ax2 + bx
each number x, f(x) = (x * lXx - l), then b2 - 4ac:
r
c, and for
#2. If each of a, b, and c is a number such that for each number x, f(x) = ax2 + bx
each number x, f(x) = (x * 4Xx - 5), then b2 - 4ac =
#3. If each of a, b, and c is a number such that for each number x, f(x)
each number x, f(x) = (x * 5Xx - 8), then b2 - 4ap=
:
ax2
#5. If each of 4 b, and c is a number such that for each number x,
each number x, f(x) = (x * 2Xx - 11), then b2 - 4ac =
(x) = ax' + bx *
#6. If each of a, b, and c is a number such that for eachnumber x,
each number x, f(x) = (x - 4Xx - 8), then b2 - 4ac:
(x)
c, and
for
-_..-,
= ax2 + bx
* c, and for
:
ax2
*
:
ax2 + bx
...-.
#7.\f
eachof a, b, and c is a number such tlrat for each number x, f(x)
each number x, f(x) (x - l2)(x - 2), then b2 - 4ac:
:
+ bx
c, and for
--.----.
#8. If each of a, b, and c is a number such that for each number x, f(x)
each number x, f(x) = (x - 3Xx - 7), then b ? - 4ac =
#9. If each of a, b, and c is a number such that for each number x,
each number x, f(x) = (x - 8Xx - 9), then b2 - 4ac:
(x)
= ax2 + bx
* c, and for
*
c, and for
*
c, and
for
= ax2 + bx
*
c, and
for
:
axz + bx
*
c, and for
#13. If each of a, b, and c is a number such that for each number x, f(x) = ax2 + bx
each number x, f(x): (5x + 4)(8x - 5), then b2 - 4ac:
*
c, and for
r
c, and
#10. If each of a, b, and c is a number such that for each number x, f(x) = ax? + bx
each number x, (x) = (2x + 4)(x - 5), then bz - 4ac =
#11. If each of 4 b, and c is a number such that for each number x,
each number x, f(x) = (x * a)(3x - 5), then b2 - 4ac =
#12.If
(x)
of a, b, and c is a number such that for each number x, f(x)
each number x, f(x) = (3x + 4)(2x - 5), then b2 - 4ac =
each
-*--__-.
#14. If each of a, b, and c is a number such that for each number x, f(x) =
(7x + 4)(4x - 5), then b2 - 4ac:
each number x, f(x)
:
-.
(end of document)
a*
+ bx
for