11.1 Notes and Theorems ? 11.2 Quiz 11.1 1. Find the value of x. o 115 o 96 64o x o 2. The measure of each interior angle of a regular polygon is o 144 . How many sides does the polygon have? 3. Find the value of x. o 76 o 52 x o 11.2 Notes and Theorems Geometric Shapes Circumscribed Circle Inscribed Polygon Inscribed Circle Circumscribed Polygon S A B T 11.2 Notes and Theorems Find the area of an equilateral triangle with 4 foot sides. Solution: Use s = 4 in the Equilateral Δ Area Theorem. A = ¼√3 s2 = ¼√3 (42) = ¼√3 (16) = ¼ (16) √3 = 4√3 11.2 Notes and Theorems A regular octagon is inscribed in a circle with radius 2 units. Find the area (A) of the octagon. B A D C Solution: Area of regular polygon 1) A = ½aP Find the measurements of ΔDBC. a) Find the measure of central ABC: 1 o o ABC = /8 · 360 = 45 b) Isosceles ΔABC, the altitude bisects base AC o DBC = 22.5 . c) Use trig ratios to find the legs: cos 22.5o = BD BC = BD 2 and sin 22.5o = DC = DC BC 2 11.2 Notes and Theorems A regular octagon is inscribed in a circle with radius 2 units. Find the area (A) of the octagon. B A D C Solution: Area of regular polygon A = ½aP 2) Determine the apothem (a): o a = BD = 2 cos 22.5 3) Find the Perimeter (P): · o o P = 8(AC) = 8(2 DC) = 8(2 2 sin 22.5 ) = 32 sin 22.5 The area of the octagon is A = ½aP o o A = ½(2 cos 22.5 )(32 sin 22.5 ) ≈ 11.3 square units 11.2 Notes and Theorems Find the perimeter (P) and area (A) of a regular hexagon with side length of 4 cm and radius 4 cm. S A B T Solution: 1) Find the perimeter: Hexagon = 6 sides with 4 cm length P = 6(4) = 24 cm. A = ½aP 2) Determine the apothem (a): consider Δ SBT. BT = ½(BA) = ½(4) = 2cm Use the Pythagorean Theorem to find the apothem ST. a = √42 - 22 = 2√3 cm. ∴ The area of the hexagon is A = ½aP A = ½(2√3)(24) = 24√3
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